//This method uses the newly added parameter Club object //to create a CheckBox and add it to a pane created in the constructor //Such check box needs to be linked to its handler class
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Comments on Question
Your questions is incomplete.
I'll provide a general answer to create a checkbox programmatically
Answer:
// Comments are used for explanatory purpose
// Function to create a checkbox programmatically
public class CreateCheckBox extends Application {
// launch the application
public void ClubObject(Stage chk)
{
// Title
chk.setTitle("CheckBox Title");
// Set Tile pane
TilePane tp = new TilePane();
// Add Labels
Label lbl = new Label("Creating a Checkbox Object");
// Create an array to hold 2 checkbox labels
String chklbl[] = { "Checkbox 1", "Checkbox 2" };
// Add checkbox labels
tp.getChildren().add(lbl);
// Add checkbox items
for (int i = 0; i < chklbl.length; i++) {
// Create checkbox object
CheckBox cbk = new CheckBox(chklbl[i]);
// add label
tp.getChildren().add(cbk);
// set IndeterMinate to true
cbk.setIndeterminate(true);
}
// create a scene to accommodate the title pane
Scene sc = new Scene(tp, 150, 200);
// set the scene
chk.setScene(sc);
chk.show();
}
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Required information NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. The gas-turbine cycle of a combined gas–steam power plant has a pressure ratio of 8. Air enters the compressor at 290 K and the turbine at 1400 K. The combustion gases leaving the gas turbine are used to heat the steam at 15 MPa to 450°C in a heat exchanger. The combustion gases leave the heat exchanger at 247°C. Steam expands in a high-pressure turbine to a pressure of 3 MPa and is reheated in the combustion chamber to 500°C before it expands in a low-pressure turbine to 10 kPa. The mass flow rate of steam is 17 kg/s. Assume isentropic efficiencies of 100 percent for the pump, 85 percent for the compressor, and 90 percent for the gas and steam turbines.Determine the rate of total heat input.
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Answer:
=> base transport factor = 0.98.
=> emitter injection efficiency = 0.99.
=> common-base current gain = 0.97.
=> common-emitter current gain = 32.34.
=> ICBO = 1 × 10^-6 A.
=> base transit time = 0.325.
=> lifetime = 1.875.
Explanation:
(Kindly check the attachment for the diagram showing the dominant current components, with proper arrows, for directions in the normal active mode).
The following parameters or data are given for a p-n-p BJT with NE 7 NB 7 NC and they are: IEp = 10 mA, IEn = 100 mA, ICp = 9.8 mA, and ICn = 1 mA.
(1). The base transport factor = ICp/IEp=9.8/10 = 0.98.
(2). emitter injection efficiency =IEp/ IEp + ICn = 10/10 + 0.1 = 0.99.
(3).common-base current gain = 0.98 × 0.99 = 0.9702.
(4).common-emitter current gain =0.97 / 1- 0.97 = 32.34.
(5). Icbo = Ico = 1 × 10^-6 A.
(6). base transit time = 1248 × 10^-2 × (1.38× 10^-23/1.603 × 10^-19). = 0.325.
(7).lifetime;
= > 2 = √0.325 + √ lifetime.
= Lifetime = 2.875.
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Answer:
you too
Explanation:
thank you for the free points
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Answer: c) 450 kPa
Explanation:
Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.
(At constant temperature and number of moles)
where,
= initial pressure of gas = 150 kPa
= final pressure of gas = ?
= initial volume of gas = v L
= final volume of gas =
Therefore, the new pressure of the gas will be 450 kPa.
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Answer:
the relative compaction is 105.88 %
Explanation:
Given;
dry unit weight of field compaction, = 18 kN/m³
maximum dry unit weight measured, = 17 kN/m³
Relative compaction (RC) of the site is given as the ratio of dry unit weight of field compaction and maximum dry unit weight measured
Relative compaction (RC) = dry unit weight of field compaction / maximum dry unit weight measured
substitute the given values;
RC (%) = 105.88 %
Therefore, the relative compaction is 105.88 %
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Three activities that I can do on a daily basis that involve both metric units (SI units) and customary units are: measuring the length of a door with a tape measure, which includes both SI units and customary units (like feet, inches, and centimeters); baking a cake that calls for one teaspoon (customary unit) of baking soda, which can also be converted to four grams (SI unit); and weighing myself on a weighing scale, which can be measured in pound and kilogram (metric unit).
Answer: Three examples of activities that I can perform on a daily basis that involves both metric units (SI units) and customary units include: measuring the length of a door using a tape measure, which includes both SI units and customary units (like feet, inches, and centimeters); baking a cake that requires one teaspoon (customary unit) of baking soda, which could also be converted into four grams (SI unit); weighing myself on a weighing scale, which can be measured by pounds (customary unit) or kilograms (metric unit).
Explanation:I big brain :) (Not Really I Just Wanted To Help) I hope this helped! ;)
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Answer:
364 566 inches of class-6th from a