The balanced combustion reaction for C 6 H 6 C6H6 is 2 C 6 H 6 ( l ) + 15 O 2 ( g ) ⟶ 12 CO 2 ( g ) + 6 H 2 O ( l ) + 6542 kJ 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If 7.300 g C 6 H 6 7.300 g C6H6 is burned and the heat produced from the burning is added to 5691 g 5691 g of water at 21 ∘ 21 ∘ C, what is the final temperature of the water?

Answers

Answer 1

Answer:

Answer: The final temperature of the water is $33.85^(o)C$ .

Explanation:

We know that molar mass of $C_(6)H_(6)$ is 78 g/mol. And, the amount of heat produced when 2 mol of $C_(2)H_(6)$ burns is 6542 KJ.

This means that,

$78 * 2$ = 156 g of $C_(2)H_(6)$ burns, heat produced is 6542 kJ.

Therefore, heat produced (Q) by burning 7.3 g of $C_(6)H_(6)$ is as follows.

$(6542 * 7.3 g)/(156 g)$

= 306.13 kJ

or, = 306130 J (as 1 KJ = 1000 J)

For water, mass is given as 5691 g and specific heat capacity of water is 4.186 $J/g^(o)C$ .

So, we will calculate the value of final temperature as follows.

Q = $m * C * (T_(f) - T_(i))$

306130 J = $5691 g * 4.186 J/g^(o)C * (T_(f) - 21)^(o)C$

$(T_(f) - 21)^(o)C = (306130 J)/(23822.53 J/^(o)C)$

$T_(f)$ = 12.85 + 21

= $33.85^(o)C$

Thus, we can conclude that the final temperature of the water is $33.85^(o)C$ .

Related Questions

(ASAP) (FOOD SCIENCE) how does the addition of starches provide structure to a food product
How many milliliters of a 70.0 ml solution of 1.51 m bacl2 must be used to make 12.0 ml of a solution that has a concentration of 0.300 m cl–?
Which of the following shows the combustion of a hydrocarbon?A. 2C2H2 +502 + 4CO2 + 2H20O B. CO2 + H2O → H2CO3O C. NaOH + HCl → NaCl + H20O D. C2H4 + Cl2 → C2H4Cl2
What is the difference between a volume that is delivered and a volume that is contained?
Name the physical properties used in seperating kerosene and petrol

How many sulfide ions are in 15 dg of sodium sulfide?O 1.16 x 1022
O 3.04 x 1028
O 5.76 x 1029
O 6.02 x 1023
O 3.13

Answers

There are 5.78 × 10^20 sulfide ions in sodium sulfide

The formula of the compound is Na2S. The molar mass of the compound is calculated as follows; 2(23) +32 = 46 + 32 = 78 g/mol

Number of moles of Na2S = 0.15 g/ 78 g/mol = 0.0019 moles

Since there is 1 mole of Na^+ and 2 moles of S^2- in Na2S, the number of S^2- ions in 0.19 moles of Na2S is 0.00096 moles of S^2-.

If 1 mole of S^2- contains 6.02 × 10^23

0.095 moles of S^2- contains 0.00096 moles × 6.02 × 10^23/ 1 mole

= 5.78 × 10^20 sulfide ions

Learn more: brainly.com/question/1309057

What mass of CO2 (in kilograms) does the combustion of a 16-gallon tank of gasoline release into the atmosphere? Assume the gasoline is pure octane (C8H18) and that it has a density of 0.70 g/mL.Express your answer in kilograms to two significant figures.

Answers

Mass of CO₂ = 1.3 x 10⁵ kg

Further explanation

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

2C₈H₁₈ + 25O₂⇒ 16CO₂ + 18H₂O

16 gallon = 60566,6 ml

mass C₈H₁₈ :

$\tt mass=\rho* V\n\nmass=0.7* 60566.6=42396.62~g$

mol C₈H₁₈ :

$\tt MW=114.232~g/mol\n\nmol=(42396.62)/(114.232)=371.145$

mol CO₂ :

$\tt (16)/(2)* 371.145=2969.159$

mass CO₂ :

$\tt =2969.159* 44(MW~CO_2)=130642.996~g=1.3* 10^5~kg$

How many moles of atoms are in 9.00 g of 13c?

Answers

0.629 moles will be present in moles of atoms are in 9.00 g of 13 carbon atom.

What is a mole?

One mole of any substance is the amount of the substance which contain 6.023 × 10²³ atoms or molecule if the substance is atomic or molecular in nature and known as gram atomic mass.

Number of atoms in carbon is 9.00 grams and isotope are 13C,

Number of moles = weight of substance / mass of substance

Substituting the value in formula,

Number of moles = 9.00 grams / 13

Number of moles = 0.629 moles

Therefore, 0.629 moles will be present in moles of atoms are in 9.00 g of 13 carbon atom.

Learn more about moles, here:

brainly.com/question/26416088

#SPJ2

The atomic weight of 13C should be pretty close to 13.0. (If you have the exact mass, use it in the problem.) So, 9.00 g / 13.0 g/mol = 0.692 moles Therefore, the answer should be 0.692 moles are in 9.00 g of 13C.

A system absorbs 12 J of heat from the surroundings; meanwhile, 28 J of work is done on the system. What is the change of the internal energy ΔEth of the system?

Answers

Answer: The value of change in internal energy of the system is, 40 J.

Explanation : Given,

Heat absorb from the surroundings = 12 J

Work done on the system = 28 J

First law of thermodynamic : It is a law of conservation of energy in which the total mass and the energy of an isolated system remains constant.

As per first law of thermodynamic,

$\Delta U=q+w$

where,

$\Delta U$ = internal energy = ?

q = heat absorb from the surroundings

w = work done on the system

Now put all the given values in this formula, we get the change in internal energy of the system.

$\Delta U=12J+28J$

$\Delta U=40J$

Therefore, the value of change in internal energy of the system is, 40J.

What is the molarity of a solution that contains 30 grams of naoh in 500 milliliters of solution?

Answers

Molar mass NaOH = 39.997 g/mol

number of moles solute:

n = mass of solute / molar mass

n = 30 / 39.997

n = 0.00075 moles of NaOH

Volume in liters:

500 mL / 1000 => 0.5 L

Therefore :

M = moles of solute / volume ( L )

M = 0.00075 / 0.5

M = 0.0015 mol/L

Answer: 1.5 M

Explanation:

Calculate the electric double layer thickness of a alumina colloid in a dilute (0.1 mol/dm3) CsCI electrolyte solution at 30 °C. How are these numbers affected by the addition of 0.1 mol/dm3 of KCL? At what distance from the particle surface (r) has the potential decayed to 1% of its initial value?