How many significant figures are in 340500

The distance of 0.704 kilometers is equivalent to 704 meters when converted, using the conversion factor that 1 kilometer equals to 1000 meters.

To convert the distance from kilometers to meters, we utilize the known fact that 1 kilometer is equivalent to 1000 meters. Thus, to get the equivalent of 0.704 kilometers to meters, simply multiply the given distance by 1000.

So, 0.704 kilometers * 1000 = 704 meters.

This means that this particular distance or length is the same as 704 meters when converted to meters from kilometers.

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There are a number of ways to express concentration of a solution. This includes molarity. Molarity is expressed as the number of moles of solute per volume of the solution. The mass of NaOH needed for the solution is calculated as follows:

2 M = amount in moles of solute / 2.5 L

amount in moles of solute = 5 mol NaOH

amount in grams = 5 x 40 = 200 grams NaOH

Answer:

                 Mass = 200 g

Solution:

             Molarity is the amount of solute dissolved per unit volume of solution. It is expressed as,

                         Molarity  =  Moles / Volume of Solution    ----- (1)

Data Given;

                  Molarity  =  2.0 mol.L⁻¹

                  Volume  =  2.5 L

                   M.Mass  =  40.0 g.mol⁻¹

First calculate Moles as,

                        Moles  =  Molarity × Volume

Putting Values,

                        Moles  =  2.0 mol.L⁻¹ × 2.5 L

                         Moles  = 5 mol

Secondly, calculate Mass using following formula,

                        Moles  =  Mass ÷ M.Mass

Solving for Mass,

                        Mass  =  Moles × M.Mass

Putting Values,

                        Mass  =  5 mol × 40.0 g.mol⁻¹

                         Mass =  200 g

Solution Preparation:

                                    Add 200 g of NaOH in a Volumetric Flask and add distilled water upto the mark of 2.5 L. Shake it and you have prepared a 2.5 L of 2.0 M solution of NaOH.

To calculate the atoms of an element in a given molecule, we need to multiply stoichiometry by the number that is written on the foot of that element. The moles of oxygen required is 7.5 mol.

What is stoichiometry?

Stoichiometry is a part of chemistry that help us in making relationship between reactant and product from quantitative aspects.

The balanced equation is

CH(g) + 5O(g)3CO(g) + 4HO(g)

The mole ratio of CH to oxygen is 1:5, means 1 mole of CH will react with 5 mole of oxygen. So, if we take 1.5 moles of  CH then the amount of oxygen that will be produced will be 5 times the moles of

CH. The moles of oxygen required to react with 1.5 moles of CH= 5× 1.5mol.  Moles of oxygen required to react with 1.5 moles of CH=7.5 mol.

Therefore the moles of oxygen required is 7.5 mol.

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Answer:

• The third chice: 0.0750 M Na₂SO₄

Explanation:

Assume 100% ionization:

1) 0.100 M solution K₂SO₄

• K₂SO4 (aq) → 2K⁺ (aq) + SO₄²⁻ (aq)

• Mole ratios: 1 mol K₂SO4 : 2 mol K⁺  + 1 mol SO₄²⁻ (aq) : 3 mol ions. This is 1 : 3

• At constant volume, the mole ratios are equal to the concentration ratios (M).

• 1  M K₂SO₄: 3 M ions = 0.100 M K₂SO₄ / x ⇒ x = 0.300 M ions

This means, that you have to find which of the choices is a solution that contains the same 0.300 M ion concentration.

2) 0.0800 M Na₂CO₃

• Na₂CO₃ (aq) → 2 Na⁺ + CO₃⁻

• 1 M Na₂CO₃ / 3 M ions = 0.0800M / x ⇒ x = 0.0267 M ions

This is not equal to 0.300 M, so this solution would not contain the same total concentration as a 0.100 M solution of K₂SO₄, and is not the right answer.

3)  0.100 M NaCl

• NaCl → Na⁺ + Cl⁻

• 1 M NaCl / 2 M ions = 0.100 M NaCl / x ⇒ x = 0.200 M ions

This is not equal to 0.300 M ion, so not a correct option.

4) 0.0750 M Na₃PO₄

• Na₃PO₄ → 3Na⁺ + PO₄³⁻

• 1 M Na₃PO₄ / 4 M ions = 0.0750 M Na₃PO₄ / x ⇒ x = 0.300 M ions

Hence, this ion concentration is equal to the ion concentration of a 0.100 M solution of K₂SO₄, and is the correct choice.

5)  0.0500 M NaOH

• NaOH → Na⁺ + OH⁻

• 1 M NaOH / 2 mol ions = 0.0500 M NaOH / x ⇒ x = 0.100 M ions

Not equal to 0.300 M, so wrong choice.