Answer:
(i) ΔS° < 0 or negative
(ii) ΔS° > 0 or positive
(iii) ΔS° > 0 or positive
(iv) ΔS° > 0 or positive
(v) ΔS° < 0 or negative
(vi) ΔS° > 0 or positive
Explanation:
Entropy is a state function and extensive property of the system.
It's the measurement of degree of randomness..
Entropy of the system decreases as follows
Gas > Liquid > Amorphous solid > Crystalline solid.
In case for chemical reaction
(i) Ba²⁺ (aq) + SO₄²⁻ (aq) --> BaSO₄ (s)
Total entropy change ΔS° < 0 or negative
During this reaction aqueous i.e liquid phase converted into solid phase.
So randomness decreases and hence entropy also decreases.
(ii) 2 NO₂ (g) --> N₂ (g) + 2 O₂ (g) ΔS° > 0 or positive
Since no. of gaseous moles increases from reactants to products.
(iii) C₅H₁₂ (g) + 8 O₂ (g) --> 5 CO₂ (g) + 6 H₂O (g) ΔS° > 0 or positive
Since no. of gaseous moles increases from reactants to products.
(iv) 2 NaClO₃ (s) --> 2 NaCl (s) + 3 O₂ (g) ΔS° > 0 or positive
Since no. of gaseous moles increases from reactants to products.
(v) 2 Na (s) + Cl₂ (g) --> 2 NaCl (s) ΔS° < 0 or negative
Since no. of gaseous moles decreases from left to right so entropy also decreases.
(vi) CH₃OH (l) --> CH₃OH (g) ΔS° > 0 or positive
Because during this phase transition Liquid to gaseous randomness increases and hence entropy also increases.
When the temperature of a substance decreases, the average kinetic energy of its particles also decreases. This is because the temperature of a substance is proportional to the average kinetic energy of its particles. The slower the particles move, the lower the kinetic energy.
The question refers to the relationship between the temperature of a substance and the average kinetic energy of its particles. According to the kinetic-molecular theory, the temperature of a substance is proportional to the average kinetic energy of its particles. When the temperature of a substance rises, the particles vibrate more in solids or move more rapidly in liquids and gases, indicating an increase in kinetic energy. Conversely, if the temperature decreases, the kinetic energy also decreases, and the particles move more slowly.
For instance, when the temperature of a gas increases, its average kinetic energy increases, more molecules have higher speeds and fewer molecules have lower speeds. The distribution shifts towards higher speeds overall. If the temperature decreases, the opposite happens: the average kinetic energy decreases, more molecules have lower speeds and fewer molecules have higher speeds. The distribution shifts towards lower speeds overall.
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Answer:
True
Explanation:
Many chemical and toxic substances used in modern industry are indeed flammable or combustible. These substances can pose significant safety hazards, especially in industrial settings, and require proper handling, storage, and safety measures to prevent fires and explosions. It is crucial to follow strict safety protocols and regulations when working with such materials to ensure the safety of workers and the environment.
The density of Argon gas at a pressure of 753 mmHg and a temperature of 35 °C is equal to 1.59 g/L.
The state of a quantity of gas is calculated by its pressure, volume, and temperature. The ideal gas law can be explained as the product of the volume and pressure of gas is equal to the multiplication of the universal gas constant and absolute temperature.
The mathematical equation for an ideal gas can be written as follows:
PV = nRT
PV =(m/M) RT
PM/RT = m/V
d = PM/RT
Where n is the moles of gas, T is the temperature of the gas, V is the volume of the gas, and R is the gas constant.
Given, the temperature of argon gas, T = 35 °C = 35 +273 = 308 K
The pressure of the argon gas, P = 753 mmHg = 1.01 atm
The molar mass of the Argon gas, M = 40 g/mol
Substitute V, R, P, and T in the ideal gas equation, we get:
The density of Argon gas, d = PM/RT
d= 1.01 ×40/(0.082 × 308)
d = 1.59 g/L
Therefore, the density of Ar gas is 1.59 g/L.
Learn more about ideal gas equation, here:
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Answer:
Detail is given below.
Explanation:
Given data;
Abundance of Berkmarium-95 = 70%
Abundance of Berkmarium-97 = 28%
Abundance of Berkmarium-94 = 2%
Average atomic mass closer to which isotope = ?
Solution:
1st of all we will calculate the average atomic mass of Berkmarium.
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass) / 100
Average atomic mass = (70×95)+(28×97)+(2×94) /100
Average atomic mass = 6650 + 2716+ 188 / 100
Average atomic mass= 9554 / 100
Average atomic mass = 95.54 amu
The average atomic mass is closer to the isotope Berkmarium-95 because it is present in abundance as compared to the other two isotope. So this isotope constitute most of the part of Berkmarium.
Answer:
For Edmentum/Plato users, the correct answer is A. 14.4%
B. Conduction
C. Radiation
D. Heat
Answer:
radiation
LOL but also heat
Explanation:
hope this helps