Answers
Answer:
The slower runner is 1.71 km from the finish line when the fastest runner finishes the race.
Explanation:
Given;
the speed of the slower runner, u₁ = 11.8 km/hr
the speed of the fastest runner, u₂ = 15 km/hr
distance, d = 8 km
The time when the fastest runner finishes the race is given by;
The distance covered by the slower runner at this time is given by;
d₁ = u₁ x 0.533 hr
d₁ = 11.8 km/hr x 0.533 hr
d₁ = 6.29 km
Additional distance (x) the slower runner need to finish is given by;
6.29 km + x = 8km
x = 8 k m - 6.29 km
x = 1.71 km
Therefore, the slower runner is 1.71 km from the finish line when the fastest runner finishes the race.
Related Questions
Air is a good conductor of heat. Please select the best answer from the choices provided T F
A 50 kg child on a skateboard experiences a 75-N force as shown.What is the expected acceleration of the child? F = 75 N 7 . A. 0.67 m/s2 B. 1.50 m/s2 C. 6.70 m/s2 D. 25.0 m/s2
If you rub a balloon on your hair, youcan hang the balloon on the wall.Why does the balloon stick to thewall?
The energy provided each hour by heat to the turbine in an electric power plant is 9.0×10^12 J. If 5.4 × 10^12 J of energy is exhausted each hour from the engine as heat, what is the efficiency of this heat engine?
Answers
Answer:
θ=π/2
Explanation:
The definition of work is W = → F ⋅ → d = q E c o s θ d W=F→⋅d→=qEcosθd. So if no work is done, the displacement must be in the direction perpendicular to the force ie c o s θ = 0 → θ = π / 2 cosθ=0→θ=π/2
Final answer:
A charged particle can be displaced without any external work done on it in a uniform electric field when its movement is perpendicular to the direction of the electric field.
Explanation:
In a uniform electric field, the electric force is the same in every direction. Therefore, if a charge were to be displaced perpendicular to the original direction of the electric field (i.e., in the y or z direction), it would not encounter any extra electric forces. This means there would be no external work being done on the charge. When a charge is moved perpendicular to an electric field, the field does not affect it, and hence, no work is done by the field.
In other words, a charge can be displaced in this field without any external work being done on it when it is moved in a direction perpendicular to the uniform electric field, either in y-axis or z-axis, assuming the electric field is constant in the x-axis direction.
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0.67 m/s2
0.075 m/s2
54 m/s2
Answers
it's 9 squared divided by 6
height at which the ball was hit is 3.0 m tall, how far did the ball go horizontally
before it hit the ground?
5.5 m
3.6 m
O 4.3 m
4.2 m
Answers
Answer:
5.5 is the correct answer
please keeps as Brainly list
Answers
Answer:
The total percent cold work done is 36.46%
Explanation:
Let initial metal thickness = T
Final metal thickness = t
The percent cold work done = WC
Then
%Wc = (T - t)/T × 100
% Wc = ( 0.096 - 0.061 )/0.096 ×100
Total %WC = 36.46%
Answer:
The total percent of cold work is 57.34%
Explanation:
Let x the initial thickness of the sheet. After 33% of cold working, the thickness is 0.096 in. Then:
x - 0.33x = 0.096
x = 0.143 in
the final thickness is equal to 0.061 in. The percent of cold work done is:
%
Answers
The angular speed should be 17.18 rad / s
Calculation of the angular speed:
Since
moment of inertia of the disc I = 1/2 m r²
= .5 x 8 x .25²
= .25 kg m²
Now the work done by force should be converted into the rotational kinetic energy
F x d = 1/2 I ω²
here,
F is the force applied,
d is displacement,
I is moment of inertia of disc
and ω is angular velocity of disc
So,
41 x .9 = 1/2 x .25 ω²
ω² = .25
ω = 17.18 rad / s
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Answer:
Explanation:
moment of inertia of the disc I = 1/2 m r²
= .5 x 8 x .25²
= .25 kg m²
The wok done by force will be converted into rotational kinetic energy
F x d = 1/2 I ω²
F is force applied , d is displacement , I is moment of inertia of disc and ω
is angular velocity of disc
41 x .9 = 1/2 x .25 ω²
ω² = .25
ω = 17.18 rad / s
B. Sprouted bean seeds increase.
C. Sprouted bean seeds remain constant.
D. None of the above
Answers
As we go up the y-axis, the number of sproutedbean seeds increase (option B).
What is a graph?
Graph is a data chart intended to illustrate the relationship between a set (or sets) of numbers (quantities, measurements or indicative numbers) and a reference set.
In a graph, there are two axes as follows;
- Y-axis or vertical axis
- X-axis or horizontal axis
According to this question, a graph of number of sprouted bean seeds on the y-axis is plotted against temperature on the x-axis.
We can observe that as we go up the y-axis, the number of sprouted bean seeds increase.
Learn more about graphs at: brainly.com/question/2938738
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