PHYSICS MIDDLE SCHOOL

A 2.00x10^6 hertz radio signal is sent a distance of 7.30x10^10 meters from earth to a spaceship orbiting Mars. How much time does it take for the radio signal to travel from earth to the spaceship

Answers

Answer 1

Answer:

Answer:

It takes $2.43* 10^2$ for the radio signal to travel from earth to the spaceship.

Explanation:

Given:

The frequency of the radio signal = $2.00 * 10^6$ hertz

Distance = $7.30* 10^10$ meters

To Find:

The time taken for the radio signal to travel from the earth to the spaceship= ?

Solution:

we know that the time taken can be found by dividing the distance travelled by the speed at which the signal travels

$Time = (Distance)/(Speed)$

Here the speed of the radio signal is equal the the speed of light

Now substituting the values,

Time taken is

=> $Time = (7.30* 10^10)/(3 * 10^8)$

=> $Time = 2.43* 10^(10-8)$

=> $Time = 2.43* 10^2$

Answer 2

Answer:

The time taken for the 2×10⁶ Hz radio signal to get to the spaceship from Earth is 243.33 s

What is speed?

Speed is the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

How to determine the time

Speed of radio signal = 3×10⁸ m/s
Distance = 7.3×10¹⁰ m
Time =?

speed = distance / time

3×10⁸ = 7.3×10¹⁰ / time

Cross multiply

3×10⁸ × time = 7.3×10¹⁰

Divide both sides by 3×10⁸

Time = 7.3×10¹⁰ / 3×10⁸

Time = 243.33 s

Learn more about speed:

brainly.com/question/680492

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Figure 1.18 (Chapter 1) shows the Hoover Dam Bridge overthe Colorado River at a height of 271 m. If a heavy object is
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Answers

Answer: 7.436 s

Explanation:

This situation is related to vertical motion, specifically free fall and can be modelled by the following equation:

$y=y_(o)+V_(o) t+(gt^(2))/(2)$

Where:

$y= 0m$ is the final height of the object (when it makes splash)

$y_(o)=271 m$ is the initial height of the object

$V_(o)=0 m/s$ is the initial velocity of the object (it was dropped)

$g=-9.8m/s^(2)$ is the acceleration due gravity (directed downwards)

$t$ is the time since the objecct is dropped until it makes splash

$0=y_(o)+0+(gt^(2))/(2)$

Clearing $t$ :

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Answers

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Answers

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Answers

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Answers

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