Answers
Answer: C2H4S5
Explanation:
Since the total mass is 5.000g
Mass of sulphur = 5.000-(0.6357+0.1070)
Mass of sulphur = 4.2573g
Using Empirical relation
C= 0.6357 H= 0.1070 S= 4.2573
Divide through by their molar mass to obtain the smallest ratio
C= 0.6357/12 H=0.1070/1 S=4.2573/32
C= 0.053 H= 0.1070 S= 0.133
Divide through by the smallest ratio (0.053)
C=0.053/0.053 H=0.1070/0.053 S=0.133/0.053
C=1 H=2 S=2.5
1:2:2.5 ,multiply through by 2 ,to obtain whole numbera
2:4:5
Therefore the empirical formula is C2H4S5. Thus only gives the ratio
Molecular formula is the chemical formula .
(Empirical formula) n = molecular formula
(C2H4S5)n = molar mass
[(12×2) + ( 1×4) +(32×5)]n = 188.4
188n=188.4
n= 1
Molecular formula = (C2H4S5)×1
Therefore the chemical formula of
lenthionine is C2H4S5
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Answers
The vapor pressure of the solution would be as follows:
torr
Given that,
Vapor pressure of Carbon Disulfide torr
Naphthalene's mass
Naphthalene's molar mass
Now,
We know that
Number of moles
Mass ×
×
So,
Number of moles of Carbon Disulfide ×
moles of Carbon Disulfide
Number of moles of Naphthalene:
Number of moles
Now,
Total number of moles :
moles
Mole fraction of each compound in solution :
Carbon Disulfide:
2.567 / 2.65
Naphthalene
0.083 / 2.65
According to Raoult's:
P ×
Carbon Sulfide = Solvent
Mole fraction of solvent
Vapour pressure of the pure solvent
×
torr
Thus, " torr" is the correct answer.
Learn more about "Pressure" here:
Answer:
344.5764 torr
Explanation:
Molar mass of naphthalene = 128.2g/mol
Mass of naphthalene = 10.60 g
Carbon disulfide:
Molar mass= 76.14g/mol ;
volume = 155mL ;
density = 1.261 g/mL
Vapour pressure = 355.6 torr
Number of moles = mass / molar mass
CS2:
Mass = density × volume
Number of moles = (density × volume) / molar mass
Number of moles = (1.261 * 155) / 76.14 = (195.455 / 76.14) = 2.567 moles of CS2
Number of moles of C8H10:
Number of moles = 10.60 / 128.2 = 0.083 C8H10
Total number of moles :
2.567 + 0.083 = 2.65 moles
Mole fraction of each compound in solution :
CS2 :
2.567 / 2.65 = 0.969
C8H10:
0.083 / 2.65 = 0.031
According to Raoult's:
Psolution = Xsolvent × Posolvent
CS2 = solvent
Xsolvent = Mole fraction of solvent
Posolvent = Vapour pressure of pure solvent
Psolution = 0.969 × 355.6 torr = 344.5764 torr
Answers
a.carbon?
Answers
Answers
Answer:
124 g (3 sig figs)
or
124.011 g (6 sig figs
Explanation:
Step 1: Calculate g/mol for AgNO₃
Ag - 107.868 g/mol
N - 14.01 g/mol
O - 16.00 g/mol
107.868 + 14.01 + 16.00(3) = 169.878 g/mol
Step 2: Multiply 0.73 moles by molar mass
0.73 mol (169.979 g/mol)
124 grams of AgNO₃
b. mmol NaOH Initial concentration of NaOH
c. mL H2O Initial concentration of HCl
Answers
Answer:
The following parameters:
- total mL solution
- mmol NaOH
- initial concentration of NaOH
Explanation:
The options have been incorrectly arranged in the question statement given here. The three conditions mentioned above are what would be observed to remain the same when this experiment is carried out.
Answers
Answer:
30.1 g NaCl
Explanation:
Your first conversion is converting grams NaOH to moles of NaOH using its molar mass (39.997 g/mol). Then, use the mole ratio of 1 mol NaCl for every 1 mol NaOH to get to moles of NaCl. Then finally multiply by the molar mass of NaCl (58.44 g/mol) to get grams of NaCl.
20.6 g NaOH • (1 mol NaOH / 39.997 g NaOH) • (1 mol NaCl / 1 mol NaOH) • (58.44 g NaCl / 1 mol NaCl) = 30.1 g NaCl