PHYSICS COLLEGE

A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle are both traveling at the same speed of 19.0m/s , and the distance between them is 52.0m . After t1 = 5.00s , the motorcycle starts to accelerate at a rate of 5.00m/s^2. a. How long does it take from the moment when the motorcycle starts to accelerate until it catches up with the car? In other words. b. Find t2−t1

Answers

Answer 1

Answer:

Answer:

$t\approx4.561\ s$

Explanation:

Given:

initial speed of car and motorcycle, $v=19\ m.s^(-1)$

initial distance between the car and motorcycle, $s=52\ m$

time after which the motorcycle starts to accelerate, $t_1=5\ s$

rate of acceleration of motorcycle, $a=5\ m.s^(-2)$

The initially the relative velocity of the motorcycle is zero with respect to car.

Now using the equation of motion in the relative quantities:

$s=u.t+(1)/(2) .a.t^2$

here:

$s =$ relative distance of motorcycle with respect to the car

$u=$ initial relative velocity of the motorcycle with respect to the car

$t=$ time taken to cover the distance gap from the car.

$52=0+0.5* 5* t^2$

$t\approx4.561\ s$

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When an external magnetic field is applied, what happens to the protons in a sample?A) All protons align with the field.
B) All protons align opposite to the field.
C) Some protons align with the field and some align opposite to it.
D) All protons assume a random orientation.

Answers

On account of external magnetic field, the protons will align with the magnetic field. Hence, option (a) is correct.

The given problem is based on the concept of magnetic field. The region where the magnetic force is experienced is known as magnetic field. Generally, the protons are the charged entities carrying the positive polarity and are one of the major constituents of modern atomic structure.

The origin of magnetic field occurs due to charged particles present in a specific space. And the magnetic field is due to the flowing of liquid metal in the outer core of the planet generates electric currents.
In the condition when an external field is applied, the majority of protons align to the field because these protons tend to act like small magnets under the effect of this external field.

Thus, we can conclude that on account of external magnetic field, the protons will align with the field.

Learn more about the magnetic field here:

brainly.com/question/14848188

Answer:

Some protons align with the field and some align opposite to it.

Explanation:

Majority align to the field because these protons tend to act like small magnets under the effect of this external field

A 1000-kg car rolling on a smooth horizontal surface ( no friction) has speed of 20 m/s when it strikes a horizontal spring and is brought to rest in a distance of 2 m What is the spring’s stiffness constant?

Answers

Explanation:

kinetic energy was converted to potential energy in the spring.

the answer is in the above image

1. Draw a quantitative motion map for the following description: A bicyclist speeds along a road at 10 m/s for 6 seconds. Then she stops for three seconds to make a 180˚ turn and then travels at 5 m/s for 3 seconds.

Answers

Answer:

Please find the attached file for the figure.

Explanation:

Given that a bicyclist speeds along a road at 10 m/s for 6 seconds.

Its acceleration = 10/6 = 1.667 m/s^2

The distance covered = 1/2 × 10 × 6

Distance covered = 30 m

That is, displacement = 30 m

Then she stops for three seconds to make a 180˚ turn and then travels at 5 m/s for 3 seconds.

The acceleration = 5/3 = 1.667 m/s^2

The displacement = 1/2 × 5 × 3

Displacement = 7.5 m

The resultant acceleration will be equal to zero.

While the resultant displacement will be:

Displacement = 30 - 7.5 = 22.5 m

Please find the attached file for the sketch.

A large rectangular tub is filled to a depth of 2.60 m with olive oil, which has density 915 kg/m3 . If the tub has length 5.00 m and width 3.00 m, calculate (a) the weight of the olive oil, (b) the force of air pressure on the sur- face of the oil, and (c) the pressure exerted upward by the bottom of the tub.

Answers

Answer:

weight is 3.50 x 10^5 N

force is 1.52 * 10^6 N

pressure is 1.25 * 10^5 Pa

Explanation:

given data

Given data

depth = 2.60 m

density = 915 kg/m3

length = 5.00 m

width = 3.00 m

to find out

weight of the olive oil, force of air pressure and the pressure exerted upward

solution

we know density = mass / volume

mass = density* width *length *depth

mass = (915)(3)(5)(2.60)

mass = 3.57 x 10^4 Kg

so weight = mg = 3.57 x 10^4 (9.81) = 3.50 x 10^5 N

weight is 3.50 x 10^5 N

and

we know force = pressure * area

area = 3 *5 = 15 m²

and we know atmospheric Pressure is about 1.01 * 10^5 Pa

so force = 1.01 * 10^5 (15) = 1.52 x 10^6 N

force is 1.52 * 10^6 N

and

we know Fup - Fdown = Weight

Fup = 1.52 * 10^6 + 3.50 * 10^5

Fup = 1.87 * 10^6 N

so pressure = Fup / area

pressure = 1.87 * 10^6 / 15

pressure is 1.25 * 10^5 Pa

So to deal with the irrational belief in REBT, we must Group of answer choices

A. Consult with a friend and get their feeback

B. Dispute the beliefs by asking if these are true and examining the evidence

C. Seek mental health counseling

D. It is just too hard so let's just forget it.

Answers

Answer:

i believe the answer is B

Explanation:

Seeking the right answer is the best thing to do

What is the magnifying power of an astronomical telescope using a reflecting mirror whose radius of curvature is 5.5 mm and an eyepiece whose focal length is 2.9 cmcm ? Follow the sign conventions.

Answers

The magnifying power of an astronomical telescope will be:

"0.095".

Telescope: Focal length and Power

According to the question,

Radius of curvature, R = 5.5 mm

Focal length of eyepiece, $F_e$ = 2.9 cm

We know that,

→ Focal length of mirror,

F₀ = $(Radius \ of \ curvature)/(2)$

By substituting the values,

= $(5.5)/(2)$

= 2.75 mm or,

= 0.278 cm

hence,

The telescope's magnification be:

= $(F_0)/(F_e)$

= $(0.275)/(2.9)$

= 0.095

Thus the above approach is correct.

Find out more information about magnification here:

brainly.com/question/1477543

Answer:

0.095

Explanation:

An astronomical telescope is a telescope used for viewing far distance object. It uses two lenses called the objective lens and the eyepiece lens.

Each lens has its own focal length

Let the focal length of the objective lens be Fo

Focal length of the eyepiece be Fe

Magnification of an astronomical telescope = Fo/Fe

Since the telescope uses a reflecting mirror having radius of curvature of 5.5mm instead of an objective lens, then we will replace Fo as the focal length of the mirror.

Focal length of a mirror Fo = Radius of curvature/2

Fo = R/2

Fo = 5.5/2

Fo = 2.75mm

Converting 2.75mm to cm gives 2.75/10 = 0.275cm

Fo = 0.275cm; Fe = 2.9cm

Magnification of the telescope = 0.275/2.9

Magnification of the astronomical telescope = 0.095

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