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A rabbit is moving in the negative x-direction at 1.10 m/s when it spots a predator and accelerates to a velocity of 13.9 m/s along the negative y-axis, all in 1.20 s. Determine the x-component and the y-component of the rabbit's acceleration. (Enter your answers in m/s2. Indicate the direction with the signs of your answers.) HINT

Answers

Answer 1

Answer:

Answer:

Explanation:

Initial velocity u = -1.1 i m /s ( along - ve direction )

final velocity = - 13.9 j

change in velocity = -13.9 j + 1.1 i

rate of change of velocity

acceleration

= (-13.9 j + 1.1 i) / 1.2

= -11.58 j + 0.916 i

x component

= 0.916 m /s²

y component

= - 11.58 m / s²

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What two statements are true about energy transformations

Answers

Answer:

First statement:

Energy can neither be created nor destroyed.

Second statement:

Energy can be converted from one form to another.

Explanation:

According to the law of conservation of energy:energy can neither be created nor destroyed but can be converted from one form to another

The International Space Station (ISS) is a space station orbiting the earth above the ground. If the radius of the earth is 3,958.8 miles, mass of earth is 5.972 x 10 24 kg, the period of the ISS at the orbit around the earth is 7.84 hours, can you calculate what is the distance from the ISS to the surface of the earth, in unit of miles

Answers

Answer:

8488 miles

Explanation:

The orbital period around an earth is given as:

$T=2\pi \sqrt{(r^3)/(Gm) }$

Where G = constant = 6.67 x 10ˉ¹¹ N m² kgˉ², m = mass of object, T = period taken to round the earth, r = distance from the center of the earth to the orbiting object = radius of earth + orbital altitude.

Given that T = 7.84 hours = 28224 seconds, m = 5.972 x 10²⁴ kg, radius of earth = 3,958.8 miles = 6371071 m

$T=2\pi \sqrt{(r^3)/(Gm) }\n\nsquaring:\n\nT^2=4\pi^2 ((r^3)/(Gm) )\n\nr^3=(GmT^2)/(4\pi^2) \n\nr=\sqrt[3]{(GmT^2)/(4\pi^2) } \n\nr=\sqrt[3]{(6.67*10^(-11)*5.972*10^(24)*(28224)^2)/(4\pi^2) } \n\nr=20031232.62\ meters$

r = radius of earth + distance from the ISS to the surface of the earth

distance from the ISS to the surface of the earth = r - radius of earth

distance from the ISS to the surface of the earth = 20031232.62 meters - 6371071 meters = 13660161.62 meters

distance from the ISS to the surface of the earth = 13660161.62 meters = 8488 miles

Which law does the following statement express? "In all cases of electromagnetic induction, the induced voltages have adirection such that the currents they produce oppose the effect that produces them."

Answers

Final answer:

Faraday's Law of electromagnetic induction states that induced voltages produce currents that oppose the change in the magnetic field.

Explanation:

The law that the statement expresses is Faraday's Law of electromagnetic induction.

According to Faraday's Law, whenever there is a change in the magnetic field through a conductor, it induces an electromotive force (EMF) or voltage across the conductor. This induced voltage creates a current that flows in a direction that opposes the change in magnetic field.

This phenomenon is described by Lenz's Law, which states that the induced current always flows in such a way as to produce a magnetic field that opposes the change in the external magnetic field.

Learn more about Faraday's Law of electromagnetic induction here:

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Imagine two billiard balls on a pool table. Ball A has a mass of 2 kilograms and ballB has a mass of 3 kilograms. The initial velocity of ball A is 9 meters per second to
the right, and the initial velocity of the ball B is 6 meters per second to the left. The
final velocity of ball A is 9 meters per second to the left, while the final velocity of
ball B is 6 meters per second to the right.

1. Explain what happens to each ball after the collision. Why do you think this
occurs? Which of Newton’s laws does this represent?

Answers

This is an example of an elastic collision. The two objects collide and return to their original shapes and move separately. In such a collision, kinetic energy is conserved. I think we can agree that this represents Newton's third law by demonstrating conservation of momentum.

Answer:

Yes, the law of conservation of momentum is satisfied. The total momentum before the collision is 1.5 kg • m/s and the total momentum after the collision is 1.5 kg • m/s. The momentum before and after the collision is the same.

Explanation:

From her bedroom window a girl drops a water-filled balloon to the ground, 4.77 m below. If the balloon is released from rest, how long is it in the air?

Answers

We need to use the equation x = vt + (1/2)at^2. We know x = 4.77, v = 0, and a = 9.81m/s^2. Plug in the values. 4.77 = (0)t + (1/2)(9.81)t^2 Solve for t. 4.77 = (4.905)t^2 0.972 = t^2 t = (sq.rt)_/0.972 t = 0.985 So it's in the air 0.985 seconds.

The rms speed of the molecules in 1.3 g of hydrogen gas is 1600 m/s.Part A. What is the total translational kinetic energy of the gas molecules?
Part B. What is the thermal energy of the gas?
Part C. 500J of work are done to compress the gas while, in the same process, 2000J of heat energy are transferred from the gas to the environment. Afterward, what is the rms speed of the molecules?

Answers

a. The total translational kinetic energy of the gas molecules is 1672 Joules.

b. The thermal energy of a gas molecule is equal to 1672 Joules.

c. The rms speed of the gas molecules is equal to 512.83 m/s.

Given the following data:

Mass of hydrogen gas = 1.3 gram.

Speed (rms), c = 1600 m/s.

Work done = 500 Joules.

Quantity of energy = 2000 Joules.

Scientific data:

Mass of proton = $1.67 * 10^(-27)$ kg.

Avogadro constant = $6.02 * 10^(23)$

a. To calculate the total translational kinetic energy of the gas molecules:

How to calculate translational kinetic energy.

First of all, we would determine the number of moles of hydrogen gas contained in 1.3 grams:

Note:Molar mass of hydrogen gas = 2 g/mol.

$Number \;of \;moles = \frac {mass}{molar\;mass}\n\nNumber \;of \;moles = \frac {1.3}{2}$

Number of moles = 0.65 moles.

Next, we would determine the number of molecules in 0.65 moles of hydrogen gas:

By stoichiometry:

1 mole = $6.02 * 10^(23)$ molecules.

0.65 mole = X molecules.

Cross-multiplying, we have:

X = $0.65 * 6.02 * 10^(23)$ = $3.913 * 10^(23)$ molecules.

Mathematically, total translational kinetic energy is given by this formula:

$T = (1)/(2) mc^2$

Substituting the given parameters into the formula, we have;

$T = (1)/(2) * 2 * 1.67 * 10^(-27) * 3.913 * 10^(23) * (1600)^2\n\nT = 6.53 * 10^(-4) * 2560000$

T = 1,671.68 ≈ 1672 Joules.

b. In Science, the total translational kinetic energy is equal to the thermal energy of a gas molecule.

Thermal energy = 1672 Joules.

c. To calculate the rms speed of the gas molecules:

$Net\;energy = 500 + 1672 -2000$

Net energy = 172 Joules.

For the rms speed:

$172 = (1)/(2) * 2 * 1.67 * 10^(-27) * 3.913 * 10^(23) * c^2\n\n172 = 6.54 * 10^(-4) c^2\n\nc = \sqrt{(172)/(6.54 * 10^(-4)) } \n\nc=√(262996.95)$

c = 512.83 m/s.

Read more on rms speed here: brainly.com/question/7427089

Final answer:

The total translational kinetic energy and thermal energy of 1.3g of hydrogen gas with rms speed of 1600 m/s is 5.01x10^25 Joules. After work of 500 Joules is done to compress the gas and 2000 Joules of heat energy are transferred out, the kinetic and thermal energy remains the same, thus the rms speed remains largely the same (with a negligible change due to roundoff errors).

Explanation:

You're asking about the behavior of a hydrogen gas in terms of its kinetic and thermal energy, as well as changes in its root mean square (rms) speed as work is done to compress the gas and heat is transferred out of it.

Part A: The total translational kinetic energy can be calculated using the formula 1/2*m*v^2, where m is the mass and v is the speed. For hydrogen in monoatomic gas, 1.3g of hydrogen is about 0.65 moles. 1 mole's mass is about 1g, so 0.65 moles would be about 0.65g. Convert this to kilograms: 0.65g = 0.00065kg. To find the individual molecule's kinetic energy, you multiply by Avogadro's number (6.02*10^23) as there are that many molecules in a mole. Therefore, the Total translational kinetic energy = 1/2 * 0.00065 kg * (1600 m/s)^2 * 6.02x10^23 = 5.01x10^25 Joules.

Part B: At equilibrium, the thermal energy of a gas is equal to its kinetic energy, so the thermal energy would also be 5.01x10^25 Joules.

Part C: According to the principle of energy conservation, the final kinetic (and thus, thermal) energy of the gas will be its initial energy plus the work done on it minus the heat transferred out of it. Therefore, the final energy = 5.01x10^25 Joules + 500 Joules - 2000 Joules = 5.01x10^25 Joules. To find the new rms speed, you set this equal to the kinetic energy formula and solve for v. Doing so gets you a modulus change in the root mean square speed. Please note that this involves some simplifying assumptions and may not reflect what would happen in a more complex system.

Learn more about Gas Physics here:

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