A circuit contains a 40 ohm resistor and a 60 ohms resistor connected in parallel. If you test this circuit with a DMM you should read a total resistance
Answers
Answer:
24Ω
Explanation:
When resistors are connected in parallel, the reciprocal of their combined resistance, when read with a DMM (Digital Multimeter - for measuring various properties of a circuit or circuit element such as resistance...) is the sum of the reciprocals of their individual resistances.
For example if two resistors of resistances R₁ and R₂ are connected together in parallel, the reciprocal of their combined resistance Rₓ is given by;
=
+
Solving for Rₓ gives;
=
------------------(i)
From the question;
Let
R₁ = resistance of first resistor = 40Ω
R₂ = resistance of second resistor = 60Ω
Now,
To get their combined or total resistance, Rₓ, substitute these values into equation (i) as follows;
=
=
= 24 Ω
Therefore, the total resistance is 24Ω
Answer:
24 ohms
Explanation:
pf
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Answer:
Explanation:
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hope this you
Answers
Find the given attachment
Answers
Answer:
0.556 Watts
Explanation:
w = Weight of object = 762 N
s = Distance = 5 m
t = Time taken = 29 seconds
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s²
Equation of motion
Mass of the body
Force required to move the body
Velocity of object
Power
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Answers
The moment of force at the given slope about point C is 210 ft-lb.
The given parameters:
- Vertical slope, = 2
- Horizontal slope = 3
- Clockwise moment = 330 ft-lb
- Counterclockwise moment = 420 ft-lb
The magnitude of the two moments are in the following simple ratio;
330:420 = 11:14 (divide through by 30)
- the A coordinate = (0, 5)
- the B-coordinate = (5,0)
The line of action of the force passes line AB at the final following coordinates;
total ratio of 11:14 = 11 + 14 = 25
The position of C = (3, 1)
The resultant position of point C = (3 - 2.2, 2.8-1) = (0.8, 1.8)
The moment of force at the given slope about point C is calculated as;
3(1.8) + 2(0.8) = 7
Recall that this is the simplest form of the moment produced by the force.
Moment about C = 7 x 30 = 210 ft-lb
Thus, the moment of force at the given slope about point C is 210 ft-lb.
Learn more about moment of force here: brainly.com/question/6278006
Answers
Answer:
Maximum work under this condition (∆G) = Maximum work under Standard Condition (∆G°) + Activities defining this condition
Explanation:
In this equation, the term DGo provides us with a value for the maximal work we could obtain from the reaction starting with all reactants and products in their standard states, and going to equilibrium. The term DG' provides us with a value for the maximal work we could obtain under the conditions defined by the activities in the logarithmic term. The logarithmic term can be seen as modifying the value under standard conditions to account for the actual conditions. In describing the work available in metabolic processes, we are concerned with the actual conditions in the reaction medium (whether that is a test-tube, or the cell cytoplasm); the important term is therefore DG'. If we measure the actual activities (in practice, we make do with concentrations), and look up a value for DGo in a reference book, we can calculate DG' from the above equation.
Values for DGo provide a useful indication through which we can compare the relative work potential from different processes, because they refer to a standard set of conditions.
Therefore both phrases describe the Biochemical and Chemical Standard State
Answers
Answer:
// Program is written in C++
// Comments are used to explain some lines
// Only the required function is written. The main method is excluded.
#include<bits/stdc++.h>
#include<iostream>
using namespace std;
int divSum(int num)
{
// The next line declares the final result of summation of divisors. The variable declared is also
//initialised to 0
int result = 0;
// find all numbers which divide 'num'
for (int i=2; i<=(num/2); i++)
{
// if 'i' is divisor of 'num'
if (num%i==0)
{
if (i==(num/i))
result += i; //add divisor to result
else
result += (i + num/i); //add divisor to result
}
}
cout<<result+1;
}
In this exercise, using the knowledge of computational language in C++, we have that this code will be written as:
The code is in the attached image.
We can write the C++ as:
#include<bits/stdc++.h>
#include<iostream>
using namespace std;
int divSum(int num)
{
int result = 0;
for (int i=2; i<=(num/2); i++)
{
if (num%i==0)
{
if (i==(num/i))
result += i; //add divisor to result
else
result += (i + num/i); //add divisor to result
}
}
cout<<result+1;
}
See more about C++ at brainly.com/question/19705654