True or false: The jet stream carries cold air to the tropics and warm air to the poles

Answers

Answer 1

Answer:

False. The jet stream does not carry cold air to the tropics and warm air to the poles.

What is the jet stream at high altitude?

The jet stream is a high-altitude, fast-moving air current in the atmosphere that generally flows from west to east. It is caused by the temperature differences between the polar regions and the mid-latitudes.

In reality, the jet stream tends to separate cold polar air from warmer air in the mid-latitudes. It meanders and can have a significant impact on weather patterns, but its primary function is not to transport warm or cold air to the poles or tropics. Instead, it plays a crucial role in the development and movement of weather systems, affecting things like storm tracks and weather conditions in different regions.

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Answer 2

Answer:

Final answer:

The jet stream does not carry cold air to the tropics or warm air to the poles.

Explanation:

The statement 'The jet stream carries cold air to the tropics and warm air to the poles' is false. The jet stream is a narrow band of strong wind in the upper atmosphere that flows from west to east. It generally moves air masses from west to east across the globe, but it does not carry cold air to the tropics or warm air to the poles. Instead, it helps distribute weather systems and influences the movement of storms.

Learn more about jet stream here:

brainly.com/question/861519

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The noble gases are the least what of any elements on the periodic table

Answers

The noble gases are the least reactive elements.

What is the mass of a large dog that weighs 441 newtons

Answers

Weight, w = mg. g ≈ 9.8 m/s². m = mass in kg. w is weight in N

441 N = m* 9.8

9.8m = 441

m = 441/9.8

m = 45 kg.

Mass of the dog is = 45 kg

What is a Nuclei of uranium atoms split apart

Answers

This is probably referring to the process of nuclear fission.

What is the momentum of a 12,000 kg car moving at a speed of 40 m/s?

Answers

Momentum = (mass) x (speed)

Momentum = (12,000 kg) x (40 m/s)

Momentum = (12,000 x 40) kg-m/s

Momentum = 480,000 kg-m/s

Which of the following is an example of mattera.leaves
b.shadow
c.light from the sun
d.sound

which of the following is an example of chemical property to matter
a.ability to melt
b.ability to break
c.ability to react
d.ability to freeze

Answers

for the first one, leaves is matter.
for the second one, ability to react
hope this helps

the answers are a and c

A student that jumps a vertical height of 50 cm during the hang time activity.a. What is the hang time of the student?
b. What speed must the student leave the ground with to reach that height?

Answers

The hang time of the student is 0.64 seconds, and he must leave the ground with a speed of 3.13 m/s

Why?

To solve the problem, we must consider the vertical height reached by the student as max height.

We can use the following equations to solve the problem:

Initial speed calculations:

$v_(f)^(2)=v_(o)^(2)+2*a*d$

At max height, the speed tends to zero.

So, calculating, we have:

$v_(f)^(2)=v_(o)^(2)+2*a*d\n\n0=v_(o)^(2)+2*(-9.81(m)/(s^(2)))*0.5m\n\nv_(o)^(2)=9.81(m^(2) )/(s^(2))\n\nv_(o)=\sqrt{9.81(m^(2) )/(s^(2))}=3.13(m)/(s)$

Hang time calculations:

We must remember that the total hang time is equal to the time going up plus the time going down, and both of them are equal,so, calculating the time going down, we have have:

$y-yo=vo.t+(1)/(2)*9.81(m)/(s^(2))*t^(2) \n\n0.5m-0=0*t+4.95*t^(2)\n\nt^(2)=(0.5)/(4.95)\n\nt=√(0.101)=0.318s$

Then, for the total hang time, we have:

$TotalHangTime=2*0.318seconds=0.64seconds$

Have a nice day!

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