Answer:
The function of the Deaerator is to remove dissolved non-condensable gases and to heat boiler feed water.
Explanation:
Answer:
Volume of aeration tank = 1.29 x 10^4 m³
Explanation:
Food/Micro- organism Ratio = 0.2/day
Feed Rate (Q) = 0.438 m³/s
Influent BOD = 150 mg/L
MLVSS = 2200 mg/L
The above mentioned parameters are related by the equation
F/M = QS₀/VX
where S₀ is the influent BOD and X is the cell concentration, with V being the Volume of the tank. Re- arranging the above equation for V and putting the values in, we get
V = 0.4380 x 150/0.2 x 2200
V = 0.1493 (m³/s) x day
V = 0.1493 x 24 x 60 x 60
V = 1.29 x 10^4 m³
Answer:
Explanation:
Given that,
Average fiber diameter is 0.01mm
d = 0.01mm = 1 × 10^-5m
The average fiber length is 2.5mm
L = 2.5mm = 0.0025m
Volume of the fraction of fibers is 0.40
Vf = 0.40
Fiber matrix bond strengths is 75MPa
τ = 75 MPa
The fraction strength of the fibers is 3500 Mpa
σf = 3500 MPa
The matrix street fiber is 8 MPa
σm = 8 MPa
We need to find the critical fiber length and compare it to original fiber length
Ic = σf•d / 2τ
Ic = 3500 × 0.01 / 75 × 2
Ic = 0.233 mm
Since the critical fiber length of 0.233 mm is much less than the provided length of the fiber (2.5mm) , so we can use the following equation to find the longitudinal tensile strength
σcd = σf•Vf(1—Ic / 2L) + σm(1—Vf)
σcd = 3500×0.4[1—0.233/(2 × 2.5)] + 8(1—0.4)
σcd = 1400(1—0.0467) + (8 × 0.6)
σcd = 1334.67 + 4.8
σcd = 1339.47 MPa
The longitudinal tensile strength of the aligned glass fiber-epoxy matrix composite is 1339.47 MPa
Answer:
The power input, in kW is -86.396 kW
Explanation:
Given;
initial pressure, P₁ = 1.05 bar
final pressure, P₂ = 12 bar
initial temperature, T₁ = 300 K
final temperature, T₂ = 400 K
Heat transfer, Q = 6.5 kW
volumetric flow rate, V = 39 m³/min = 0.65 m³/s
mass of air, m = 28.97 kg/mol
gas constant, R = 8.314 kJ/mol.k
R' = R/m
R' = 8.314 /28.97 = 0.28699 kJ/kg.K
Step 1:
Determine the specific volume:
p₁v₁ = RT₁
Step 2:
determine the mass flow rate; m' = V / v₁
mass flow rate, m' = 0.65 / 0.81997
mass flow rate, m' = 0.7927 kg/s
Step 3:
using steam table, we determine enthalpy change;
h₁ at T₁ = 300.19 kJ /kg
h₂ at T₂ = 400.98 kJ/kg
Δh = h₂ - h₁
Δh = 400.98 - 300.19
Δh = 100.79 kJ/kg
step 4:
determine work input;
W = Q - mΔh
Where;
Q is heat transfer = - 6.5 kW, because heat is lost to surrounding
W = (-6.5) - (0.7927 x 100.79)
W = -6.5 -79.896
W = -86.396 kW
Therefore, the power input, in kW is -86.396 kW
Kim is working on the cost estimate. The stage of a construction plan is Kim working on now is schematic design. The correct option is B.
A schematic design is an outline of a house or a building or another construction thing. The schematic design makes the outline map of the exterior or interior of the building. It is the foremost phase of designing something.
The design expert discusses the project three-dimensionally at this point in the process. To define the character of the finished project and an ideal fulfillment of the project program, a variety of potential design concepts are investigated.
The schematic design consists of a rough sketch with markings and measurements.
Therefore, the correct option is B. schematic design.
To learn more about schematic design, refer to the link:
#SPJ5
Answer:
B. schematic design
Explanation:
This correct for Plato/edmentum
Answer: This is EASY!
Explanation:
To make it easy, you would convert those binary numbers and to denary. And this gives:
84 104 105 115 32 105 115 32 69 65 83 89 33
Then, the denary numbers generated can be converted to ASCII code using this ASCII Table in the attachment below. And the result is: This is EASY!
Answer:
The code is attached.
Explanation:
I created a string s including 6 colors with spaces in between. Then I converted the string into a list x by using split() method. I used three different methods for removing elements from the list. These methods are remove(), pop() and del.
Then I used methods append(), insert() and extend() for adding elements to the list.
Finally I converted list into a string using join() and adding space in between the elements of the list.