A 2.9-kg cart is rolling along a frictionless, horizontal track towards a 1.4-kg cart that is held initially at rest. The carts are loaded with strong magnets that cause them to attract one another. Thus, the speed of each cart increases. At a certain instant before the carts collide, the first cart's velocity is +3.9 m/s, and the second cart's velocity is -1.2 m/s. (a) What is the total momentum of the system of the two carts at this instant? (b) What was the velocity of the first cart when the second cart was still at rest?

Answers

Answer 1
Answer:

Answer:

9.63 kg m/s

3.32 m/s

Explanation:

m_1 = Mass of first cart = 2.9 kg

m_2 = Mass of second cart = 1.4 kg

v_1 = Velocity of first cart = 3.9 m/s

v_2 = Velocity of second cart = -1.2 m/s

Total momentum of the system

p=m_1v_1+m_2v_2\n\Rightarrow p=2.9* 3.9+1.4* -1.2\n\Rightarrow p=9.63\ kg m/s

The total momentum of the system is 9.63 kg m/s

Equating the same equation with v_2=0

p=m_1v_1+m_2v_2\n\Rightarrow v_1=(P-m_2v_2)/(m_1)\n\Rightarrow v_1=(9.63-1.4* 0)/(2.9)\n\Rightarrow v_1=3.32\ m/s

The velocity of the first cart when the second cart was still at rest is 3.32 m/s


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Forces of attraction limit the motion of particles most inA. a solid.
B. a liquid.
C. a gas.
D. both b and c

Answers

Answer:

Solids

Explanation:

Solids have definite shapes and definite volumes. The forces of attraction between the molecules of a solid substance are strong and the intermolecular spaces are very small. Due to this, the motion of molecules within a solid substance are very difficult that they only vibrate in their positions.

For liquids, they have definite volumes and indefinite shapes. The forces of attraction between the molecules of a liquid are intermediate and the the intermolecular spaces are intermediate as well. Due to this, the motion of molecules within a liquid substance is not as difficult as it is within solids.

Finally, for gases, they have indefinite shapes and indefinite volumes. The forces of attraction between the molecules of a gas are weak and the intermolecular spaces are large. Due to this, the motion of particles of gas is very easy.

Hope this helps :)

Final answer:

The forces of attraction limit the motion of particles most significantly in solids because particles in a solid are closely packed and have stronger forces of attraction, which hold them tightly in fixed positions.

Explanation:

The forces of attraction between particles limit motion most significantly in a solid (Option A). In a solid, particles are closely packed together and have the least amount of freedom to move, compared to particles in a liquid or gas. This is because the forces of attraction in a solid are very strong, holding particles tightly in fixed positions. In contrast, particles in liquids and gases have more freedom to move as the forces of attraction are weaker.

However, this does not mean that particles in a liquid or gas do not experience forces of attraction. They do, but the forces are weaker in comparison to solids, allowing for more movement. Hence, solids are the state of matter in which forces of attraction limit the motion of particles most.

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Which of the following shows the abbreviation for a unit of density? (a) lb/mL
(b) g/cm
(c) g/cm3
(d) L/kg

Answers

c) gram/centimeters^3

Answer:

g/ml

Explanation:

How much heat energy must be added to 52kg Of water at 68°F to raise the temperature to 212°F? The specific heat capacity for water is 4.186×10 to the third power J/kg times degrees Celsius

Answers

Answer:

The amount of energy added to rise the temperature Q = 17413.76 KJ

Explanation:

Mass of water = 52 kg

Initial temperature T_(1) = 68 °F = 20° c

Final temperature T_(2) = 212 °F = 100° c

Specific heat of water  C = 4.186 (KJ)/(kg c)

Now heat transfer Q = m × C × ( T_(2)  - T_(1) )

⇒ Q = 52 × 4.186 × ( 100 - 20 )

⇒ Q = 17413.76 KJ

This is the amount of energy added to rise the temperature.

How long will it take a car to accelerate from 15.2 to 23.5 m/s if the car has an average acceleration of 3.2 m/s?

Answers

It will take a car, 2.59 s to accelerate from 15.2 to 23.5 m/s.

What is Speed?

speed is described as. the pace at which an object's location changes in any direction. Speed is defined as the distance traveled divided by the travel time. Speed is a scalar quantity because it just has a direction and no magnitude.

Given, the car has an average acceleration of 3.2 m/s².

To solve this problem, we can use the following kinematic equation:

v = u +at

where:

v is the final velocity (23.5 m/s)

u is the initial velocity (15.2 m/s)

a is the acceleration (3.2 m/s^2)

t is the time

We can rearrange this equation to solve for t:

t = (v -u)/a

substituting the values we have:

t = (23.5 - 15.2 ) / 3.2

t = 2.59375 seconds

Therefore, it will take approximately 2.59 seconds for the car to accelerate from 15.2 m/s to 23.5 m/s with an average acceleration of 3.2 m/s².

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Hello!

How long will it take a car to accelerate from 15.2 m/s to 23.5 m/s if the car has an average acceleration of 3.2 m/s² ?

We have the following data:

Vf (final velocity) = 23.5 m/s

Vi (initial velocity) = 15.2 m/s

ΔV  (speed interval)  = Vf - Vi → ΔV  = 23.5 - 15.2 → ΔV  = 8.3 m/s

ΔT (time interval) = ? (in s)

a (average acceleration) = 3.2 m/s²

Formula:

a = \frac{\Delta{V}}{\Delta{T^}}

Solving:  

a = \frac{\Delta{V}}{\Delta{T^}}

3.2 = \frac{8.3}{\Delta{T^}}

\Delta{T^} = (8.3)/(3.2)

\Delta{T^} = 2.59375 \to \boxed{\boxed{\Delta{T^} \approx 2.6\:s}}\:\:\:\:\:\:\bf\green{\checkmark}

Answer:  

The car will take approximately 2.6 seconds to accelerate

____________________________________  

I Hope this helps, greetings ... Dexteright02! =)

A 10-meter long ramp has a mechanical advantage of 5. What is the height of the ramp?

Answers

1.       If the ramp has a length of 10 and has a mechanical advantage (MA) of 5. Then we need to find the height of the ramp.
Formula:
MA = L / H
Since we already have the mechanical advantage and length, this time we need to find the height .
MA 5 = 10 / h
h = 10 / 5
h = 2 meters

Therefore, the ramp has a length of 10 meters, a height of 2 meters with a mechanical advantage of 5.




Answer:

height=2

Explanation:

MA= input/output

MA= 5

input = 10 (the ramp)

output=x (the height)

5=10/x

x=2

How many electrons make up a charge of 3.5kC?

Answers

21.8452851 * 10^21 e. Which is 21.845.285.100.000.000.000.000 electrons. A lot.
Well now, I don't know !
Let's figure it out.

The charge on one electron is 1.60 x 10⁻¹⁹ Coulomb .

To get 3,500 Coulombs of charge, you'd need to
go around and collect

             (3,500) / (1.60 x 10⁻¹⁹)  electrons.

That's  2.19 x 10²²  of the little fellas.

That's a big number.  But what's REALLY amazing is the
mass and weight of that many electrons:

             Mass:    1.989 x 10⁻⁵ gram

             Weight:  about  0.0000007 ounce  !

That's not one electron.  That's the whole  2.19 x 10²²  uvvum
that it takes to hold 3,500 Coulombs of charge.