Study the image. Which image best describes what the arrows represent?

Answers

Answer 1

Answer: i’m pretty sure it’s d, please let me know !

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Object A has a molar heat of 31.2 J/mole∙°C and object B molar heat is 11.2 J/mole∙°C. Which object will heat up faster if they have the same mass and equal amount of heat is applied? Explain why.

Answers

Answer:

Substance B

Explanation:

Molar heat of A = 31.2J/mole.°C

Molar heat of B = 11.2 J/mole∙°C.

The molar heat of a substance is the amount of heat that must be added to a mole of a substance to raise the temperature by 1°C.

Substance B will heat up faster compared to A.
It has a smaller molar heat compared to A.
This suggests that it will require lesser heat to raise its temperature by 1°C.

Question 51 pts A breathalyzer is a device used to estimate the blood alcohol content of a suspected drunk driver by measuring the amount of alcohol in one's breath. The fuel cell breathalyzer employs the reaction below: CH3CH2OH(g)+O2(g)→HC2H3O2(g)+H2O(g) When a suspected drunk driver blows his or her breath through the fuel-cell breathalyzer, the device measures the current produced by the reaction and calculates the percent alcohol in the breath. How many moles of electrons are transferred per mole of ethanol, CH3CH2OH, in the reaction?

Answers

Answer:

Four moles of electrons

Explanation:

The reactions in a breathalyzer are redox reactions. Fuel cell breathalyzers consists of fuel cells with platinum electrodes. The current produced depends on the amount of alcohol in the breath. Detection of alcohol involves the oxidation of ethanol to ethanoic acid. The two half cells set in the process are;

Anode;

C2H5OH(aq) + 4OH^-(aq) ----------> CH3COOOH(aq) + 3H2O(l) + 4e

Cathode;

O2(g) + 2H2O(l) +4e--------> 4OH^-(aq)

Hence four electrons are transferred in the process.

Compound X has the formula C8H14.X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethylcyclohexane. Treatment of X with ozone follwed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O). What is the structure of X?

Answers

Answer:

Compound X has the formula C8H14.

X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethyl cyclohexane. Treatment of X with ozone followed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O). What is the structure of X?

Explanation:

The degree of unsaturation in the given molecule C8H14 is:

DU=(Cn+1)-Hn/2-Xn/2+Nn/2

where,

Cn=number of carbon atoms

Hn=number of hydrogen atoms

Xn=number of halogen atoms

Nn=number of nitrogen atoms

C8H14:

DU=(8+1)-14/2

=>DU=9-7 =2

Hence, the given molecule will have either two double bonds or one double bond and one ring or two rings.

X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethylcyclohexane.

This indicates that the molecule X has one double bond and one ring that is cyclohexane ring.

Treatment of X with ozone follwed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O).

So, the molecule has a ring and double bond CH2.

Based on the given data the structure of compound X is shown below:

The reaction sequence is shown below:

Final answer:

Compound X, with the formula C8H14, reacts with hydrogen to form 1,2-dimethylcyclohexane. When treated with ozone and zinc, it yields a ketone and formaldehyde. Therefore, the structure of X is 1,2-dimethylcyclohexane.

Explanation:

X is a compound with the formula C8H14. The reaction of X with hydrogen in the presence of a palladium catalyst produces a mixture of cis- and trans-1,2-dimethylcyclohexane. When X is treated with ozone followed by zinc in aqueous acid, it forms a ketone and formaldehyde (CH2=O).

This information tells us that compound X is a cycloalkane with two methyl groups. Since it reacts with hydrogen to form 1,2-dimethylcyclohexane, we know that X must have a cyclohexane ring with two methyl groups at the 1 and 2 positions. The cis and trans isomers of 1,2-dimethylcyclohexane have different arrangements of the methyl groups relative to each other.

Thus, the structure of compound X is 1,2-dimethylcyclohexane.

Learn more about Structure of Compound X here:

brainly.com/question/32678153

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What is the mass in grams of 1.9×1023 atoms of lead?

Answers

Answer:

Explanation:

# moles that exist in 1.9 X 10 23 =

= # of atoms/# of Avogadro 's num

= 1.9 X 10 23 / 6.02x10 23

= 0.266 mole of Pb

now we calculate the mass

mass of lead = # mol x m.wt

= 0.266 X 106.4

= 28.30 gram

Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it is used to make the refrigerant carbon tetrafluoride, CF4 via the reaction 2COF2(g)⇌CO2(g)+CF4(g), Kc=4.90 If only COF2 is present initially at a concentration of 2.00 M, what concentration of COF2 remains at equilibrium?

Answers

Answer : The concentration of $COF_2$ remains at equilibrium will be, 0.37 M

Explanation : Given,

Equilibrium constant = 4.90

Initial concentration of $COF_2$ = 2.00 M

The balanced equilibrium reaction is,

$2COF_2(g)\rightleftharpoons CO_2(g)+CF_4(g)$

Initial conc. 2 M 0 0

At eqm. (2-2x) M x M x M

The expression of equilibrium constant for the reaction will be:

$K_c=([CO_2][CF_4])/([COF_2]^2)$

Now put all the values in this expression, we get :

$4.90=((x)* (x))/((2-2x)^2)$

By solving the term 'x' by quadratic equation, we get two value of 'x'.

$x=1.291M\text{ and }0.815M$

Now put the values of 'x' in concentration of $COF_2$ remains at equilibrium.

Concentration of $COF_2$ remains at equilibrium = $(2-2x)M=[2-2(1.219)]M=-0.582M$

Concentration of $COF_2$ remains at equilibrium = $(2-2x)M=[2-2(0.815)]M=0.37M$

From this we conclude that, the amount of substance can not be negative at equilibrium. So, the value of 'x' which is equal to 1.291 M is not considered.

Therefore, the concentration of $COF_2$ remains at equilibrium will be, 0.37 M

A solution is made by dissolving37.5g of sodium sulfide (Na2S) in

217g of water.

What is the molality of the solution?

Answers

Answer:

THE MOLARITY IS 2.22 MOL/DM3

Explanation:

The solution formed was as a result of dissolving 37.5 g of Na2S in 217 g of water

Relative molecular mass of Na2S = ( 23* 2 + 32) = 78 g/mol

Molarity in g/dm3 is the amount of the substance dissolved in 1000 g or 1 L of the solvent. So we have;

37.5 g of Na2S = 217 g of water

( 37.5 * 1000 / 217 ) g = 1000 g of water

So, 172.81 g/dm3 of the solution

So therefore, molarity in mol/dm3 = mol in g/dm3 / molar mass

Molarity = 172.81 g/dm3 / 78 g/mol

Molarity = 2.22 mol/dm3

The molarity of the solution is 2.22 mol/dm3

Answer:

The answer is 2.22mol

Explanation:

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