Answer: STP
CaCO3 = 5 g
Convert gram to mol
100 g of CaCO3 = 1 mol
5 g of CaCO3 (n) = 5 g *(1 mol/100 g) = 0.05 mol
Gas law
PV =nRT
V = nRT/P
V = (0.05 mol * (0.08206 L atm /K mol) *273 K)/1 atm
V = 1.124 L
Explanation:
When 5.0 g of CaCO3 are treated with excess hydrochloric acid, it forms 1.118 L of CO2 gas at STP.
When 5.0 g of CaCO3 is treated with excess hydrochloric acid, it undergoes a chemical reaction and forms CO2 gas. To find the number of liters of CO2 formed at STP (standard temperature and pressure), we need to use the ideal gas law. The molar mass of CaCO3 is 100.09 g/mol, and 1 mol of CaCO3 produces 1 mol of CO2 gas. The volume of 1 mol of any gas at STP is 22.4 L. Therefore, we can calculate the number of moles of CaCO3, then convert it to moles of CO2 and finally to the volume of CO2 gas in liters.
Using the given information, we have:
Mass of CaCO3 = 5.0 g
Molar mass of CaCO3 = 100.09 g/mol
Moles of CaCO3 = Mass of CaCO3 / Molar mass of CaCO3
Moles of CO2 = Moles of CaCO3
Volume of CO2 at STP = Moles of CO2 * 22.4 L/mol
Plugging in the values, we get:
Moles of CaCO3 = 5.0 g / 100.09 g/mol = 0.04997 mol
Moles of CO2 = 0.04997 mol
Volume of CO2 at STP = 0.04997 mol * 22.4 L/mol = 1.118 L
#SPJ2
reactant would be required to produce 25.0 mol
of sodium chloride?
Answer:
Mass of Sodium = 574.75 g
Mass of Chlorine = 886.25 g
Explanation:
The balance chemical equation for the synthesis of NaCl is,
2 Na + Cl₂ → 2 NaCl
Step 1: Find out moles of each reactant required,
According to balance chemical equation,
2 moles of NaCl is produced by = 2 moles of Na
So,
25 moles of NaCl will be produced by = X moles of Na
Solving for X,
X = 25 mol × 2 mol / 2 mol
X = 25 moles of Na
Similarly for Cl₂,
According to balance chemical equation,
2 moles of NaCl is produced by = 1 mole of Cl₂
So,
25 moles of NaCl will be produced by = X moles of Cl₂
Solving for X,
X = 25 mol × 1 mol / 2 mol
X = 12.5 moles of Cl₂
Step 2:Convert each moles to mass as;
Mass = Moles × Atomic Mass
For Na,
Mass = 25 mol × 22.99 g/mol
Mass = 574.75 g
For Cl₂,
Mass = 12.5 mol × 70.90 g/mol
Mass = 886.25 g
Mass of Sodium = 574.75 g and Mass of Chlorine = 886.25 g
The number of moles can be calculated by dividing given mass over molar mass.
2 Na + Cl₂ → 2 NaCl
Calculation for moles:
2 moles of NaCl is produced by = 2 moles of Na
So,
25 moles of NaCl will be produced by = x moles of Na
Solving for x,
x = 25 mol × 2 mol / 2 mol
x = 25 moles of Na
Similarly for Cl₂,
2 moles of NaCl is produced by = 1 mole of Cl₂
So,
25 moles of NaCl will be produced by = x moles of Cl₂
Solving for x,
x = 25 mol × 1 mol / 2 mol
x = 12.5 moles of Cl₂
Conversion of moles from mass:
Mass = Moles × Atomic Mass
For Na,
Mass = 25 mol × 22.99 g/mol
Mass = 574.75 g
For Cl₂,
Mass = 12.5 mol × 70.90 g/mol
Mass = 886.25 g
Find more information about Molar mass here:
A. an ion
B. an isotope
Answer:
the hypothesis is the anawer.
(2) nitrogen (4) oxygen