PHYSICS COLLEGE

Two 10-cm-diameter charged rings face each other, 25.0cm apart. Both rings are charged to +20.0nC. What is the electric field strength at:a) the midpoint between the two rings?b) the center of the left ring?

Answers

Answer 1

Answer:

The electric field strength at the midpoint of the rings is 0 N/C.

The electric field strength at the center of the left ring is 2710.84 N/C.

The given parameters:

Diameter of the rings, d = 10 cm
Distance between the rings, r = 25 cm
Charge of the rings, q = 20 nC

The electric field strength at the midpoint of the rings is calculated as follows;

$E_(net) = E_1 + E_2\n\nE_(net) = E_1(+ve) - E_2(-ve) = 0$

The electric field strength at the center of the left ring is calculated as follows;

$E = (kqL)/((R^2 + L^2)^(3/2)) \n\nE = (9* 10^9 * 20* 10^(-9) * 0.25 \ )/((0.05^2 + 0.25^2 )^(3/2)) \n\nE = 2710.84 \ N/C$

Learn more about electric field here: brainly.com/question/14372859

Answer 2

Answer:

Final answer:

The electric field strength at the midpoint between the two rings is zero, and at the center of the left ring, it is 2.88 * 10^4 N/C.

Explanation:

The electric field strength at the

midpoint between the two rings is zero. The electric fields from each ring cancel each other out at this point because they are equal in magnitude and opposite in direction.
At the center of the left ring, the electric field strength can be calculated using the formula for the electric field due to a charged ring. The formula is E = k * (Q / r²), where E is the electric field strength, k is the Coulomb's constant, Q is the charge, and r is the distance from the center of the ring. Plugging in the values, we get:

E = (8.99 * 10^9 Nm²/C²) * (20.0 * 10^-9 C) / (0.05 m)² = 2.88 * 10^4 N/C

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The table below shows the mass and velocity of four objects. Which object has the least inertia?A. Y
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C. X
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Answers

The object with the least inertia is Z.

option B is the correct answer.

What is Newton's first law of motion?

Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that path unless it is acted upon by an external force and it will move in the direction of applied force.

The Newton's first law of motion is also called the law of inertia because it depends on the mass of the object.

Inertia is defined as the reluctancy of an object to move when a force is applied to it.

As the mass of an object increase, the inertia of the object increases because the object will be more reluctant to move when a force is applied to it.

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A block m1 rests on a surface. A second block m2 sits on top of the first block. A horizontal force F applied to the bottom block pulls both blocks at constant velocity. Here m1 = m2 = m.(a)
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Answers

(a) The normal force exerted by the surface on the bottom block is N1 = 2mg.

Given that,

A block m1 rests on a surface.
A second block m2 sits on top of the first block.
A horizontal force F applied to the bottom block pulls both blocks at constant velocity. Here m1 = m2 = m.

Based on the above information, we can say that the N1 is 2mg.

Learn more: brainly.com/question/17429689

Answer:

N = 2mg

Explanation:

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2
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Answers

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srry ik im super late but to help other people theres the answer

The temperature within a thin plate with thermal conductivity of 10 W/m/K depends on position as given by the following expression: TT=(100 K)????????−xx2/????????xx 2cos�yy/????????yy�+300 K Where, Lx = 1 m, and Ly = 2 m. At the point (0.4 m, 1 m), find: a. The magnitude of the heat flux b. The direction of the heat flux

Answers

Answer:

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b) Direction of the heat flux = 18.85°

Explanation:

- The correct question is the first image attached to this solution.

- The solution to this question is contained on the second and third images attached to this solution respectively.

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the period of the satellite is exact 42.391 hours, the earth's mass is 5.98 kg and the radius of th earth is 3958.8 miles, what is the distance of the satellite from the surface of the earth in miles?

Answers

Answer:

As the mass is not written well, i will use the equation in terms of the gravitational acceleration:

The equation for the period of a satellite is:

$T = 2*pi*\sqrt{(r^3)/(g*R^2) }$

We want to find r, so isolating r we get:

$r = \sqrt[3]{x ((T)/(2*pi) )^2*g*R^2}$

Where:

T = period.

r = radius of the satellite.

R = radius of the planet.

g = gravitational acceleration of the planet.

pi = 3.14159...

g = 78999.64 mi/h^2 (value of a table)

T = 42.391 h.

R = 3958.8 miles

We can replace those values in the equation and get:

$r = \sqrt[3]{ ((42.391)/(2*3.14159) )^2*78999.64*(3958.8)^2} = 38,339.5 mi$

Now this value is measured from the center of the Earth, then the altitude of the satellite measured from the surface of the Earth will be:

H = r - R = 38,339.1mi - 3958.8mi = 34,380.3 mi

The equations for single-slit and multiple-slit interference both contain the variable θ. For the multiple-slit case, the angle is: a. the angular location of the first order minimum in the diffraction pattern. Which means at this point the light experiences constructive interference.
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c. the angular location of bright interference maxima in the pattern. Which means at this point the light experiences constructive interference.
d. the angular location of bright interference maxima in the pattern. Which means at this point the light experiences destructive interference.

Answers

Answer:

the answers the correct one is c

Explanation:

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