A cylindrical specimen of cold-worked steel has a Brinell hardness of 250.(a) Estimate its ductility in percent elongation.(b) If the specimen remained cylindrical during deformation and its original radius was 5 mm (0.20 in.), determine its radius after deformation.

Answers

Answer 1
Answer:

Answer:

A) Ductility = 11% EL

B) Radius after deformation = 4.27 mm

Explanation:

A) From equations in steel test,

Tensile Strength (Ts) = 3.45 x HB

Where HB is brinell hardness;

Thus, Ts = 3.45 x 250 = 862MPa

From image 1 attached below, for steel at Tensile strength of 862 MPa, %CW = 27%.

Also, from image 2,at CW of 27%,

Ductility is approximately, 11% EL

B) Now we know that formula for %CW is;

%CW = (Ao - Ad)/(Ao)

Where Ao is area with initial radius and Ad is area deformation.

Thus;

%CW = [[π(ro)² - π(rd)²] /π(ro)²] x 100

%CW = [1 - (rd)²/(ro)²]

1 - (%CW/100) = (rd)²/(ro)²

So;

(rd)²[1 - (%CW/100)] = (ro)²

So putting the values as gotten initially ;

(ro)² = 5²([1 - (27/100)]

(ro)² = 25 - 6.75

(ro) ² = 18.25

ro = √18.25

So ro = 4.27 mm


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IN JAVA,Knapsack Problem

The file KnapsackData1.txt and KnapsackData2.txt are sample input files

for the following Knapsack Problem that you will solve.

KnapsackData1.txt contains a list of four prospective projects for the upcoming year for a particular

company:

Project0 6 30

Project1 3 14

Project2 4 16

Project3 2 9

Each line in the file provides three pieces of information:

1) String: The name of the project;

2) Integer: The amount of employee labor that will be demanded by the project, measured in work weeks;

3) Integer: The net profit that the company can expect from engaging in the project, measured in thousands

of dollars.

Your task is to write a program that:

1) Prompts the user for the number of work weeks available (integer);

2) Prompts the user for the name of the input file (string);

3) Prompts the user for the name of the output file (string);

4) Reads the available projects from the input file;

5) Dolves the corresponding knapsack problem, without repetition of items; and

6) Writes to the output file a summary of the results, including the expected profit and a list of the best

projects for the company to undertake.

Here is a sample session with the program:

Enter the number of available employee work weeks: 10

Enter the name of input file: KnapsackData1.txt

Enter the name of output file: Output1.txt

Number of projects = 4

Done

For the above example, here is the output that should be written to Output1.txt:

Number of projects available: 4

Available employee work weeks: 10

Number of projects chosen: 2

Number of projectsTotal profit: 46

Project0 6 30

Project2 4 16

The file KnapsackData2.txt, contains one thousand prospective projects. Your program should also be able to handle this larger problem as well. The corresponding output file,

WardOutput2.txt, is below.

With a thousand prospective projects to consider, it will be impossible for your program to finish in a

reasonable amount of time if it uses a "brute-force search" that explicitly considers every possible

combination of projects. You are required to use a dynamic programming approach to this problem.

WardOutput2.txt:

Number of projects available: 1000

Available employee work weeks: 100

Number of projects chosen: 66

Total profit: 16096

Project15 2 236

Project73 3 397

Project90 2 302

Project114 1 139

Project117 1 158

Project153 3 354

Project161 2 344

Project181 1 140

Project211 1 191

Project213 2 268

Project214 2 386

Project254 1 170

Project257 4 427

Project274 1 148

Project275 1 212

Project281 2 414

Project290 1 215

Project306 2 455

Project334 3 339

Project346 2 215

Project356 3 337

Project363 1 159

Project377 1 105

Project389 1 142

Project397 1 321

Project399 1 351

Project407 3 340

Project414 1 266

Project431 1 114

Project435 3 382

Project446 1 139

Project452 1 127

Project456 1 229

Project461 1 319

Project478 1 158

Project482 2 273

Project492 1 142

Project525 1 144

Project531 1 382

Project574 1 170

Project594 1 125

Project636 2 345

Project644 1 169

Project668 1 191

Project676 1 117

Project684 1 143

Project689 1 108

Project690 1 216

Project713 1 367

Project724 1 127

Project729 2 239

Project738 1 252

Project779 1 115

Project791 1 110

Project818 2 434

Project820 1 222

Project830 1 179

Project888 3 381

Project934 3 461

Project939 3 358

Project951 1 165

Project959 2 351

Project962 1 316

Project967 1 191

Project984 1 117

Project997 1 187

Answers

Answer:

Explanation:

Code:

import java.io.File;

import java.io.FileWriter;

import java.io.IOException;

import java.util.Scanner;

public class Knapsack {

 

  public static void knapsack(int wk[], int pr[], int W, String ofile) throws IOException

  {

      int i, w;

      int[][] Ksack = new int[wk.length + 1][W + 1];

     

      for (i = 0; i <= wk.length; i++) {

  for (w = 0; w <= W; w++) {

  if (i == 0 || w == 0)

  Ksack[i][w] = 0;

  else if (wk[i - 1] <= w)

  Ksack[i][w] = Math.max(pr[i - 1] + Ksack[i - 1][w - wk[i - 1]], Ksack[i - 1][w]);

  else

  Ksack[i][w] = Ksack[i - 1][w];

  }

  }

     

      int maxProfit = Ksack[wk.length][W];

      int tempProfit = maxProfit;

      int count = 0;

      w = W;

      int[] projectIncluded = new int[1000];

      for (i = wk.length; i > 0 && tempProfit > 0; i--) {

         

      if (tempProfit == Ksack[i - 1][w])

      continue;    

      else {

          projectIncluded[count++] = i-1;

      tempProfit = tempProfit - pr[i - 1];

      w = w - wk[i - 1];

      }

     

      FileWriter f =new FileWriter("C:\\Users\\gshubhita\\Desktop\\"+ ofile);

      f.write("Number of projects available: "+ wk.length+ "\r\n");

      f.write("Available employee work weeks: "+ W + "\r\n");

      f.write("Number of projects chosen: "+ count + "\r\n");

      f.write("Total profit: "+ maxProfit + "\r\n");

     

  for (int j = 0; j < count; j++)

  f.write("\nProject"+ projectIncluded[j] +" " +wk[projectIncluded[j]]+ " "+ pr[projectIncluded[j]] + "\r\n");

  f.close();

      }    

  }

 

  public static void main(String[] args) throws Exception

  {

      Scanner sc = new Scanner(System.in);

      System.out.print("Enter the number of available employee work weeks: ");

      int avbWeeks = sc.nextInt();

      System.out.print("Enter the name of input file: ");

  String inputFile = sc.next();

      System.out.print("Enter the name of output file: ");

      String outputFile = sc.next();

      System.out.print("Number of projects = ");

      int projects = sc.nextInt();

      int[] workWeeks = new int[projects];

      int[] profit = new int[projects];

     

      File file = new File("C:\\Users\\gshubhita\\Desktop\\" + inputFile);

  Scanner fl = new Scanner(file);

 

  int count = 0;

  while (fl.hasNextLine()){

  String line = fl.nextLine();

  String[] x = line.split(" ");

  workWeeks[count] = Integer.parseInt(x[1]);

  profit[count] = Integer.parseInt(x[2]);

  count++;

  }

 

  knapsack(workWeeks, profit, avbWeeks, outputFile);

  }

}

Console Output:

Enter the number of available employee work weeks: 10

Enter the name of input file: input.txt

Enter the name of output file: output.txt

Number of projects = 4

Output.txt:

Number of projects available: 4

Available employee work weeks: 10

Number of projects chosen: 2

Total profit: 46

Project2 4 16

Project0 6 30

In a refrigerator, heat is transferred from a lower-temperature medium (the refrigerated space) to a higher-temperature one (the kitchen air). Is this a violation of the second law of thermodynamics

Answers

nononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononnonononononnononononononnonononononononononno

When looking at a chain of processes with a low yield (high defective rate), what is a good place to start investigating the source of variation?

Answers

The most upstream process with issues would be a good location to start exploring the cause of the variance.

Chain processes

A manufacturing technique would be a specific procedure for generating a commodity.

Throughout manufacturing, a six sigma process has been utilized just to generate a product throughout which 99.99966 percent among all possibilities to produce certain aspects of a part seem to be likely toward being defect-free.

Thus the response above is correct.

Find out more information about chain processes here:

brainly.com/question/25646504

Answer: The furthest upstream process that has problems.

A process in manufacturing is a particular method used for producing a product.

A six sigma process is used in processing to produce a product that is 99.99966% of all opportunities to produce some feature of a part are statistically expected to be free of defects.

According to the rules of the six sigma process, when there's a defect, the best thing to do is investigate the furthest upstream process that has problems.

A small family home in Tucson, Arizona has a rooftop area of 2667 square feet, and it is possible to capture rain falling on about 61.0% of the roof. A typical annual rainfall is about 14.0 inches. If the family wanted to install a tank to capture the rain for an entire year, without using any of it, what would be the required volume of the tank in m3 and in gallons? How much would the water in a full tank of that size weigh (in N and in lbf)?

Answers

Answer:

volume  = 53.747 m3 = 14198.138 gal

weight = 526652 N = 118396.08 lbf

Explanation:

We know that volume of water

volume  =  A'* H

where A' = 61% of A

              = 0.61* 2667 = 1626.87 sq ft

volume  =  1626.87 * ((14)/(12) ft)

               =1898.015 ft^3

in\ m^3 = ( 1898.015)/(35.315) =   53.7457 m^3

in\ gallon = 1898.015 * 7.481 = 14198.138 gallon

weight = \rho Vg

       = 1000* 53.74* 9.8

             =526652 N

In\ lbf =  (526652)/(4.448) = 118396.08 lbf

A horizontal curve on a single-lane highway has its PC at station 1+346.200 and its PI at station 1+568.70. The curve has a superelevation of 6.0% and is designed for 120 km/h. The limiting value for coefficient of side friction at 120 km/h is 0.09. What is the station of the PT? Remember that 1 metric station = 1000 m.

Answers

Answer:

The solution is given in the attachments.

A 4-pole, 3-phase induction motor operates from a supply whose frequency is 60 Hz. calculate: 1- the speed at which the magnetic field of the stator is rotating

Answers

Answer:

The answer is below

Explanation:

A 4-pole, 3-phase induction motor operates from a supply whose frequency is 60 Hz. calculate: 1- the speed at which the magnetic field of the stator is rotating. 2- the speed of the rotor when the slip is 0.05. 3- the frequency of the rotor currents when the slip is 0.04. 4- the frequency of the rotor currents at standstill.

Given that:

number of poles (p) = 4, frequency (f) = 60 Hz

1) The synchronous speed of the motor is the speed at which the magnetic field of the stator is rotating. It is given as:

n_s=(120f)/(p)=(120*60)/(4)=1800\ rpm

2) The slip (s) = 0.05

The speed of the motor (n) is the speed of the rotor, it is given as:

n=n_s-sn_s\n\nn=1800-0.05(1800)\n\nn=1800-90\n\nn=1710\ rpm

3) s = 0.04

The rotor frequency is the product of the supply frequency and slip it is given as:

f_r=sf\n\nf_r=0.04*60\n\nf_r=2.4\ Hz

4) At standstill, the motor speed is zero hence the slip = 1:

s=(n_s-n)/(n_s)\n \nn=0\n\ns=(n_s-0)/(n_s)\n\ns=1

The rotor frequency is the product of the supply frequency and slip it is given as:

f_r=sf\n\nf_r=1*60\n\nf_r=60\ Hz