PHYSICS COLLEGE

A Michelson interferometer operating at a 400 nm wavelength has a 3.95-cm-long glass cell in one arm. To begin, the air is pumped out of the cell and mirror M2 is adjusted to produce a bright spot at the center of the interference pattern. Then a valve is opened and air is slowly admitted into the cell. The index of refraction of air at 1.00 atmatm pressure is 1.00028.Required:
How many bright-dark-bright fringe shifts are observed as the cell fills with air?

Answers

Answer 1
Answer:

Answer:

55.3

Explanation:

The computation of the number of bright-dark-bright fringe shifts observed is shown below:

\triangle m = (2d)/(\lambda) (n - 1)

where

d = 3.95 * 10^(-2)m

\lambda = 400 * 10^(-9)m

n = 1.00028

Now placing these values to the above formula

So, the  number of bright-dark-bright fringe shifts observed is

= (2 *3.95 * 10^(-2)m)/(400 * 10^(-9)m) (1.00028 - 1)

= 55.3

We simply applied the above formula so that the number of bright dark bright fringe shifts could come

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A virtual image produced by a lens is always

Answers

The correct answer is:

"located in front of lens"

just took PF test and this was right answer

M = 30.3kg
M = 40.17kg 9
R = 0.5m
G = 6. 67x10^11
F ?​

Answers

Answer:

m¹=30.3kg

m²=40.17kg

R=0.5m

G=6.67*10¹¹

F=Gm¹m²/R²

=160.68

A heavy object and a light object are dropped from the same height. If we neglect air resistance, which will hit the ground first?

Answers

Answer:

None, both objects will hit ground at the same time.

Explanation:

  • Assuming no air resistance present, and that both objects start from rest, we can apply the following kinematic equation for the vertical displacement:

        \Delta h = (1)/(2)*g*t^(2) (1)

  • As the left side in (1) is the same for both objects, the right side will be the same also.
  • Since g is constant close to the surface of the Earth, it's also the same for both objects.
  • So, the time t must be the same for both objects also.

Last night, Shirley worked on her accounting homework for one and one half hours. During that time, she completed 6 problems. What is the velocity in problems per hour? a. 6 per hour
b. 4 per hour
c. 10 per hour
d. 0.67 per hour
e. 15 per hour

Answers

Answer:

velocity in problems per hour = 4 per hour

so correct option is b. 4 per hour

Explanation:

given data

worked on  homework time = 1.5 hour

completed = 6 problems

to find out

What is the velocity in problems per hour

solution

we know that Shirley solve complete 6 accounting homework problem in 1.5 hour so her velocity  in problems per hour will be as

velocity in problems per hour =  (complete\ problem)/(time\ taken)   ..................1

put here value we will get

velocity in problems per hour =  (6)/(1.5)

velocity in problems per hour = 4 per hour

so correct option is b. 4 per hour

Answer:

option (b) is correct

Explanation:

time t = 1 and half hour = 1.5 hour

Number of problems, n = 6

So, the velocity in problems

v = n / t

v = 6 / 1.5

v = 4

So, the rate is 4 problems per hour.

Two bodies, one hot and the other cold kept in vacuum.what will happen to the tempreture of bodies after some time.

Answers

Hot body will lose heat from it, and that heat will goes out from it through radiation, so it's temperature will decrease after some time.

In same manner, cold body will take the heat, and it's temperature will increase

Hope this helps!

When a 20.0-ohm resistor is connected across the terminals of a 12.0-V battery, the voltage across the terminals of the battery falls by 0.300 V. What is the internal resistance of this battery

Answers

The internal resistance of the battery is 0.5 ohms.

To calculate the internal resistance of the battery, we use the formula below

Formula:

  • (V/R)r = V'............. Equation 1

Where:

  • V = Voltage across the terminal of the battery
  • R = Resistance connected across the battery
  • r = internal resistance of the battery
  • V' = voltage drop of the battery.

Make r the subject of the equation

  • r = V'R/V............ Equation 2

From the question,

Given:

  • V = 12 V
  • R = 20 ohms
  • V' = 0.3 V

Substitute these values into equation 2

  • r = (0.3×20)/12
  • r = 6/12
  • r = 0.5 ohms.

Hence, The internal resistance of the battery is 0.5 ohms.

Learn more about internal resistance here: brainly.com/question/14883923

Answer:

The  internal resistance is  r = 0.5 \ \Omega

Explanation:

From the question we are told that the resistance of

   The  resistance of the resistor is  R = 20.0\ \Omega

    The  voltage is V = 12.0 \ V

     The magnitude of the voltage fall is  e = 0.300\ V

Generally the current flowing through the terminal due to the voltage of the battery  is  mathematically represented as

        I = (V)/(R)

substituting values

        I = (12.0 )/(20 )

       I = 0.6 \ A

The internal resistance of the battery is mathematically represented as

      r = (e)/(I)

substituting values

     r = (0.300)/( 0.6 )

    r = 0.5 \ \Omega
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