Ammonia, methane, and phosphorus trihydride are three different compounds with three different boiling points. Rank their boiling points in order from lowest to highest.A. CH4< NH3 < PH3
B. NH3 < PH3< CH4
C. CH4 < PH3 < NH3
D. NH3 < CH4< PH3
E. PH3< NH3 < CH4

Answers

Answer 1
Answer:

Answer:

B. NH3 < PH3< CH4

Explanation:

Hello,

In this case, taking into account that the boiling point of ammonia, methane and phosphorous trihydrate are -33.34 °C, -161.5 °C  and -87.7 °C, clearly, methane has the lowest boiling point (most negative) and ammonia the greatest boiling point (least negative), therefore, ranking is:

B. NH3 < PH3< CH4

Best regards.


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Draw the Lewis structure for the polyatomic hydronium H3O cation. Be sure to include all resonance structures that

Answers

Answer:

 Lewis structure of Hydronium ion is shown below :                          

Explanation:

Lewis structure : It is a representation of valence electrons on the atoms in a molecule

Here , Hydronium ion is given , which contains 1 atom of oxygen and 3 atoms of hydrogen .

Oxygen has a total of 6 valence electrons and hydrogen contains 1 valence electron .

Oxygen share its 3 valence electrons with 3 hydrogen atoms and left with 3 valence electrons. From these three valence  electrons of oxygen atom  two electrons will be shown as a pair of electrons on oxygen atom but a single electron can not be shown . So , to simplify this, one positive charge is shown overall .  

Resonance structure will be same as the hybrid structure because all  three atoms are same , that is hydrogen .

A cool, yellow-orange flame is used to heat the crucible. Would this affect the mass of the crucible? If so, how?

Answers

Answer:

yes

Explanation:

Usually, it would not affect the crucible, but depending on the temperature of the flame the enamel of the crucible may begin to melt and stick to the metal object being used to handle the crucible. This tiny amount that is melted off can cause very small changes in the original mass of the crucible, which although it is almost unnoticeable it is still there. Therefore, the answer to this question would be yes.

Final answer:

Using a cool, yellow-orange flame to heat the crucible does not directly affect its mass, but can lead to the burning off or decomposition of any impurities or residues present.

Explanation:

When a cool, yellow-orange flame is used to heat the crucible, it does not directly affect the mass of the crucible. The color of the flame is an indication of the temperature and the type of fuel being burned.

However, if there are impurities or residues in the crucible, the heat from the flame can cause them to burn off or decompose, which may slightly affect the mass of the crucible.

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When the chemical equation is balanced what is the ratio of the coefficient of Ag(s) to the cofficient of H2O(l)?___Ag(s)+____NO3-(aq)+____H+(aq)→ ___Ag+(aq)+____NO(g)+______H2O(l)a. 1:1b. 2:1c. 3:1d. 3:2

Answers

Answer:

Ag(s):H2O(l)  = 3:2

For 3 moles Ag(s) we'll have 2 moles H2O(l)

Option D is correct

Explanation:

Step 1: Balancing the equation

3 Ag (s) + 4 HNO3 (aq) → 3 AgNO3 (aq) + NO (g) + 2 H2O (l)

3Ag(s)  +  4NO  ^3-  +  4H+  →3Ag+ +3NO3- +  +NO  +  2H2O

3Ag(s)  +  NO  ^3-(aq)  +  4H+(aq)  →3Ag+(aq)  +NO(g)  +  2H2O(l)

Step 2: The ratio between Ag(s) and H2O(l)

Ag(s):H2O(l)  = 3:2

For 3 moles Ag(s) we'll have 2 moles H2O(l)

Option D is correct

A solution of salt and water is 33.0% salt by mass and has a density of 1.50 g/ml. what mass of the salt in grams is in 5.00l of this solution?

Answers

To answer this item, we solve first for the mass of the solution by multiplying the density by the volume. That is,

      m = (density)(volume)

Substituting the known values,
    m = (1.50 g/mL)(5L)(1000 mL/1L)
      m = 7500 grams

To determine the mass of the salt in the solution, multiply the calculated mass of the solution by the decimal equivalent of the percent salt in the solution.

      m of salt = (7500 g)(0.33)
      m of salt = 2475 grams

Answer: 2475 grams

Suppose a scientist made a claim that all spontaneous reactions are exothermic. Whic of the following would provide the strongest challenge to their claim? Suppose a scientist made a claim that all spontaneous reactions are exothermic. Which of the following would provide the strongest challenge to their claim? a. An exothermic reaction which is not spontaneous
b. An endothermic reaction that only proceeds when coupled to an exothermic reaction
c. An endothermic reaction that only proceeds when a catalytst is present
d. An endothermic reaction which is not spontaneous
e. All of the above

Answers

Answer: Option (c) is the correct answer.

Explanation:

It is given that the scientist is claiming that all the spontaneous reactions are exothermic in nature.

And, it is known that when a reaction is spontaneous in nature then \Delta G is negative.

Now, the relation between Gibb's free energy, enthalpy and entropy is as follows.

               \Delta G = \Delta H - T \Delta S

So, when a catalyst is present in a chemical reaction then we do not need to give large amount of heat from outside. And, because of this the enthalpy of reaction will not be highly positive.

Hence, the value of \Delta G will result in a negative value which means the reaction is spontaneous.

Thus, we can conclude that an endothermic reaction that only proceeds when a catalytst is present, would provide the strongest challenge to their claim.

Isopropyl methyl ether is slightly soluble with water because the oxygen atom of ethers with three or fewer carbon atoms can form a few hydrogen bonds with water.(A) True
(B) False

Answers

Isopropyl methyl ether is slightly soluble in water because the oxygen atom of ethers with 3 or lesser carbon atoms can form hydrogen bonds with water. Therefore, the given statement is true.

What is hydrogen bonding?

Hydrogen bonding is a special class of attractive intermolecular forces that arise because of the dipole-dipole interaction between hydrogen that is bonded to a highly electronegative atom and another highly electronegative atom that lies in the neighborhood of the hydrogen atom.

For example, in water, hydrogen is covalently bonded to the oxygen atom. Therefore, hydrogen bonding arises because of the dipole-dipole interactions between the hydrogen atom of one water molecule and the oxygen atom of another water molecule.

The solubility of ether in water depends upon the extent of the formation of hydrogen bonds with water. Ether which contains three carbon atoms is soluble in water due to these lower hydrocarbon atoms can form hydrogen bonding with water.  

But the solubility of hydrocarbons or ethers decreases as increase the number of carbon atoms. This is because higher ethers or ethers with more carbons have more hydrophobic parts. Therefore they cannot be soluble in water as they cannot form hydrogen bonds with water molecules.

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Answer:

True

Hydrogen bond is a partial intermolecular bonding interaction between a lone pair on an electron rich donor atom, particularly the second-row elements nitrogen (N), oxygen (O), or fluorine (F), and the antibonding orbital of a bond between hydrogen (H) and a more

electronegative atom or group. Such an interacting system is generally denoted Dn–H···Ac, where the solid line denotes a polar covalent bond, and the dotted or dashed line indicates the hydrogen bond. The use of three centered dots for the hydrogen bond is specifically recommended by the IUPAC. While hydrogen bonding has both covalence and electrostatic contributions, and the degrees to which they contribute are currently debated, the present evidence strongly implies that the primary contribution is covelant.

Hydrogen bonds can be intermolecular (occurring between separate molecules) or

intramolecular (occurring among parts of the same molecule)