MATHEMATICS COLLEGE

What is the next number in the sequence. 1,121,12321, 1234321

The next number in the sequence is _____

Answers

Answer 1
Answer:

Answer:

123454321

Step-by-step explanation:

it's a palendrome, made out of a number of numbers in the sqquence.

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The probability of finding a broken cookie in a bag of chocolate chip cookies is P = .03. Find the probability of getting at least 2 broken cookies in a bag containing 36 cookies

Answers

P(at least 2 broken cookies) = 1 - P(X = 0) - P(X = 1)

How to find the  probability of getting at least 2 broken cookies in a bag containing 36 cookies

To find the probability of getting at least 2 broken cookies in a bag containing 36 cookies, we need to calculate the probability of getting 2, 3, 4, ..., up to 36 broken cookies and then sum up those probabilities.

The probability of getting exactly 2 broken cookies can be calculated using the binomial probability formula:

P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)

Using the formula, we can calculate P(X = 2):

P(X = 2) = C(36, 2) * (0.03)^2 * (1 - 0.03)^(36 - 2)

Similarly, we can calculate P(X = 3), P(X = 4), and so on, up to P(X = 36).

Once we have calculated all these probabilities, we can sum them up to find the probability of getting at least 2 broken cookies:

P(at least 2 broken cookies) = P(X = 2) + P(X = 3) + P(X = 4) + ... + P(X = 36)

P(at least 2 broken cookies) = 1 - P(X = 0) - P(X = 1)

To calculate P(X = 0), we can use the binomial probability formula with k = 0, and for P(X = 1), we can use the formula with k = 1.

Once we have calculated P(X = 0) and P(X = 1), we can substitute them into the equation:

P(at least 2 broken cookies) = 1 - P(X = 0) - P(X = 1)

This will give us the probability of getting at least 2 broken cookies in a bag containing 36 cookies.

Learn more about probability at brainly.com/question/13604758

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the answer would be .06 bc its 2 broken cookies in a bag therefore it would be double so the answer is .06

Need help with 5. Part C

Answers

Answer:

  BA = 12

Step-by-step explanation:

All the right triangles are similar, so the ratio of hypotenuse to long side is a constant. In particular ΔABC ~ ΔDBA, so ...

  hypotenuse/long-side = BC/BA = BA/BD

Cross multiplying gives ...

  BA² = BC·BD

  BA = √(BC·BD) = √(16·9)

  BA = 12

Use the GCF and the distributive property to find the expression that isequivalent to 36 - 48
A 6(6+8)
B. 12(3+4)
C. 2(18-24)
D. 419-12

Answers

The answer is 2(18-24) or C.
It’s c! Make sure to do the problems and remember when a problem has () these you do that problem first then the rest!

C^2 + 5c =3 Tell if this factors or not? And show how it factors or does not factor? And if it factors what are the roots?

Answers

The answer to your questions is that it depends on how we view the polynomial. In particular,


c^2+5c=3\implies c^2+5c-3=0

If the left hand side were factorizable, then we would be able to write it in the form

(c-r_1)(c-r_2)=c^2+5c-3=0

If we expand the leftmost expression, we'd get

c^2-(r_1+r_2)c+r_1r_2=c^2+5c-3=0

and so for the two polynomials to be the same, the coefficients must match. In other words, the unknowns r_1,r_2 would have to satisfy

\begin{cases}-(r_1+r_2)=5\nr_1r_2=-3\end{cases}

Suppose that, moreover, we want integer solutions for r_1,r_2. For this to happen, they must be factor pairs of the constant term.

-3 only has two factor pairs. Either r_1=-1 and r_2=3, or r_1=1 and r_2=-3. In the first case, we'd get a linear coefficient of -(-1+3)=-2\neq5, while in the second, we'd get -(1-3)=2\neq5.

There is no integer solution for this system, so the original quadratic is not factorizable - but only so over the integers.

If we change the scope of the coefficients, i.e. allow for any real numbers/complex numbers to appear in the factorization, then we always factorize a quadratic. The above system is easy to solve.

r_1r_2=-3\implies r_2=-\frac3{r_1}
\implies-\left(r_1-\frac3{r_1}\right)=5
\implies{r_1}^2+5r_1-3=0
\implies r_1=\frac{-5\pm√(37)}2

\implies c^2+5c-3=\left(c+\frac{5-√(37)}2\right)\left(c+\frac{5+√(37)}2\right)

so the original quadratic is factorizable over the reals.

1. Find y, A. and B.

Answers

3A=120 degrees (bcoz they are alternate exterior angles)

A= 40 degrees

5B= 120 degrees( bcoz they're alternate exterior angles)

B= 24 degrees

to find value of y I equalized

8+15=29/3 + y

y= 23-29/3

y=17/3

Use a table to multiply (–5a)(2a – 1). A) –15a B) 5a2 + 10a C) –10a2 – 5a D) –10a2 + 5a

Answers

Answer:

-10a² + 5a

Step-by-step explanation:

Given the expression (–5a)(2a – 1)

Open the bracket

(–5a)(2a – 1)

= -5a(2a) -5a(-1)

= -10a² + 5a

hence the equivalent expression is -10a² + 5a
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