Practice the Skill 21.15b When the following ketone is treated with aqueous sodium hydroxide, the aldol product is obtained in poor yields. In these cases, special distillation techniques are used to increase the yield of aldol product. Predict the aldol addition product that is obtained, and propose a mechanism for its formation. For the mechanism, draw the curved arrows as needed. Include lone pairs and charges in your answer. Do not draw out any hydrogen explicitly in your products. Do not use abbreviations such as Me or Ph.
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Answer:
Check the explanation
Explanation:
Kindly check the attached image below for the step by step explanation to the question above.
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In compliance with conservation of energy, Einstein explained that in the photoelectric effect, the energy of a photon (hv) absorbed by a metal is the sum of the work function (Φ), the minimum energy needed to dislodge an electron from the metal’s surface, and the kinetic energy (Ek) of the electron: hv = Φ + Ek. When light of wavelength 358.1 nm falls on the surface of potassium metal, the speed (u) of the dislodged electron is 6.40 x 10⁵ m7s. (a) What is Ek (½mu²) of the dislodged electron? (b) What is Φ (in J) of potassium?
Consider the titration of a 73.9 mL sample of 0.13 M HC2H3O2 with 6.978 M NaOH. Ka(HC2H3O2) = 1.8x10-5 Determine the initial pH before any NaOH is added. Express your answer using two decimal places.Consider the titration of a 46.6 mL sample of 0.078 M HC2H3O2 with 1.135 M NaOH. Ka(HC2H3O2) = 1.8x10-5 Determine the volume of added base required to reach the equivalence point. Answer in units of milliliters.Consider the titration of a 17.2 mL sample of 0.128 M HC2H3O2 with 0.155 M NaOH. Ka(HC2H3O2) = 1.8x10-5 Determine the pH at 0.46 mL of added base.
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Answer:
use google and use the first link
Explanation:
Final answer:
Treatment of (S)-( )-5-methyl-2-cyclohexenone with lithium dimethylcuprate followed by protonolysis produces dextrorotatory ketone A and a trace of isomer B. Compound A can yield optically active, dextrorotatory hydrocarbon C when treated with zinc amalgam and HCl.
Explanation:
Treatment of (S)-( )-5-methyl-2-cyclohexenone with lithium dimethylcuprate followed by protonolysis yields a mixture containing primarily a dextrorotatory ketone A and a trace of an optically inactive isomer B. Compound A can be treated with zinc amalgam and HCl to produce an optically active, dextrorotatory hydrocarbon C.
To provide a specific identification and stereochemical configuration of compounds A, B, and C, I would need additional information or further context about the starting components and reaction conditions, as well as any other relevant data or observations.
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highland
it is actually science on the subject but it doesn't have that option.
marine west coast
Mediterranean
subarctic
tropical wet-dry
Answers
Marine west coast and Mediterranean are the types of temperate climates, due to the dispersion of precipitation throughout the year, temperate marine climates are typically distinguished by a notable lack of dry season, hence options D and E are correct.
What is temperate climates?
Temperate climates are regions with moderate annual or seasonal rainfall, intermittent drought, mild to warm summers, and cool to cold winters.
Humid subtropical, marine west coast, Mediterranean are the phrases that clearly identified with temperate marine climates.
Geographically speaking, the moderate climates of Earth are found in the middle latitudes, which are halfway between the tropics and the poles.
Therefore, options D and E are correct.
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Answer:
Humid Continental
Marine west coast
Mediterranean
subarctic
Explanation:
just did assignment on edge
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polar amino acids: serine, threonine, cysteine, asparagine, glutamine
positively charged (basic) amino acids: lysine, arginine, histidine
negatively charged (acidic) amino acids: aspartic acid, glutamic acid
1) K+ and H+ and PO43-
6
2) K 2+ H+, and PO43-
9
3) K+, H+, p3-, and O2-
4) K2H3+ and PO43-
5) K2HPO4 is not ionic.
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Answer:
K⁺ and HPO₄²⁻ ions are present in K₂HPO₄
Explanation:
K₂HPO₄ consist of anion and cation such as HPO₄²⁻ and K⁺. We can see that the charge on HPO₄²⁻ is negative 2. Thus inroder to balance the charge and to neutral the compound two potassium ions are attached because the charge on one atom of potassium is K⁺.
Properties of K₂HPO₄ :
It is salt of phosphoric acid.
Its density is 2.44 g/cm³.
It is odourless compound.
It is white powder and soluble in water.
It is used in fertilizer because it provide phosphorus which is beneficial for the growth of plants.
It is also used as a additive in food.
It is inorganic compound and also used as buffering agent.
Final answer:
The correct ions present in K2HPO4 are K+, H+, and PO43-. Here, potassium (K+) ions, hydrogen (H+) ion and phosphate (PO43-) ion are released.
Explanation:
The compound K2HPO4 dissociates in water to form ions. The correct answer from your selection would be the first one. When K2HPO4 is added to water, it dissociates into its ions 'K+' (Potassium), 'H+' (Hydrogen) and 'PO43-' (Phosphate). So, the ions present in K2HPO4 are K+, H+ and PO43-. Please note that K2HPO4 is also called dipotassium hydrogen phosphate.
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Answer:
a molecule is the smallest particle in a chemical element or compound that has the chemical properties of that element or compound. Molecules are made up of atoms that are held together by chemical bonds. These bonds form as a result of the sharing or exchange of electrons among atoms
Answer:
: A molecule is the smallest particle in a chemical element or compound that has the chemical properties of that element or compound. Molecules are made up of atoms that are held together by chemical bonds. These bonds form as a result of the sharing or exchange of electrons among atoms.
Explanation:
i hope its right
Answers
Answer:- .
Explanation:- Atomic number for fluorine(F) is 9 and it's electron configuration is .
is formed when F loses one electron from it's valence shell.
Second shell is the valence shell for fluorine and so it loses one electron from 2p to form and the electron configuration of the ion becomes
.
Final answer:
The ground state electron configuration of F+ is 1s²2s²2p⁴, which is derived from the neutral Fluorine's configuration 1s²2s²2p⁵ by removing one electron from the outermost 2p orbital.
Explanation:
The question asked for the full ground state electron configuration of F+. The neutral Fluorine atom (F) has 9 electrons. Its electron configuration is: 1s²2s²2p⁵. When Fluorine loses one electron it becomes a positively charged ion (F+), so its electron configuration will be: 1s²2s²2p⁴. This is because the electron is removed from the outermost shell, specifically the 2p orbital. This ground-state electron configuration refers to the most stable arrangement of electrons around the nucleus.
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