Ocean water is the coldest at ​

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Answer 1
Answer: The bottom of the ocean because it does not get sun light

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Ri1. Among these which is the example of compound?a) sulphurb) ironc) ammoniader​
The standard free energy change for a reaction in an electrolytic cell is always:_________ a. Positive b. Negative c. Zero d. Impossible to determine
The amount of gas that occupies 36.52 L at 68.0°C and 672 mm Hg is __________ mol.
Predict the sign of the entropy change,Delta S, for each of the following reactions:The signs are either going to be pos or negativea) Pb^2+(aq) + 2Cl-(aq) ---> PbCl2(s)b) CaCO3(s) ---> CaO(s) + CO2 (g)c) 2NH3(g) ---> N2(g) + 3H2(g)d) P4(g) + 5O2(g) ---> P4O10(s)e) C4H8(g) + 6O2(g) ---> 4CO2(g) + 4H2O(g)f) I2(s) ---> I2(g)

The ΔG°f of atomic oxygen is 230.1 kJ/mol. Find ΔG° for the following dissociation reactionO2 (g) <--> 2O (g)then calculate its equilibrium constant at 298 K.

Answers

Answer:

Kc = 2.145 × 10⁻⁸¹

Explanation:

Let's consider the following reaction:

O₂(g) ⇄ 2O(g)

The standard Gibbs free energy for the reaction (ΔG°) can be calculated using the following expression:

ΔG° = Σnp. ΔG°f(p) - Σnp. ΔG°f(p)

where,

ni are the moles of products and reactants

ΔG°f(p) are the standard Gibbs free energy of formation of products and reactants

In this case,

ΔG° = 2 × ΔG°f(O) - 1 × ΔG°f(O₂)

ΔG° = 2 × 230.1 kJ/mol - 1 × 0 kJ/mol

ΔG° = 460.2 kJ/mol

With this information, we can calculate the equilibrium constant (Kc) using the following expression:

Kc=e^(-\Delta G \°/R.T ) = e^{-460.2 kJ/mol/(8.314 * 10^(-3)kJ/mol.K)  * 298K }=2.145 * 10^(-81)

Determine the number of moles of oxygen atoms in each of the following.1) 4.93 mol H2O2
2) 2.01 mol N2O

Answers

Answer :

Part 1: 4.93 moles of H_2O_2 contains 9.86 moles of oxygen atoms.

Part 2: 2.01 moles of N_2O contains 2.01 moles of oxygen atoms.

Explanation :

Part 1: 4.93 mol H_2O_2

In 1 mole of H_2O_2, there are 2 atoms of hydrogen and 2 atoms of oxygen.

As, 1 mole of H_2O_2 contains 2 moles of oxygen atoms.

So, 4.93 moles of H_2O_2 contains 4.93* 2=9.86 moles of oxygen atoms.

Thus, 4.93 moles of H_2O_2 contains 9.86 moles of oxygen atoms.

Part 2: 2.01 mol N_2O

In 1 mole of N_2O, there are 2 atoms of nitrogen and 1 atom of oxygen.

As, 1 mole of N_2O contains 1 mole of oxygen atoms.

So, 2.01 moles of N_2O contains 2.01* 1=2.01 moles of oxygen atoms.

Thus, 2.01 moles of N_2O contains 2.01 moles of oxygen atoms.

Atmospheric pressure arises due to the force exerted by the air above the Earth. At higher altitudes, the mass of the air above the Earth is _____ than at sea level, and atmospheric pressure therefore _____ with altitude.

Answers

Answer:

less, decreases

Explanation:

When the pressure of an atmosphere occurs because of the force exerted so at the time of the higher altitudes, the air mass i.e. above the earth should be less as the air is attracted towards surface of an earth because of the gravity and air contains the mass that shows near the surface area so automatically the air density reduced due to which the mass also decreased

Complete and balance the equation for the following acid-base neutralization reaction. If water is used as a solvent, write the reactants and products as aqueous ions. In some cases, there may be more than one correct answer, depending on the amount of reactants used.(a)Mg(OH)2 + HClO4?
(b)SO3 + H2O? (Assume an excess of water and that the product dissolves)
(c) SrO + H2SO4?

Answers

Explanation:

A balanced equation is defined as the one that has equal number of atoms of all the elements present on both reactant and product side.

(a) Mg(OH)_(2) + HClO_(4) \rightarrow Mg(ClO_(4))_(2) + H_(2)O

Number of atoms on reactant side are as follows.

Mg = 1

O = 6

H = 3

Cl = 1

Number of atoms on product side are as follows.

Mg = 1

O = 9

H = 2

Cl = 2

So, to balance this equation we multiply Mg(OH)_(2) by 2 on reactant side and multiply H_(2)O by 2 on product side.

Therefore, the balanced reaction equation is as follows.

       2Mg(OH)_(2) + HClO_(4) \rightarrow Mg(ClO_(4))_(2) + 2H_(2)O  

(b)  SO_(3) + H_(2)O \rightarrow H_(2)SO_(4)

Number of atoms on reactant side are as follows.

S = 1

O = 4

H = 2

Number of atoms on product side are as follows.

S = 1

O = 4

H = 2

Therefore, this equation is balanced as it has same number of atoms on both reactant and product side.

(c)  SrO + H_(2)SO_(4) \rightarrow SrSO_(4) + H_(2)O

Number of atoms on  reactant side are as follows.

Sr = 1

O = 1

H = 2

S = 1

O = 4

Number of atoms on product side are as follows.

Sr = 1

O = 1

H = 2

S = 1

O = 4

Therefore, this equation is balanced.

Use the following structures of amino acids to answer the questions below. Note that the difference in the structures (the side chains) is highlighted by gray shading.


A student performed chromatography of the four amino acids and theresults were shown in the chromatogram below. If an anion exchangecolumn (column is positively charged) was used in a neutral buffer,assign each amino acid to the corresponding peak in the chromatogram.

Answers

In a positively charged column, Asparate will travel the farthest followed by Threonine, Leucine and Lysine.

State and explain grahms law of diffusion​

Answers

Answer:

Graham's law of effusion was formulated by Scottish physical chemist Thomas Graham in 1848. Graham found experimentally that the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles. This formula can be written as: , where: Rate₁ is the rate of effusion for the first gas.

Explanation:

r1 = rate of effusion for gas 1

r2 = rate of effusion for gas 2

M1 = molar mass of gas 1

M2 = molar mass of gas 2