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The height h (in feet) of an object shot into the air from a tall building is given by the function h(t) = 650 + 80t − 16t2, where t is the time elapsed in seconds. (a) Write a formula for the velocity of the object as a function of time t.

Answers

Answer 1

Answer:

80 - 32t

Explanation:

The height, h, in terms of time, t, is given as:

h(t) = 650 + 80t − 16t²

Velocity is the derivative of distance with respect to time:

v(t) = dh(t)/dt = 80 - 32t

Answer 2

Answer:

Final answer:

The velocity of the object as a function of time is given by the derivative of the height function, which is v(t) = 80 - 32t.

Explanation:

The height h(t) of an object is given by the equation h(t) = 650 + 80t − 16t2. To find the velocity v(t), we need to take the derivative of h(t) with respect to time t. Using the power rule, we get:

v(t) = dh/dt = 0 + 80 - 32t.

So, the velocity of the object as a function of time t is v(t) = 80 - 32t.

Learn more about Velocity Function here:

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Two 3.7 microCoulomb charges are 0.8 m apart. How much energy (in milliJoule) went into assembling these two charges? Enter a number with one digit behind the decimal point.

Answers

Answer:

Explanation:

The potential energy of a system of two charges is given by the expression

$(K* Q_1* Q_2)/(R)$

Q₁ and Q₂ are two charges and R is distance between the charges.

Given Q₁ = Q₂ = 3.7 X 10⁻⁶ , R = .8 and K = 9 x 10⁹

Putting these values in the equation we have,

$[tex](9* 10^9* 3.7*10^(-6) 3.7* 10^(-6))/(.8)$ [/tex]

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A 120-V rms voltage at 60.0 Hz is applied across an inductor, a capacitor, and a resistor in series. If the peak current in this circuit is 0.8484 A, what is the impedance of this circuit

Answers

Answer:

200 $\Omega$

Explanation:

The computation of the impedance of the circuit is shown below:

Provided that

RMS voltage = 120 v

Frequency = 60.0 Hz

RMS current = 0.600 A

Based on the above information, the formula to compute the impedance is

$Z=(V_(max))/(I_(peak))$

where,

$V_(max) = √(2) * V_(rms)$

$= √(2) * 120$

$= 169.7 V$

And, $I_Peak = 0.8484$

Now placing these above values to the formula

So, the impedance of the circuit is

$= (169.7)/(0.8484)$

= 200 $\Omega$

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Answers

Answer:

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Explanation:

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Answers

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Answer:

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Explanation:

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Answers

Explanation:

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