Air enters the first compressor stage of a cold-air standard Brayton cycle with regeneration and intercooling at 100 kPa, 300 K, with a mass flow rate of 6 kg/s. The overall compressor pressure ratio is 10, and the pressure ratios are the same across each compressor stage. The temperature at the inlet to the second compressor stage is 300 K. The turbine inlet temperature is 1400 K. The compressor stages and turbine each have isentropic efficiencies of 80% and the regenerator effectiveness is 80%. For k = 1.4, calculate: a. the thermal efficiency of the cycle
b. the back work ratio
c. the net power developed, in kW
d. the rates of exergy destruction in each compressor stage and the turbine stage as well as the regenerator, in kW, for T 0 = 300 K.

The program was written in MATLAB. The program source file has an incomplete function, that needs to be completed.

Complete the function with the following code segment

function onTime = RunningLate (noTraffic, gasEmpty)

onTime = ((noTraffic) & not(gasEmpty))

end

The following, should be noted about the above code segment

1. The first line declares/defines the function; The function name is RunningLate, and it receives noTraffic and gasEmpty as its parameters
2. On the second line; If noTraffic is true and gasEmpty is false, the function will return true
3. If otherwise, it will return false.

I've added the image of the complete question (in a more presentable format), as an attachment.

As stated above;

After running the complete program; onTime will be true if noTraffic and gasEmpty are true and false, respectively.

Read more about MATLAB programs at;

brainly.com/question/7247701

Answer: This is EASY!

Explanation:

To make it easy, you would convert those binary numbers and to denary. And this gives:

84 104 105 115 32 105 115 32 69 65 83 89 33

Then, the denary numbers generated can be converted to ASCII code using this ASCII Table in the attachment below. And the result is: This is EASY!

Answer:

// This program is written in C++ programming language

// Comments are used for explanatory purpose

/* The aim of this program is to to remove all the white space,digits, punctuation, and other special characters, leaving only the letters. */

// Program starts here

#include <stdio.h>

#include<iostream>

using namespace std;

int main()

{

// Declare Variable of 100 characters

char word[100];

// Prompt user for input

cout<<"Your input goes here (max, 100 characters)";

cin>>word;

// Iterate through string to check for non alphabetic characters

for (int i = 0; word[i] != '\0'; ++i) {

// Check for uppercase and lowercase letters

while (!((word[i] >= 'a' && word[i] <= 'z') || (word[i] >= 'A' && word[i] <= 'Z') || word[i] == '\0')) {

for (int j = i; word[j] != '\0'; ++j) {

word[j] = word[j + 1];

}

word[j] = '\0';

}

}

cout<<"The resulting compressed string: "<<word;

return 0;

}

Answer:

w = str(input("input your values: "))

values = ' '.join(filter(str.isalpha, w))

while len(w) < 100:

       print(values)

       break

Explanation:

The code is written in python

w = str(input("input your values: "))

This code ask the user to input any string values with characters, numbers, line spaces , letters etc.

values = ' '.join(filter(str.isalpha, w))

This code filters the inputted value to bring only letters. All the letter are then joined together

while len(w) < 100:

The code check if the inputted value is less than 100 characters. While it is less than 100 characters. If it is less than 100 character the next code will function.

print(values)

This code prints the joined letters after checking with  a while loop to confirm the length of character is less than 100

break

The break function breaks the code whether it print the values or not.

Generally, the letters will only be printed if the character inputted is less than 100 and later break the while loop or will not print any letter if the character is greater than 100 and later break.

Answer:

volume  = 53.747 m3 = 14198.138 gal

weight = 526652 N = 118396.08 lbf

Explanation:

We know that volume of water

where A' = 61% of A

               =1898.015 ft^3

             =526652 N

Answer:

The bending stress of the face tooth is  

Explanation:

From the question we are told that

        The number of tooth of the pinion is  

         The velocity of rotation is given as

         The number of tooth is of the gear is  

        The quality level is

          The transmitted tangential load is =

        The angle of the teeth is  

         The module is  

         The face width is

The diameter of the pinion is mathematically represented as

Substituting the values

The pitch line velocity is mathematically represented as

Substituting values

Generally the dynamic factor is mathematically represented as

Now B is a constant that is mathematically represented as

substituting values

A is also a constant that is mathematically represented as

Substituting values

Substituting these value into the equation for dynamic factor we have

The geometric bending factor for a 20° profile from table

"AGMA Bending Geometry Factor J for 20°, Full -Depth Teeth with HPSTC Loading , Table 2-9"                

That corresponds to 55 tooth gear meshing with 26 pinion is

the diameter pitch can be mathematically represented as

Substituting values

The mathematically representation for gear tooth bending stress in the teeth face is as follows

Where is the tangential load

            is the face width

            is the application factor  this is obtained from table "Application Factors, Table 12-17 " and the value  is    = 1

            is the load distributed factor

            is the size factor

              is the rim thickness factor which is obtained for M which has a value  1

            is the idler

Substituting values into equation 1

Answer:

Q=127.66W

L=9.2mm

Explanation:

Heat transfer consists of the propagation of energy in the form of heat in different ways, these can be convection if it is through a fluid, radiation through electromagnetic waves and conduction through solid solids.

To solve any problem related to heat transfer, the general equation is used

Q = delta / R

Where

Q = heat

Delta = the temperature difference

R = is the thermal resistance by conduction, convection and radiation

to solve this problem we propose the previous equation

Q = delta / R

later we find R

Q=(25-(-5))/0.235=127.66W

part b

we use the same ecuation with Q=127.66

Q = delta / R

Δ