C6H6NCl On the basis of the molecular formula, 1H NMR data, and IR data provided, propose a consistent structure.H`NMR data: δ 300 (s, 2H), 6.57 (d, 2H), 7.05 (d, 2H)
IR data: 3400 (broad), 3250 (broad), 1590, 820 cm^(-1).

Draw your proposed structure below.

Answers

Answer 1
Answer:

Answer:

Please refer to the attachment below.

Explanation:

Please refer to the attachment below for explanation.


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On another planet, the isotopes of titanium have the following natural abundances. a. Isotope 46Ti Abundance 70.900% Mass(amu) 45.95263 b. Isotope 48Ti Abundance 10.000% Mass(amu) 47.94795 c. Isotope 50Ti Abundance 19.100% Mass(amu) 49.94479 d. What is the average atomic mass of titanium on that planet? e. I got 46.9 amu but it is wrong.

Please ignore my answers because they are wrong.

Answers

Answer:

The wavelength of the radio wave is 3.003 m.

The energy of the radio wave is 6.6194* 10^(-26) J.

Explanation:

Frequency of the radio waves, ν = 99.9 MHz = 99.9* 10^6 Hz

Wavelength and frequency are related to each other by realtion:

\lambda =(c)/(\nu )

\lambda = Wavelength of the wave

c = speed of the light

ν = Frequency of the wave

\lambda =(3* 10^8 m/s)/(99.9* 10^6 s^(-1))=3.003 m

The wavelength of the radio wave is 3.003 m.

The energy of the electromagnetic wave is given by Planck's equation:

E=h* \nu

h = Planck's constant = 6.626* 10^(-34) Js

The energy of the radio wave with 99.9 MHz frequency will be:

E=6.626* 10^(-34) Js* 99.9* 10^6 s^(-1)

E = 6.6194* 10^(-26) J

The energy of the radio wave is 6.6194* 10^(-26) J.

At a winter carnival, a balloon is filled with 5.00 L of helium at a temperature of 1.0°C. What will be the volume of the balloon when it is brought into a warm house at 24°C?

Answers

Answer:

The volume of balloon is 5.41 L.

Explanation:

The volume of helium (V1) = 5 L

Temperature (T1) = 1 degree Celsius

Now covert the temperature into kelvin by simply adding the 273 with given temperature. Thus, 1-degree Celsius = 274 kelvin.

The volume of balloon (V2) =?

Temperature (T2) = 24 degree Celsius

Now covert degree Celsius into kelvin. Thus, 24-degree Celsius = 297 kelvin.

Using Charl’s law.

(V1)/(T1) = (V2)/(T2) \n

(5)/(274) = (V2)/(297) \n

V2 = 5.41 \ L

A 0.2264 g sample of a pure carbonate, XnCO3(s) , was dissolved in 50.0 mL of 0.1800 M HCl(aq) . The excess HCl(aq) was back titrated with 24.90 mL of 0.0980 M NaOH(aq) . How many moles of HCl react with the carbonate

Answers

Answer:

6.56x10⁻³ mol

Explanation:

First we calculate how many HCl moles are there in 50.0 mL of a 0.1800 M solution:

  • 0.1800 M * 50.0 mL = 9.00 mmol HCl

Then we need to calculate how many HCl moles were in excess, that number is the same as the number of NaOH moles they reacted with:

  • 0.0980 M * 24.90 mL = 2.44 mmol NaOH = 2.44 mmol HCl

Finally we calculate the difference between the original number of HCl moles and the number remaining after the reaction with XnCO₃:

  • 9.00 mmol - 2.44 mmol = 6.56 mmol
  • 6.56 mmol / 1000 = 6.56x10⁻³ mol

Final answer:

The amount of HCl that reacted with the carbonate is found by subtracting the amount of HCl neutralized by NaOH from the total initial amount of HCl, resulting in 0.00656 moles of HCl reacting with carbonate.

Explanation:

In this problem, we first need to calculate the total amount of HCl initially used. This is done using the formulaMolarity (M) = moles of solute/Liters of solution. We can calculate moles of HCl as (0.1800 moles/L) * (0.0500 L) = 0.00900 moles.

Next, the HCl reacts with the carbonate, but there is excess that needed to be neutralized using NaOH. The amount of HCl neutralized by NaOH can be calculated similarly as (0.0980 moles/L) * (0.0249 L) = 0.00244 moles.

Thus, the amount of HCl that reacted with the carbonate is the initial moles of HCl minus the moles of HCl neutralized by NaOH. This yields 0.00900 moles - 0.00244 moles = 0.00656 moles of HCl reacted with the carbonate.

Learn more about Acid-base titration here:

brainly.com/question/34855887

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Which letter indicates the asthenosphere

Answers

Answer:

q

Explanation:

1. The atomic number of an element isdetermined by the number of:
a. protons.
b. electrons.
C. neutrons.
d. isotopes.

Answers

The answer is: A, protons

Answer:

Atomic number is protons

Explanation:

Protons = positive charge

When the following redox equation is balanced with smallest whole number coefficients, the coefficient for Sn(OH)3– will be _____. Bi(OH)3(s) + Sn(OH)3–(aq) → Sn(OH)62–(aq) + Bi(s) (basic solution)

Answers

Answer:

The coefficient of Sn(OH)_3^(-) is 3 in the balanced redox reaction.

Explanation:

Oxidation reaction is defined as the chemical reaction in which an atom loses its electrons. The oxidation number of the atom gets increased during this reaction.

X\rightarrow X^(n+)+ne^-

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

X^(n+)+ne^-\rightarrow X

For the given chemical reaction:

Bi(OH)_3+Sn(OH)_3^(-)\rightarrow Sn(OH)6^(2-)+Bi

The half cell reactions for the above reaction follows:

Oxidation half reaction:  Sn(OH)_3^(-)+3OH^-\rightarrow Sn(OH)6^(2-)+2e^-

Reduction half reaction:  Bi(OH)_3+3e^-\rightarrow Bi+3OH^-

To balance the oxidation half reaction must be multiplied by 3 and reduction half reaction must be multiplied by 2 thus, the balanced equation is:-

3Sn(OH)_3^(-)+3OH^-+2Bi(OH)_3\rightarrow 3Sn(OH)6^(2-)+2Bi

The coefficient of Sn(OH)_3^(-) is 3 in the balanced redox reaction.