Malia did push-ups and pull-ups in her physical education class. She did 24 push-ups and pull-ups combined, with each push-up taking her 2 seconds and each pull-up taking her 4 seconds. If she spent a total of 68 seconds doing the push-ups and pull-ups, how many pull-ups did she do?

Answers

Answer 1
Answer:

Answer:

12 pull

As 48 seconds + 20 seconds push = 68 seconds

Step-by-step explanation:

Because she did 10 push = 20 seconds = 2 seconds each

12 pull = 48 seconds  = 4 seconds each

= 68 seconds combined.

Workings;

18 seconds found for the first set

We then find a divider of 68 and know that

6 x 3 = 18 seconds push

12 x 3 =36 seconds pull  T= 54

14 left over = 1 x 12 seconds pull

+ 2 seconds push

= 10 push = 20 seconds combined.

= 12 pull = 48 seconds combined.

Answer 2
Answer:

Answer:

yall its ten

Step-by-step explanation:

twelves not even an option and i got it right edge2020


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What number is 65% of 98?

Answers

What is 65% of 98? in mathematical terms it means:
X= 0.65*98
multiply 0.65 by 98, that equals 63.7

Answer:

63.7

Step-by-step explanation:

x=0.65*98

In A School Election 3/4 Of The Students Vote. There Are 1464 Ballots. Write And Solve An Equation To Find The Number Of Students

Answers

A simple way to turn this into an equation is by replacing the words with letters: 
1464B = 3/4 S

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Answers

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the base of a regular pyramid is a hexagon whose perimeter is 84 feet. the volume of the pyramid is approximately 4,677.85 cubic feet. find the height of the pyramid.

Answers

Answer:

The height of the pyramid is 27.56\ ft

Step-by-step explanation:

we know that

The volume of the pyramid is equal to

V=(1)/(3)BH

where

B is the area of the base of the pyramid

H is the height of the pyramid

step 1

Find the area B of the regular hexagonal base

we know that

The perimeter of a regular hexagon is

P=6b

where

b is the length side of the hexagon

we have

P=84\ ft

substitute

84=6b

solve for b

b=14\ ft

Remember that the area of a regular hexagon is the same that the area of six equilateral triangles

Determine the area of the six equilateral triangles, applying the formula of the law of sines

B=6[(1)/(2)b^2sin(60\°)]

substitute the value of b

B=6[(1)/(2)(14)^2sin(60\°)]

B=509.22\ ft^2

step 2

Find the height of the pyramid

V=(1)/(3)BH

we have

V=4,677.85\ ft^3

B=509.22\ ft^2

substitute

4,677.85=(1)/(3)(509.22)H

solve for H

14,033.55=(509.22)H

H=14,033.55/(509.22)H

H=27.56\ ft

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Answers

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