CHEMISTRY COLLEGE

How many valence electrons must two atoms share to form a single covalent bond? answers A.2 B.4 C.3 D.1

Answers

Answer 1

Answer:

Answer:

Explanation:

A single covalent bond is formed when two electrons are shared between the same two atoms, one electron from each atom.

Answer 2

Answer:

Answer:

the answer is 2

Explanation:

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The amount of I − 3 ( aq ) in a solution can be determined by titration with a solution containing a known concentration of S 2 O 2 − 3 ( aq ) (thiosulfate ion). The determination is based on the net ionic equation 2 S 2 O 2 − 3 ( aq ) + I − 3 ( aq ) ⟶ S 4 O 2 − 6 ( aq ) + 3 I − ( aq ) Given that it requires 29.4 mL of 0.380 M Na 2 S 2 O 3 ( aq ) to titrate a 30.0 mL sample of I − 3 ( aq ) , calculate the molarity of I − 3 ( aq ) in the solution.

Answers

Answer:

The molarity of I₃⁻ (aq) solution: M₂ = 0.186 M

Explanation:

Given net ionic equation:

2S₂O₃²⁻ (aq) + I₃⁻ ( aq ) ⟶ S₄O₆²⁻ (aq) + 3I⁻ (aq)

Number of moles of S₂O₃²⁻: n₁ = 2, Number of moles of I₃⁻: n₂ = 1

Given- For S₂O₃²⁻ solution: Molarity: M₁ = 0.380 M, Volume: V₁ = 29.4 mL;

For I₃⁻ (aq) solution: Molarity: M₂ = ? M, Volume: V₂ = 30.0 mL

To calculate the molarity of I₃⁻ (aq) solution, we use the equation:

$(M_(1)V_(1))/(n_(1))=(M_(2)V_(2))/(n_(2))$

$((0.380 M)* (29.4 mL))/(2)=(M_(2)* (30.0 mL))/(1)$

$\Rightarrow M_(2) = ((0.380 M)* (29.4 mL))/((30.0 mL)* 2) = 0.186 M$

Therefore, the molarity of I₃⁻ (aq) solution: M₂ = 0.186 M

Solve the following problem:

Answers

Answer:

Option 3.

Explanation:

Isomerism is a phenomenon where by two or more compounds have the same molecular formula but different structural patterns.

Geometric Isomerism is a type of Isomerism that occurs within a double bond i.e Geometric isomers have different arrangement within the double bond.

Considering the options given above,

The 1st option is exactly the same as the compound only, it is inverted.

The 2nd option is still the same as the compound, only it is laterally inverted.

The 3rd option satisfy geometric Isomerism as the arrangement differ from the compound in the double bond.

The 4th option is entirely a saturated compound in which geometric Isomerism is not possible.

2.67 grams of butane (C4H10) is combusted in a bomb calorimeter. The temperature increases from 25.68 C to 36.2C. What is the change in the internal energy (deltaE) in KJ/mol for the reaction if the heat capacity of the bomb calorimeter is 5.73 kJ/C?

Answers

The internal energy : 1310.43 kJ/mol

Further explanation

Internal energy (ΔE) can be formulated for Calorimeter :

$\tt \Delta E=C*.\Delta t$

C= the heat capacity of the calorimeter

Δt=36.2-25.68=10.52°C

$\tt \Delta E=5.73 kJ/^oC* 10.52^oC=60.2796~kJ$

mol butane(MW=58,12 g/mol)

$\tt (2.67)/(58,12 )=0.046$

the internal energy (ΔE) in KJ/mol

$\tt (60.2796)/(0.046)=1310.43~kJ/mol$

Final answer:

The change in internal energy when 2.67 grams of butane is combusted in a bomb calorimeter, given a temperature increase from 25.68 C to 36.2C and a heat capacity of 5.73 kJ/C for the calorimeter, is approximately 1308 kJ/mol.

Explanation:

To solve the problem of calculating the changes in internal energy when 2.67 grams of butane (C4H10) is combusted in a bomb calorimeter, it is necessary to understand calorimeter's heat capacity and how a bomb calorimeter works.

The first step will be to calculate the change in temperature which here is the final temperature subtracted from the initial temperature: 36.2 C - 25.68 C = 10.52 C.

Then, we multiply this temperature change by the heat capacity of the calorimeter to find the total heat produced by the reaction in kJ: 10.52 C * 5.73 kJ/C = 60.18 kJ.

The final step is to convert grams of butane to moles, because we are asked to find the energy change in kJ/mol. The molar mass of butane (C4H10) is approximately 58.12 g/mol. So we have approximately 2.67 g / 58.12 g/mol = 0.046 mol.

Finally, we divide the heat produced by the number of moles to get the energy change per mole of butane: 60.18 kJ / 0.046 mol = approximately 1308 kJ/mol.