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The following reaction was monitored as a function of time: A→B+C A plot of ln[A] versus time yields a straight line with slope −4.3×10−3 /s. If the initial concentration of A is 0.260 M, what is the concentration after 225 s?

Answers

Answer 1

Answer:

The concentration after 225 s is 0.099 M.

As we know that, the graph of ln [A] versus time yields a straight line with slope 'k'.

So, Slope = k = $4.3*10^(-3)/s$

Rate law for first order kinetics:

$t=(2.303)/(k) log (a)/(a-x)$

where,

k = rate constant = $4.3*10^(-3)/s$

t = time passed by the sample = 225 s

a = initial amount of the reactant = 0.260 M

a - x = amount left after decay process = ?

On substituting the values:

$t=(2.303)/(k) log (a)/(a-x)\n\nt=(2.303)/(4.3*10^(-3)) log (0.260)/(a-x)\n\na-x=0.099M$

Therefore, the concentration after 225 s is 0.099 M.

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Answer 2

Answer:

Answer : The concentration after 225 s is, 0.099 M

Explanation :

As we know that, the graph of ln [A] versus time yields a straight line with slope 'k'.

So, Slope = k = $4.3* 10^(-3)s^(-1)$

Expression for rate law for first order kinetics is given by:

$t=(2.303)/(k)\log(a)/(a-x)$

where,

k = rate constant = $4.3* 10^(-3)s^(-1)$

t = time passed by the sample = 225 s

a = initial amount of the reactant = 0.260 M

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$225=(2.303)/(4.3* 10^(-3))\log(0.260)/(a-x)$

$a-x=0.099M$

Therefore, the concentration after 225 s is, 0.099 M

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How many moles of Al are necessary to form 23.6 g of AlBr₃ from this reaction: 2 Al(s) + 3 Br₂(l) → 2 AlBr₃(s) ?

Answers

0.085 moles of Al are required to form 23.6 g of AlBr₃.

Let's consider the following balanced equation for the synthesis reaction of AlBr₃.

2 Al(s) + 3 Br₂(l) → 2 AlBr₃(s)

First, we will convert 23.6 g to moles using the molar mass of AlBr₃ (266.69 g/mol).

$23.6 g * (1mol)/(266.69g) = 0.0885 mol$

The molar ratio of Al to AlBr₃ is 2:2. The moles of Al required to form 0.0885 moles of AlBr₃ are:

$0.0885molAlBr_3 * (2molAl)/(2molAlBr_3) = 0.0885molAl$

0.085 moles of Al are required to form 23.6 g of AlBr₃.

You can learn more about stoichiometry here: brainly.com/question/22288091

Answer:

0.088 mole of Al.

Explanation:

First, we shall determine the number of mole in 23.6 g of AlBr₃.

This is illustrated below:

Mass of AlBr₃ = 23.6 g

Molar Mass of AlBr₃ = 27 + 3(80) = 267 g/mol

Mole of AlBr₃ =.?

Mole = mass/Molar mass

Mole of AlBr₃ = 23.6 / 267

Mole of AlBr₃ = 0.088 mol

Next, we shall writing the balanced equation for the reaction.

This is given below:

2Al(s) + 3Br₂(l) → 2AlBr₃(s)

From the balanced equation above,

2 moles of Al reacted with 3 mole of Br₂ to 2 moles AlBr₃.

Finally, we shall determine the number of mole of Al needed for the reaction as follow:

From the balanced equation above,

2 moles of Al reacted to 2 moles AlBr₃.

Therefore, 0.088 mole of Al will also react to produce 0.088 mole of AlBr₃.

From the combinations of substances listed below, which would most likely be miscible ineach other?
(33 Points)
A.polar water, nonpolar oil
B.polar vinegar, nonpolar nail polish
C. polar bleach, polar water
D.nonpolar mineral oil, polar alcohol

Answers

Answer:

Explanation:

polar has unequal sharing of electrons that has the lone pairs which has the electronegativity difference. can be mixed with water.

Final answer:

The combination of polar bleach and polar water would likely be most miscible with each other as substances with similar molecular structures and polarities tend to mix. This is based on the rule of 'like dissolves like' in chemistry.

Explanation:

The question is asking which combination of substances would be most likely to mix, or be miscible, in one another. Miscibility is a property in chemistry relating to whether different substances can combine into a homogeneous mixture without separating.

The rule of thumb in chemistry is 'like dissolves like' which means that substances with similar molecular structures and polarities tend to be miscible with each other. Therefore, among the provided options, the combination of polar bleach and polar water (Option C) would be the most likely to mix with each other as they are both polar substances.

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Ammonia, methane, and phosphorus trihydride are three different compounds with three different boiling points. Rank their boiling points in order from lowest to highest.A. CH4< NH3 < PH3
B. NH3 < PH3< CH4
C. CH4 < PH3 < NH3
D. NH3 < CH4< PH3
E. PH3< NH3 < CH4

Answers

Answer:

B. NH3 < PH3< CH4

Explanation:

Hello,

In this case, taking into account that the boiling point of ammonia, methane and phosphorous trihydrate are -33.34 °C, -161.5 °C and -87.7 °C, clearly, methane has the lowest boiling point (most negative) and ammonia the greatest boiling point (least negative), therefore, ranking is:

B. NH3 < PH3< CH4

Best regards.

Why was plastic first invented? How is plastic bad for the environment?

Answers

Answer: The first plastic based on a synthetic polymer was invented in 1907. Plastic sticks around in the environment for ages, threatening wildlife and spreading toxins.

Not sure how it was invented but it had for the environment cause it causes plastic particles killing anything or endangering those that consume it.

. Which law of motion relates the action of a stretched rubber band

Answers

Answer:

newtons 3rd law of motion

Explanation:

Calculate the pH of a buffer solution made by adding 15.0 g anhydrous sodium acetate (NaC2H3O2) to 100.0 mL of 0.200 M acetic acid. Assume there is no change in volume on adding the salt to the acid. (pKa for acetic acid is 4.74 or Ka is 1.8 x 10-5)3.