A car passes the Eiffel tower driving at a constant rate of 60 km per hour. A second car, traveling at a constant rate of 75 km per hour, passes the Eiffel tower a while later and then follows the first car. It catches the first car after traveling a distance of 75 km past the Eiffel tower. How many minutes after the first car passed the Eiffel tower did the second car pass the Eiffel tower

Answers

Answer 1
Answer:

Answer:

300 minutes.

Explanation:

Given,

Speed of car 1 = 60 Km/h

Speed of car 2 = 75 Km/h

distance travel by car 2 to catch car 1 = 75 Km

time taken to catch the car = ?

Relative velocity between the car = 75 - 60 = 15 Km/h

time = (distance)/(speed)

time = (75)/(15)

t = 5 hrs

t = 5 x 60 = 300 minutes.


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Opposite electric charges will repel, and like charges will attract.

Answers

As it stands now, that statement is false.

There are two ways to make the statement true:

#1).  Exchange the places of the words "Opposite" and "like".

#2).  Exchange the places of the words "repel" and "attract".

Either ONE of these changes will make the statement true.
Doing BOTH of these changes will leave it false.

Answer:

False. Opposite electric charges will attract, and like charges will repel.

suppose that you look into a photometer's eyepiece and the fluorescent disks appear to be equal in intensity. If the distance between the photometer to lamp 1 is 400mm, the distance between the photometer to lamp 2 is 200 mm, and the intensity of lamp 2 is known to be 15 candelas, what is the intensity to lamp 1?

Answers

Use the Inverse square law, Intensity (I) of a light is inversely proportional to the square of the distance(d).

I=1/(d*d)

Let Intensity for lamp 1 is L1 distance be D1 so on, L2 D2 for Intensity for lamp 2 and its distance.

L1/L2=(D2*D2)/(D1*D1)

L1/15=(200*200)/(400*400)
L1=15*0.25
L1=3.75 candela

"El sujeto es emergente de la compleja trama de relaciones vinculares e institucionales que lo determinan. En esa trama, las relaciones tempranas adquieren un lugar fundamental en los procesos de constitución subjetiva" Terigi, Flavia (2010) Sujetos de la Educación. Para el psicoanálisis, ¿cuáles serían esas relaciones tempranas y por qué se afirma que son fundamentales en los procesos de constitución subjetiva?

Answers

La respuesta correcta para esta pregunta abierta es la siguiente.

Para el psicoanálisis, las relaciones tempranas son las relaciones a posteriori entre los padres del recién nacido y el bebé mismo. Estas relaciones son fundamentales en los procesos de constitución subjetiva para el discurso parental para entender los aspectos del desarrollo infantil y sus diferentes estados o teorías de desarrollo para ir comprendiendo cada aspecto de la interrelación y el comportamiento entre las partes.

Para el psicoanálisis, el recién nacido está llegando a un núcleo familiar que ya está establecido y se basa en conocimientos, tradiciones y experiencias de los padres que han recibido de generaciones anteriores, y  éstas van a influir directamente en la interrelación permanente con los primeros años del crecimiento del bebé.

Ilya and Anya each can run at a speed of 8.90mph and walk at a speed of 3.80mph . They set off together on a route of length 5.00miles. Anya walks half of the distance and runs the other half, while Ilya walks half of the time and runs the other half.a)How long does it take Anya to cover the distance of 5.00miles ?
Express your answer numerically, in minutes.
b)Find Anya's average speed.
Express Anya's average speed save,Anya numerically, in miles per hour
C)How long does it take Ilya to cover the distance?
Express the time tIlya taken by Ilya numerically, in minutes.
d)Now find Ilya's average speed.
Express Ilya's average speed save,Ilya numerically, in miles per hour

Answers

Answer:

Part a)

T = 0.94 hours

Part b)

v_(avg) = 5.32 mph

Part c)

T = 0.79 h

Part d)

v_(avg) = 6.35 mph

Explanation:

Speed while she is running = 8.90 mph

speed while she walk = 3.80 mph

Part a)

Anya walks half the distance

so time to walk

t_1 = (2.5)/(3.80) = 0.66 h

time to cover the distance while she run

t_2 = (2.5)/(8.90) = 0.28 h

total time to cover the distance

T = t_1 + t_2

T = 0.94 hours

Part b)

Average speed is given as

v_(avg) = (d)/(t)

v_(avg) = (5.00 miles)/(0.94)

v_(avg) = 5.32 mph

Part c)

Half the time Llya walks and next half the time she runs

so total distance is given as

d = v_1(T/2) + v_2(T/2)

so we have

5.00 = 8.90(T/2) + 3.80(T/2)

T = 0.79 h

Part d)

Average speed is given as

v_(avg) = (d)/(t)

v_(avg) = (5.00 miles)/(0.79)

v_(avg) = 6.35 mph

Which unit of measurement is included in the International System of Unit! (si)?

Answers

Answer:

See the explanation below

Explanation:

There are several measures for the international system of measures. Let's name some and their representation symbol.

meter = [m]

time = [s] = seconds

mass = [kg] = kilograms

Temperature = [°C] = celcius degrees

Power = [W] = watts.

Force = [N] = Newtons

Which best describes how geothermal energy is used to make electricity? A.
Rocks are split to release energy that drives a steam turbine attached to an electrical generator.
B.
Heat energy from below the ground converts water to steam to drive a steam turbine attached to an electrical generator.
C.
Heat energy from below the ground drives liquid water though a turbine attached to an electrical generator.
D.
Heat energy from below ground heats and pressurizes air that drives a turbine attached to an electrical generator.

Answers

Heat energy from below the ground converts water to steam to drive a steam turbine attached to an electrical generator