Layla is walking in a rectangular park. She walks one side that is 50 yards and then the otherside that is 120 yards. Layla develops a cramp in her leg and walks diagonally through the park
to head back home. What is the total distance that layla walked? (HINT: Final answer is
perimeter of the triangle park)
120 yd.
PARK
PARK
50 vd
Oak St
1
Park Rd

Answers

Answer 1
Answer:

Total distance walked by Layla is 300 yards

Solution:

Given that,

Layla is walking in a rectangular park

She walks one side that is 50 yards and then the other  side that is 120 yards

Length = 120 yards

Width = 50 yards

Layla develops a cramp in her leg and walks diagonally through the park  to head back home

Let us find the length of diagonal of rectangle

d=√(w^2+l^2)

d = √(50^2+120^2)\n\nd = √(2500+14400)\n\nd = √(16900)\n\nd = 130

Thus length of diagonal is 130 yards

What is the total distance that layla walked?

Given that Final answer is  perimeter of the triangle park

The diagonal and length and width forms a right angle triangle

Perimeter of triangle = diagonal length + width + length

Perimeter of triangle = 130 + 50 + 120 = 300

Thus total distance walked by Layla is 300 yards


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Answers

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Answers

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Answers

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