A buffer solution is 0.413 M in HF and 0.237 M in KF. If Ka for HF is 7.2×10-4, what is the pH of this buffer solution?

Answers

Answer 1
Answer:

Answer:

2.90

Explanation:

Any buffer system can be described with the reaction:

HA~->~H^+~+~A^-

Where HA is the acid and A^- is the base. Additionally, the calculation of the pH of any buffer system can be made with the Henderson-Hasselbach equation:

pH=pKa~+~Log([A^-])/([HA])

With all this in mind, we can write the reaction for our buffer system:

HF~->~H^+~+~F^-

In this case, the acid is HF with a concentration of 0.413 M and the base is F^- with a concentration of 0.237 M. We can calculate the pKa value if we do the "-Log Ka", so:

pKa~=~-Log(7.2X10^-^4)=~3.14

Now, we can plug the values into the Henderson-Hasselbach

pH=~3.14~+~Log(([0.237~M])/([0.413~M]))~=~2.90

The pH value would be 2.90

I hope it helps!


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Calculate the number of C atoms in 9.837 x 1024 molecules of CO2.

Please help

Answers

Answer:

Explanation:

1 molecule contains 1 carbon atom.

9.837 * 10^24 molecules contains 9.837 * 10^24  atom of carbon.

It's a 1 to 1 ratio.

1. In a hydrogen fuel cell, hydrogen gas and oxygen gas are combined to form water. (1) Write the balanced chemical equation describing this reaction using the lowest whole number coefficients. (2) Identify the oxidizing agent and reducing agent. (3) Determine the number of electrons transferred in the balanced chemical equation

Answers

Explanation:

Hydrogen + Oxygen --> Water

(1) Write the balanced chemical equation describing this reaction using the lowest whole number coefficients.

2H2(g) + O2(g) ---> 2H2O(g)

(2) Identify the oxidizing agent and reducing agent.

Oxidizing agent = O (There is decrease in oxidation number from 0 to -2)

Reducing agent = H (There is increase in oxidation number form 0 to  +1)

(3) Determine the number of electrons transferred in the balanced chemical equation

2H2(g) -->  4H+   + 4e- (4 hydrogen atom lost a single electron each)

O2 + 4e-  --> 2O2- (Two oxygen gain 2 electrons each)

Total number of electrons transferred in the balanced chemical equation is 4.

1. What kind of intermolecular forces act between a chlorine monofluoride molecule and a hydrogen bromide moleculeNote: If there is more than one type of intermolecular force that acts, be sure to list them all, with a comma between the name of each force.

Answers

Final answer:

The intermolecular forces that act between chlorine monofluoride (ClF) and hydrogen bromide (HBr) are dipole-dipole interactions. These types of forces result from the attraction between polar molecules.

Explanation:

The intermolecular forces that act between a chlorine monofluoride (ClF) molecule and a hydrogen bromide (HBr) molecule are

dipole-dipole interactions

. A

dipole-dipole interaction

is a type of force that results from the attraction between polar molecules. Since ClF and HBr are both polar molecules, they exhibit this kind of interaction. For instance, the positive end of the polar ClF molecule would be attracted to the negative end of the polar HBr molecule, and vice versa, leading to a

dipole-dipole interaction

.

Learn more about Dipole-Dipole Interaction here:

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Final answer:

Between chlorine monofluoride and hydrogen bromide, the intermolecular forces present are dipole-dipole forces and London dispersion forces due to their polar nature and instantaneous polarizations of electron clouds respectively.

Explanation:

The intermolecular forces that act between a chlorine monofluoride molecule and a hydrogen bromide molecule are primarily the dipole-dipole forces. Dipole-dipole forces are attractive forces that occur between the positive end of one polar molecule and the negative end of another polar molecule. Both chlorine monofluoride and hydrogen bromide are polar molecules, and as such, they interact through dipole-dipole forces. Apart from this, there exists London dispersion forces which are weak forces resulting from instantaneous polarizations of electron clouds in molecules. Hence, between chlorine monofluoride and hydrogen bromide, both dipole-dipole forces and London dispersion forces act.

Learn more about Intermolecular Forces here:

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A system absorbs 12 J of heat from the surroundings; meanwhile, 28 J of work is done on the system. What is the change of the internal energy ΔEth of the system?

Answers

Answer: The value of change in internal energy of the system is, 40 J.

Explanation : Given,

Heat  absorb from the surroundings = 12 J

Work done on the system = 28 J

First law of thermodynamic : It is a law of conservation of energy in which the total mass and the energy of an isolated system remains constant.

As per first law of thermodynamic,

\Delta U=q+w

where,

\Delta U = internal energy  = ?

q = heat  absorb from the surroundings

w = work done on the system

Now put all the given values in this formula, we get the change in internal energy of the system.

\Delta U=12J+28J

\Delta U=40J

Therefore, the value of change in internal energy of the system is, 40J.

lowly add a slight excess of concentrated (12 M) HCl to your aqueous solution until the pH of the solution is acidic as measured by pH paper.

Answers