The sum of 43.9 and a number is 49.65, as shown below. What number should go in the box to complete the addition problem? 43.9 plus box _.75 equals 49.65

Answers

Answer 1
Answer:

43.9 + x = 49.65

Subtract 43.9 from both sides:

49.65 - 43.9 = 5.75

The missing number is 5


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Compare using <, >, or =.
7 2/5_____ 7 3/8

Answers

7 2/5 as an improper fraction is 37/5 and 7 3/8 as an improper fraction is 59/8. Then we convert those two improper fractions into a decimal (by 100) and get  7 2/5 = 7.4 and 7 3/8 = 7.3, 7.4 is bigger than 7.3 so the answer is...

7 2/5 > 7 3/8

Tell how to undo each operation and explain why it works. Adding 28. Dividing by 17

Answers

Addition: Use subtraction, because the inverse of adding is subtracting. Same goes for subtracting. Add.

Multiplying: Opposite to divideing

If carpet costs $12 per square yard. How much will it cost to carpet a room that is 180 square feet?

Answers

12$ per 3×3 if its square yard

so 180 ÷ 9 = 20

20×12$=240$

Answer:

12$ per 3×3

180 ÷ 9 = 20

20×$12=$240

Step-by-step explanation:

4^3 • 5^3 and 20^3, Are the expressions equivalent? Yes or no?

Answers

Hey there!

4^3 * 5^3 = ?

4^3

= 4 * 4 * 4

= 16 * 4

= [64]

5^3

= 5 * 5 * 5

= 25 * 5

= [125]

125 * 64

= [8,000]

20^3

= 20 * 20 * 20

= 400 * 20

= 8,000

8,000 = [8,000]

Therefore, this statement is TRUE so your answer is: [YES]

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

Yes

Step-by-step explanation:

4³ × 5³

(4 × 5)³

=20³

Both are equivalent

A map is drawn using a scale of 80 mi to 1 cm. On the map , the two cities are 7.5 cm apart. What is the actual distance between the two cities ??

Answers

we know that
scale =measure in the map/measure in the actual
measure in the actual=measure in the map/scale
scale=1 cm/ 80 mi
for
measure in the map=7.5 cm
measure in the actual=?
measure in the actual=7.5 /(1/80)-----> 7.5*80-----> 600 mi

the answer is
the actual distance between the two cities is 600 miles

WHAT IS X AND Y, HELP ITS URGENT

Answers

Answer:I'm here to help! However, your question is a bit vague. Could you please provide more context or clarify what you mean by "X and Y"? Are you referring to variables, coordinates, equations, or something else? The more details you can provide, the better I'll be able to assist you.

Step-by-step explanation: