CHEMISTRY COLLEGE

At a winter carnival, a balloon is filled with 5.00 L of helium at a temperature of 1.0°C. What will be the volume of the balloon when it is brought into a warm house at 24°C?

Answers

Answer 1

Answer:

Answer:

The volume of balloon is 5.41 L.

Explanation:

The volume of helium (V1) = 5 L

Temperature (T1) = 1 degree Celsius

Now covert the temperature into kelvin by simply adding the 273 with given temperature. Thus, 1-degree Celsius = 274 kelvin.

The volume of balloon (V2) =?

Temperature (T2) = 24 degree Celsius

Now covert degree Celsius into kelvin. Thus, 24-degree Celsius = 297 kelvin.

Using Charl’s law.

$(V1)/(T1) = (V2)/(T2) \n$

$(5)/(274) = (V2)/(297) \n$

$V2 = 5.41 \ L$

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Which description is not a property of a base? (2 points)a
pH lower than 7

b
Turns litmus paper blue

c
Bitter taste

d
Slimy feel

Answers

i think it’s A
because if the pH is lower than 7 than it is acidic

Answer:

the answer is a hope it helps.

Explanation:

Which indicator will be the same color in hydrochloric acid as it is in pure water?1.methyl orange
2.phenolphthalein
3.bromcresol green

Answers

Phenolphthalein
In acid it is colourless and in water also colourless

What is the pH at each of the points in the titration of 25.00 mL of 0.2000 MHCl by 0.2000 M NaOH:
i) Before adding NaOH

ii) After adding 24.00 mL NaOH

Answers

Answer:

i) pH = 0.6990

ii) pH = 2.389

Explanation:

i) Before adding aqueous NaOH, there are 25.00 mL of 0.2000 M HCl. HCl reacts with the water in the aqueous solution as follows:

HCl + H₂O ⇒ H₃O⁺ + Cl⁻

The HCl and H₃O⁺ are related to each other through a 1:1 molar ratio, so the concentration of H₃O⁺ is equal to the HCl concentration.

The pH is related to the hydronium ion concentration as follows:

pH = -log([H₃O⁺]) = -log(0.2000) = 0.699

ii) Addition of NaOH causes the following reaction:

H₃O⁺ + NaOH ⇒ 2H₂O + Na⁺

The H₃O⁺ and NaOH react in a 1:1 molar ratio. The amount of NaOH added is calculated:

n = CV = (0.2000 mol/L)(24.00 mL) = 4.800 mmol NaOH

Thus, 4.800 mmol of H₃O⁺ were neutralized.

The initial amount of H₃O⁺ present was:

n = CV = (0.2000 mol/L)(25.00 mL) = 5.000 mmol H₃O⁺

The amount of H₃O⁺ that remains after addition of NaOH is:

(5.000 mmol) - (4.800 mmol) = 0.2000 mmol

The concentration of H₃O⁺ is the amount of H₃O⁺ divided by the total volume. The total volume is (25.00 mL) + (24.00 mL ) = 49.00 mL

C = n/V = (0.2000 mmol) / (49.00 mL) = 0.004082 M

The pH is finally calculated:

pH = -log([H₃O⁺]) = -log(0.004082) = 2.389

Calculate the pH of a buffer solution made by adding 15.0 g anhydrous sodium acetate (NaC2H3O2) to 100.0 mL of 0.200 M acetic acid. Assume there is no change in volume on adding the salt to the acid. (pKa for acetic acid is 4.74 or Ka is 1.8 x 10-5)3.

Answers

Answer:

pH of Buffer Solution 5.69

Explanation:

Mole of anhydrous sodium acetate = $(Given mass)/(Molecular mass)$

= $(15)/(82)$

= 0.18 mole

100 ml of 0.2 molar acetic acid means

= M x V

= 0.2 x 100

= 20 mmol

= 0.02 mole

Using Henderson equation to find pH of Buffer solution

pH = pKa + log $([Salt])/([Acid])$

= 4.74 + log $(0.18)/(0.02)$

= 4.74 + log 9

= 5.69

So pH of the Buffer solution = 5.69

given that the only known ionic charges of lead are pb(ii) and pb(iv), how can you explain the existence of the pb2o3 salt

Answers

Answer:

See Explanation

Explanation:

Pb2O3 is better formulated as PbO.PbO2. It is actually a mixture of the two oxides of lead, lead II oxide and lead IV oxide.

This implies that this compound Pb2O3 (sometimes called lead sesquioxide) is a mixture of the oxides of lead in its two known oxidation states +II and +IV.

Hence Pb2O3 contains PbO and PbO2 units.

How many molecules are there in 4.27 mol of tungsten(VI) oxide, WO3

Answers

25.71 × 10²³ molecules are there in 4.27 mol of tungsten (VI) oxide, $WO_3$ .

How to find the number of molecules ?

To find the Number of molecules of substance multiply the number of moles of given substance by Avogadro number

Number of molecules = Number of moles × Avogadro's Number

Avogadro's Number

Avogadro's number $(N_(A))$ is the number of particles in one mole of substance. 6.023 × 10²³ is known as Avogadro's constant / Avogadro's number.