Which of the following chemicals is potentially dangerous?A. ammonium nitrate

B. ethyl alcohol

C.sulfuric acid

D.All chemicals are potentially dangerous

Answers

Answer 1
Answer:

Answer:

D.All chemicals are potentially dangerous

Explanation:

No chemical is toxicologically neutral


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How do the chemical reactions in this lab activity compare to nuclear reactions, such as fission and fusion?

Answers

The chemical reaction has been the low energy reaction containing electrons rearrangement, while nuclear reactions have been the higher energy reactions with change in nuclei.

What are nuclear reactions ?

The term nuclear reactions is defined as when there has been the including the change in the nuclei of the atom. However, the reaction has been known as the chemical reaction when the change has been processed in the electrons with the rearrangement.

The nuclear reactions have made up of a more amount of energy to be liberated, while the amount of energy included in the chemical reaction has been smaller.

Thus, the chemical reaction has been the low energy reaction including electrons rearrangement, while nuclear reactions have been the high energy reactions with change in nuclei.

For more information about the nuclear reactions, refer to the link:

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Nuclear energy released in nuclear fission and fusion is much larger than chemical reactions because of the astonishing amounts of energy being released at one moment.

1.81 g H2 is allowed to react with 10.2 g N2, producing 2.19 g NH3.What is the theoretical yield in grams for this reaction under the given conditions?3H2(g)+N2(g)→2NH3(g)

Answers

The theoretical yield : = 10.251 g

Further explanation

Given

Reaction

3H₂(g)+N₂(g)→2NH₃(g)

1.81 g H₂

10.2 g N₂

2.19 g NH₃

Required

The theoretical yield

Solution

Find limiting reactant :

H₂ : 1.81 g : 2 g/mol = 0.905 mol

N₂ : 10.2 g : 28 g/mol = 0.364 mol

mol : coefficient

H₂ = 0.905 : 3 = 0.302

N₂ = 0.364 : 1 = 0.364

H₂ as a limiting reactant(smaller ratio)

Moles NH₃ based on H₂, so mol NH₃ :

= 2/3 x mol H₂

= 2/3 x 0.905

=0.603

Mass NH₃ :

= mol x MW

=0.603 x 17 g/mol

= 10.251 g

What reaction conditions most effectively conver a cabocxylic acid to a methly ester?

Answers

Answer:

Esterification reaction

Explanation:

When we have to go from an acid to an ester we can use the esterification reaction. On this reaction, an alcohol reacts with a carboxylic acid on acid medium to produce an ester and water. (See figure).  

In this case, we need the methyl ester, therefore we have to choose the appropriate alcohol, so we have to use the methanol as reactive if we have to produce the methyl ester.

A buffer solution is 0.413 M in HF and 0.237 M in KF. If Ka for HF is 7.2×10-4, what is the pH of this buffer solution?

Answers

Answer:

2.90

Explanation:

Any buffer system can be described with the reaction:

HA~->~H^+~+~A^-

Where HA is the acid and A^- is the base. Additionally, the calculation of the pH of any buffer system can be made with the Henderson-Hasselbach equation:

pH=pKa~+~Log([A^-])/([HA])

With all this in mind, we can write the reaction for our buffer system:

HF~->~H^+~+~F^-

In this case, the acid is HF with a concentration of 0.413 M and the base is F^- with a concentration of 0.237 M. We can calculate the pKa value if we do the "-Log Ka", so:

pKa~=~-Log(7.2X10^-^4)=~3.14

Now, we can plug the values into the Henderson-Hasselbach

pH=~3.14~+~Log(([0.237~M])/([0.413~M]))~=~2.90

The pH value would be 2.90

I hope it helps!

What factors govern the position of an IR absorption peak? Select one or more correct answers.(A) strength of the bond
(B) effect of a magnetic field on nucleus spin
(C) masses of the atoms involved in the bond
(D) the type of vibration being observed

Answers

Answer:

The factors that govern the position of an IR absorption peak are:

(A) strength of the bond

(C) masses of the atoms involved in the bond

(D) the type of vibration being observed

Explanation:

In infrared spectroscopy the molecules absorb the frequencies that are characteristic of their structure. These absorptions occur at resonance frequencies, that is, the frequency of the absorbed radiation coincides with the frequency of vibration. The energies are affected by the shape of molecular potential energy surfaces, the masses of atoms and the associated vibronic coupling. The resonance frequencies are also related to the strength of the bond and the mass of the atoms at each end of it. Therefore, the frequency of vibrations is associated with a particular normal movement mode and a particular type of link.

Which of the following reactions would have the smallest value of K at 298 K? Which of the following reactions would have the smallest value of K at 298 K? A + B → 2 C; E°cell = -0.030 V A + 2 B → C; E°cell = +0.98 V A + B → C; E°cell = +1.22 V A + B → 3 C; E°cell = +0.15 V More information is needed to determine.

Answers

The reactions that would have the smallest value of K is

A + B → 2 C; E°cell = -0.030 V

Option A

Generally the equation for the number of electrons transferred  is mathematically given as

nFE^o_(cell)=RT\ln K

where

T= Temperature

F=25C(298K)

R = Gas constant

R= 8.314 J/K.mol

F = Faraday's constant

F= 96500 C

We see from the equation that the E-cell is directly proportional to K(equilibrium constant of the reaction)

Hence, The reactions that would have the smallest value of K is

A + B → 2 C; E°cell = -0.030 V

For more information on Reaction

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Answer:

The reaction with smallest value of K is :

A + B → 2 C; E°cell = -0.030 V

Explanation:

nFE^o_(cell)=RT\ln K

where :

n = number of electrons transferred

F = Faraday's constant = 96500 C

E^o_(cell) = standard electrode potential of the cell

R = Gas constant = 8.314 J/K.mol

T = temperature of the reaction = 25^oC=[273+25]=298K

K = equilibrium constant of the reaction

As we cans see, that standard electrode potential of the cell is directly linked to the equilibrium constant of the reaction.

  • Higher E^o_(cell) higher will be the value of K.
  • Lower E^o_(cell) lower will be the value of K.

So, the reaction with smallest value of electrode potential will have smallest value of equilibrium constant. And that reaction is:

A + B → 2 C; E^o_(cell) =-0.030 V