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What displacement do I have if I travel at 10 m/s E for 10 s? A. 1 m E B. 1 m C. 100 m D. 100 m E Scalar quantities include what 2 things? A. Number and direction B. Numbers and units C. Units and directions D. Size and direction What measures distance in a car? A. Odometer B. Pressure gauge C. Speedometer D. Steering wheel What displacement do I have if I travel 10 m E, then 6 m W, then 12 m E? A. 28 m E B. 16 m E C. 16 m D. 28 m

Answers

Answer 1

Answer: Hope this will help you

Answer 2

Answer:

Final answer:

The displacement is 100 m to the east.

Explanation:

The displacement can be calculated using the formula:

Displacement = Velocity × Time

In this case, the velocity is 10 m/s to the east and the time is 10 seconds.

So, Displacement = 10 m/s × 10 s = 100 m to the east.

Learn more about Displacement here:

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The magnitude J(r) of the current density in a certain cylindrical wire is given as a function of radial distance from the center of the wire's cross section as J(r) = Br, where r is in meters, J is in amperes per square meter, and B = 2.35 ✕ 105 A/m3. This function applies out to the wire's radius of 2.00 mm. How much current is contained within the width of a thin ring concentric with the wire if the ring has a radial width of 11.5 μm and is at a radial distance of 1.20 mm?
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An ac source of period T and maximum voltage V is connected to a single unknown ideal element that is either a resistor, and inductor, or a capacitor. At time t = 0 the voltage is zero. At time t = T/4 the current in the unknown element is equal to zero, and at time t = T/2 the current is I = -Imax, where Imax is the current amplitude. What is the unknown element?

What problem did Katherine face in checking other people’s calculations in the movie ¨Hidden figures¨

Answers

Answer:

Information from the leading mathematicians was considered "classified".

A ball with radius .15 m is rolling with an angular velocity of 6.5 rad/s. (a) What linear distance will the ball roll in 5.0 seconds? The ball then slows down with a linear acceleration of -1.2 rad/s2. (B) How fast will it be rolling rad/s after .65 second? (C) If a piece of gum is stuck on the outer part of the ball, what is its linear speed? (4.9, 5.72, .858)

Answers

Answer:

(a) 4.875 m

(b) 5.72 rad/s

Explanation:

(a) Assuming constant angular speed, the angular distance the ball would have traveled after 5s at the rate of 6.5 rad/s is

6.5 * 5 = 32.5 rad

With radius of 0.15m, the linear distance it would have traveled is

32.5 * 0.15 = 4.875 m

(b)The angular velocity of the ball after 0.65s when subjected to an angular acceleration of -1.2 rad/s is

6.5 - 1.2*0.65 = 5.72 rad/s

(c)The linear speed of the ball is the product of the angular speed and radius 0.15 m

5.72 * 0.15 = 0.858 m/s

The cart is initially at rest. ForceF is applied to the cart for time ? t, after which the car has speed v. Suppose the same force is applied for the same time to a second cart with twice the mass. Friction is negligible. Afterward, the second cart's speed will be
a) 2v
b) 1/2v
c) v
d) 4v
e) 1/4v

Answers

Answer:

$v'=(1)/(2)v$

Explanation:

Given that,

Initial speed of the cart, u = 0

Let F force is applied to the cart for time $\Delta t$ after which the car has speed v. The force on an object is given by :

F = ma

m is the mass of the cart

We need to find the speed of second cart, if the same force is applied for the same time to a second cart with twice the mass. Force becomes,

$F=(mv')/(t)$

$v'=(F t)/(2m)$

$v'=(1)/(2)v$

So, the speed of second cart is half of the initial speed of first cart. So, the correct option is (b).

Which of the following could be reasonable explanations for how a piece of invisible tape gets charged? Select all that apply. (1) Protons are pulled out of nuclei in one tape and transferred to another tape.
(2) Charged molecular fragments are broken off one tape and transferred to another.
(3) Electrons are pulled out of molecules in one tape and transferred to another tape.
(4) Neutrons are pulled out of nuclei in one tape and transferred to another tape.

Answers

Answer:

2 and 3

Explanation:

The right answer is the option 2 and 3,

This is all about the electrons transfer from one material to the other material.

For example if the electrons in the valence shell of one material are loosely attached then the other material's atoms try to take those electron to complete their shells and that is how the charges transfers from one another.

And it could also be happen as in option 2.

If i throw up an object up at 31 m/s, how long will it take to get to its highest point

Answers

Answer:

Explanation:

vf=vi+at

vf=31 m/s

vi=0 m/s

a=g=9.8 m/s2

t=?

vf-vi=at

vf-vi/a=t

t=vf-vi/a

t=31 m/s-0/9.8

t=3.16 s

A 0.120 kg baseball, thrown with a speed of 38.4 m/s, is hit straight back at the pitcher with a speed of 47.3 m/s. (a) What is the magnitude of the impulse delivered by the bat to the baseball? kg · m/s (b) Find the magnitude of the average force exerted by the bat on the ball if the two are in contact for 2.20 10-3 s. kN