What is the earliest version of the present day Internet?

To calculate percent of a total (i.e. calculate a percent distribution), you can use a formula that simply divides an amount by the total.

Note: you must format the result using the Percentage number format in Excel to see 25%, 10%, etc. 

 the reference to C11 is absolute (i.e. $C$11) so that it won't change when the formula is copied down the column.

As always in Excel, when you want to display a percentage, you need to use the Percentage number format, which will automatically display a decimal value as a percentage.

-dave bruns

Answer:

equations

this is the answer

Answer:too many words ahhh

Explanation:

(assuming jsx)

function Buttons (props) {

return(

{props.counterValue}

counter

increment

reset

);

}

var counterValue = 1;

function addup(a){

if(counterValue + a <= 20){

counterValue += a;

} else if (counterValue + a > 20){

//do nothing

}

ReactDOM.render(

 ,

 document.getElementById('root')

);

}

function reset() {

counterValue = 1;

ReactDOM.render(

 ,

 document.getElementById('root')

);

}

Answer:

See Explaination

Explanation:

#include <iostream>

#include <cmath>

using namespace std;

int main()

{

float input1, input2, input3;

float sum=0.0, avg, l;

cout<<"enter the value for input1: ";

cin>>input1;

cout<<"enter the value for input2: ";

cin>>input2;

cout<<"enter the value for input3: ";

cin>>input3;

sum=input1+input2+input3;

cout<<"sum of three numbers: "<<sum<<endl;

avg=sum/3;

cout<<"average of three numbers: "<<avg<<endl;

l=log2(input1);

cout<<"log2 value of input1 number: "<<l;

return 0;

}

output:

enter the value for input1: 4

enter the value for input2: 5

enter the value for input3: 6

sum of three numbers: 15

average of three numbers: 5

log2 value of input1 number: 2

Answer:

a.  cout<<hidden(15,10)<<endl;

output = 5

b. cout << compute(3, 9) << endl;

output=3

c. cout << hidden(30, 20) << " " << compute(10, hidden(30, 20)) << endl;

output = 10

d. x = 2; y = 8; cout << compute(y, x) << endl;

output= 8

Explanation:

solution a:

num1= 15;

num2= 10;

according to condition 1, num1 is not greater than 20. In condition 2, num2 is also not greater than 20.

so,

the solution is

return num1 - num2 = 15 - 10 = 5

So the output for the above function is 5.

solution b:

as in function there are two  integer type variables named as one and two. values of variables in given part are:

one = 3

two = 9

secret = one = 3

for (int i= one + 1 = 3+1 = 4; i<=9%2=1; i++ )

9%2 mean find the remainder for 9 dividing by 2 that is 1.

//  there 4 is not less than equal to  1 so loop condition will be false and loop will terminate. statement in loop will not be executed.

So the answer will be return from function compute is

return secret ;

secret = 3;

so answer return from the function is 3.

solution c:

As variables in first function are num1 and num2. the values given in part c are:

num1 = 30;

num2= 20;

According to first condition num1=30>20, So,

num1= num2/10

so the solution is

num1 = 20/10 = 2

now

num1=2

now the value return from function Hidden is,

return num1*num2 = 2* 20 = 40

Now use the value return from function hidden in function compute as

compute(10, hidden(30, 20))

as the value return from hidden(30, 20) = 40

so, compute function becomes

compute(10, 40)

Now variable in compute function are named as one and two, so the values are

one= 10;

two = 40;

as

secret = one

so

secret = 10;

for (int i= one + 1 = 10+1 = 11; i<=40%2=0; i++ )

40%2 mean find the remainder for 40 dividing by 2 that is 0.

//  there 11 is not less than equal to  0 so loop condition will be false and loop will terminate. statement in loop will not be executed.

So the answer will be return from function compute is

return secret ;

secret = 10;

so answer return from the function is 10.

solution d:

Now variable in compute function are named as one and two, so the values are

one = y = 8

two = x = 2

There

Secret = one = 8;

So

for (int i= one + 1 = 8+1 = 9; i<=2%2=0; i++ )

2%2 mean find the remainder for 2 dividing by 2 that is 0.

//  there 9 is not less than equal to  0 so loop condition will be false and loop will terminate. statement in loop will not be executed.

So the answer will be return from function compute is

return secret ;

secret = 8;

so answer return from the function is 8.

Answer:

The output is 20

Explanation:

This line divides the value of x by userVal

tmpVal = x / userVal;

i.e.

tmpVal = 100/5

tmpVal = 20

This line then prints the value of tmpVal

System.out.print(tmpVal);

i.e 20

Hence, The output is 20

Final answer:

The provided Java code checks if the variable userVal does not equal 0. As this is the case when userVal is 5, another variable tmpVal is assigned the value of another variable x (which is 100) divided by userVal. Hence, the output of the code would be 20.

Explanation:

In the given piece of code, the variable userVal is assigned a value of 5. The program also contains a variable x which is assigned a value of 100. An if statement checks whether userVal does not equal 0 - since 5 != 0, the condition is true. A new variable tmpVal is then declared and assigned the value of x divided by userVal, so tmpVal equals 100 / 5, which is 20. So, the output of this code when userVal is 5 would be 20.

Learn more about Java Programming here:

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