PHYSICS COLLEGE

A 0.47 kg block of wood hangs from the ceiling by a string, and a 0.070kg wad of putty is thrown straight upward, striking the bottom of the block with a speed of 5.60 m/s. The wad of putty sticks to the block. (Answer on previous exams) How high does the putty-block system rise above the original position of the block Is the kinetic energy of the system conserved during the collision Is the mechanical energy of the system conserved during the collision Is the mechanical energy conserved after the collision

Answers

Answer 1

Answer:

Answer:

The height is $h =0.0269 \ m$

The kinetic energy during collision is not conserved

The Mechanical energy during the collision is not conserved

The mechanical energy after the collision is not conserved

Explanation:

From the question we are told that

The mass of the block is $m_b = 0.47\ kg$

The mass of the wad of putty is $m_p = 0.070 \ kg$

The speed o the wad of putty is $v_p = 5.60 \ m/s$

The law of momentum conservation can be mathematically represented as

$p_i = p_f$

Where $p_i$ is the initial momentum which is mathematically represented as

$p_i =m_p * v_p$

While $p_f$ is the initial momentum which is mathematically represented as

$p_f = (m_b + m_p)v_f$

Where $v_f$ s the final velocity

$m_p v_p = (m_p + m_b) * v_f$

Making $v_f$ the subject

$v_f = (m_p v_p)/(m_b +m_p)$

substituting values

$v_f = ((0.070)*(5.60))/(0.47 + 0.070)$

$v_f = 0.726 \ m/s$

According to the law of energy conservation

$KE = PE$

Where KE is the kinetic energy of the system which is mathematically represented as

$KE = (1)/(2) (m_p + m_b)v_f^2$

And PE is the potential energy of the system which is mathematically represented as

$PE = (m_p +m_b) gh$

$(1)/(2) (m_p + m_b)v_f^2 = (m_p +m_b) gh$

Making h the subject of the formula

$h = (v_f^2)/(2g)$

substituting values

$h = ((0.726 )^2 )/(2 * 9.8)$

$h =0.0269 \ m$

Now the kinetic energy is conserved during collision because the system change it height during which implies some of the kinetic energy was converted to potential energy during collision

The the mechanical energy of the system during the collision is conserved because this energy consists of the kinetic and the potential energy.

Now after the collision the mechanical energy is not conserved because the external force like air resistance has reduced the mechanical energy of that system

Related Questions

An electron in a vacuum chamber is fired with a speed of 7400 km/s toward a large, uniformly charged plate 75 cm away. The electron reaches a closest distance of 15 cm before being repelled. What is the plate's surface charge density?
Three resistors are connected in series across a battery. The value of each resistance and its maximum power rating are as follows: 6.7Ω and 15.9 W, 30.4Ω and 9.12 W, and 16.3Ω and 12.3 W. (a) What is the greatest voltage that the battery can have without one of the resistors burning up? (b) How much power does the battery deliver to the circuit in (a)?
The production of heat by metabolic processes takes place throughout the volume of an animal, but loss of heat takes place only at the surface (i.e. the skin). Since heat loss must be balanced by heat production if an animal is to maintain a constant internal temperature, the relationship between surface area and volume is relevant for physiology. If the surface area of a cube is increased by a factor of 2, by what factor does the volume of the cube change? Give your answer to two significant figures. 1.59
What is 902 in proper scientific notation?
Suppose that 600 W of radiation in a microwave oven is absorbed by 250 g of water in a very lightweight cup. Approximately how long will it take to heat the water from 20 C to 80 C?(A) 50 s(B) 100 s(C) 150 s(D) 200 s

You are an electrician installing the wiring in a new home. The homeowner desires that a ceiling fan with light kits be installed in five different rooms. Each fan contains a light kit that can accommodate four 60-watt lamps. Each fan motor draws a current of 1.8 amperes when operated on high speed. It is assumed that each fan can operate more than three hours at a time and therefore must be considered a continuous-duty device. The fans are to be connected to a 15-ampere circuit. Because the devices are continuous-duty, the circuit current must be limited to 80% of the continuous connected load. How many fans can be connected to a single 15-ampere circuit

Answers

Answer:

3 fans per 15 A circuit

Explanation:

From the question and the data given, the light load let fan would have been

(60 * 4)/120 = 240/120 = 2 A.

Next, we add the current of the fan motor to it, so,

2 A + 1.8 A = 3.8 A.

Since the devices are continuos duty and the circuit current must be limited to 80%, then the Breaker load max would be

0.8 * 15 A = 12 A.

Now, we can get the number if fans, which will be

12 A/ 3.8 A = 3.16 fans, or approximately, 3 fans per 15 A circuit.

Final answer:

The total power draw of each fan is 3.8 amperes. Thus, considering a limit of 80% usage of 15 amperes, only 3 fans can be connected to a single circuit to keep the total power draw below 12 amperes.

Explanation:

The question is asking how many ceiling fans, each with a certain power draw, can be connected on a single 15-ampere circuit, considering that each fan is a continuous-duty device. The power draw of each fan when the motor is operated at high speed and the light kit is fully loaded is the sum of the power draw of the motor and the light kit. As the power draw of each motor is 1.8 amperes and the light kit is 240 watts or 2 amperes (calculated using the formula Power = Voltage x Current; assuming a voltage of 120 volts), the total power draw of each fan is 3.8 amperes. Considering the limit of 80% of the continuous load, only 12 amperes (80% of 15) can be used. Thus, 3 fans can be connected to the circuit as it reaches 11.4 amperes, close enough to the 12 amperes limit.

Learn more about Circuit Capacity here:

brainly.com/question/34704571

#SPJ3

The magnetic flux that passes through one turn of a 11-turn coil of wire changes to 5.60 from 9.69 Wb in a time of 0.0657 s. The average induced current in the coil is 297 A. What is the resistance of the wire?

Answers

Answer:

2.31 Ω

Explanation:

According to the Faraday's law of electromagnetic induction,

Induced emf = - N (dΦ/dt)

Emf = -N (ΔΦ/t)

where N = number of turns = 11

Φ = magnetic flux

ΔΦ = change in magnetic flux = 9.69 - 5.60 = 4.09 Wb

t = time taken for the change = 0.0657 s

Emf = 11(4.09/0.0657)

Emf = - 684.78 V (the minus sign indicates that the direction of the induced emf is opposite to the direction of change of magnetic flux)

From Ohm's law,

Emf = IR

R = (Emf)/I

I = current = 297 A

R = (684.78)/297

R = 2.31 Ω

Hope this Helps!!

Explanation:

Below is an attachment containing the solution.

Water on Earth was (a) transported here by comets; (b) accreted from the solar nebula; (c) produced by volcanoes in the form of steam; (d) created by chemical reactions involving hydrogen and oxygen shortly after Earth formed.

Answers

Answer: Water on Earth was transported here by comets. The correct option is A.

Explanation:

Comets are made up of water with ice, rock and minerals.

Alot of research and hypotheses has been made to prove the origin of water on planet earth. Extraplanetary source such as comets, trans-Neptunian objects, and water-rich meteoroids (protoplanets) are believed to have delivered water to Earth.

An artificial satellite circling the Earth completes each orbit in 144 minutes. (a) Find the altitude of the satellite.

Answers

Answer:

Explanation:

given,

time taken to complete the each orbit = 144 minutes

t = 144 x 60 = 8640 s

mass of the earth = 5.98 x 10²⁴ Kg

radius of earth,R = 6.38 x 10⁶ m

Using Kepler's 3rd law

$T^2 = ((4\pi^2)/(GM_e))r^3$

$r = ((T^2GM_e)/(4\pi^2))^(1/3)$

$r = ((8640^2* 6.67 * 10^(-11)* 5.98* 10^(24))/(4\pi^2))^(1/3)$

r = 9.1 x 10⁶ m

the altitude of the satellite

H = r - R

H = 9.1 x 10⁶ - 6.38 x 10⁶

H = 2.72 x 10⁶ m

The interatomic spring stiffness for tungsten is determined from Young's modulus measurements to be 90 N/m. The mass of one mole of tungsten is 0.185 kg. If we model a block of tungsten as a collection of atomic "oscillators" (masses on springs), what is one quantum of energy for one of these atomic oscillators? Note that since each oscillator is attached to two "springs", and each "spring" is half the length of the interatomic bond, the effective interatomic spring stiffness for one of these oscillators is 4 times the calculated value given above. Use these precise values for the constants: ℏ = 1.0546 10-34 J · s (Planck's constant divided by 2π) Avogadro's number = 6.0221 1023 molecules/mole kB = 1.3807 10-23 J/K (the Boltzmann constant)

Answers

Answer:

Explanation:

solution below

Final answer:

The quantum of energy for one atomic oscillator in tungsten, given the effective interatomic spring stiffness of 360 N/m, the mass of one tungsten atom as 3.074 x 10^-25 kg, and the reduced Planck's constant of 1.0546 x 10^-34 J · s, can be calculated to be approximately 1.33 x 10^-21 J.

Explanation:

To calculate the quantum of energy for one atomic oscillator in tungsten, we will consider the model of an atom being connected to two springs, both having an effective interatomic spring stiffness of four times the given value (90 N/m). This value thus becomes 360 N/m.

One mole of tungsten has a mass of 0.185 kg, thus the mass of one atom can be determined by dividing this value by Avogadro's number (6.0221 x 10^23 molecules/mole), which gives approximately 3.074 x 10^-25 kg.

The quantum of energy, or the energy of one quantum (the smallest possible energy increment), is given by the formula E = ħω, where ħ is the reduced Planck's constant (1.0546 x 10^-34 J · s) and ω is the angular frequency, given by sqrt(k/m), where k is the spring constant and m is the mass.

Substituting the known values into these equations gives ω= sqrt((360)/(3.074 x 10^-25)) and E= (1.0546 x 10^-34) x sqrt((360)/(3.074 x 10^-25)), which results in a quantum of energy of approximately 1.33 x 10^-21 J.

Learn more about Quantum Energy here:

brainly.com/question/28175160

#SPJ3

A pair of thin spherical shells with radius r and R, r < R are arranged to share a center. What is the capacitance of the system. If a potential difference V is created between the shells, how much energy is stored between them?