I'm taking physics and trying to figure out the 4 questions to this problem.
I'm taking physics and trying to figure out the 4 - 1

Answers

Answer 1
Answer:

Answer:

Explanation:

At t = 1 velocity = 0

At t = 3 velocity = 3

slope of the line = 3-0 / 3-1 = 3/2

At t = 2

velocity = 3/2 x ( 2 - 1 )

= 1.5 m /s

velocity at t = 2 is 1.5 m /s

Position at t = 2 :

displacement at t = 2

area of graph upto  t = 2

= 1 / 2 x 1 x 1.5 = .75

position at t = 2 :

= initial position + displacement

= 10 + .75 = 10.75 m

position at 6 s :

displacement at t = 6

area of curve upto  t = 6

= 1 / 2 x 2 x 3 +  3 x 3 + 1/2 x 3 x ( 4.5 - 3 )

= 3 + 9 + 2.25

= 14.25 m

position at t = 6

= initial position + displacement

= 10 + 14.25 = 24.25 m

position at 9 s :

displacement at t = 9

area of curve upto  t = 9

= 1 / 2 x 2 x 3 +  4 x 3 + 1/2 x 4 x ( 5 - 3 )- 1/2 x 2 x 1.5

= 3 + 12 + 4 - 1.5

= 17.5  m

position at t = 9

= initial position + displacement

= 10 + 17.5 = 27.5  m


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In a parallel circuit with 3 resistors, the output voltage at the power supply is recorded to be 5 A.   The current flowing through the first resistor is 1 A and the current flowing through the second resistor is .5 A. What is the current flowing through the third resistor?

Answers

In a parallel circuit, the total power supply current is the sum of the
currents through all of the individual branches.

The output current (not the voltage) of the power supply is 5 A.
So the individual currents in the circuit branches is 5 A.

The current through the first 2 resistors is (1 + 0.5) = 1.5 A.

So the current through the 3rd resistor is (5 - 1.5) = 3.5 A.

A place kicker must kick a football from a point 36.0 m from the uprights. As a result of the kick, the ball must clear the crossbar, which is 3.05 m high. When kicked, the ball leaves the ground with an initial speed of 20 m/s at an angle of 53° to the horizontal. By how much does the ball clear or fall short of clearing the crossbar?

Answers

Final answer:

By utilizing principles of projectile motion, it is found that the football clears the crossbar by approximately 10.75 meters.

Explanation:

To determine by how much the ball clears or falls short of clearing the crossbar, we need to use the physics principles of projectile motion. The maximum height 'h' of the football can be given by equation of motion: h = (v²sin²θ) / (2g), where 'v' is the initial velocity, 'g' is the acceleration due to gravity and 'θ' is the angle of projection.

Substituting the given values: h = [(20)²sin²53°] / (2*9.8) ≈ 13.8 m above the ground when it was kicked. However, the football was kicked from ground level, so we need to subtract the height of the crossbar from this value, which is 3.05 m. Thus, the ball clears the crossbar by approximately: 13.8 - 3.05 = 10.75 m.

Learn more about Projectile Motion here:

brainly.com/question/20627626

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How many 176 ohm resistors are connected in series to get a current of 5 a on 220 v battey

Answers

Total resistance = voltage / current = 220 / 5 = 44 ohms .

Even one 176-ohm resistor is too much.  The current through it is 1.25 A,
and more than one of them in series reduces the current even further.

Connecting them in parallel, however . . .

Four resistors of 176-ohms each, in parallel, have a net effective resistance
of 176/4 = 44 ohms ... exactly what you need to do the job.

A wave oscillates 50 times per second. What is its frequency?

Answers

Answer: The frequency of the wave is 0.02 Hertz.

Explanation:

Frequency is a parameters which describe a wave. This is defined as the number of oscillations happening per unit second.

Mathematically,

Frequency=\frac{1}{\text{Number of oscillations}}

In the question,

Number of oscillations happening per second = 50

Putting this value in above equation, we get:

Frequency=(1)/(50)\n\n\nu=0.02Hz

Hence, the frequency of the wave is 0.02 Hertz.

You just told us how many times per second the wave oscillates. That's a definition of frequency. So the frequency of this wave is 50 per second or 50 hertz.

A current carrying wire wrapped around an iron ore is called a

Answers

I'm pretty sure that you're talking about an "electromagnet",
and that you actually meant an iron core .

Two charged objects, A and B, exert an electric force on each other. What happens if the distance between them is increased?

Answers

The correct answer to the question will be that the electric force between them will be decreased.

EXPLANATION:

Let us consider the charge contained by A and B are denoted as Q and Q' respectively.

Let R is the separation distance between them.

As per Coulomb's law in electrostatics, the force of attraction or repulsion between the two charge bodies A and B  will be -

           Coulombic force F = (1)/(4\pi \epsilon) (QQ')/(R^2)

Here, \epsilon is the permittivity of the medium in which the charges are present.

From above, we see that electric force is inversely proportional to the square of separation distance between them.

Mathematically it can be written:  F\ \alpha\ (1)/(R^2)

As per the question, the distance between A and B is increased.

Hence, the electric force between A and B will be decreased.

I agree with Hussein but I would like to add that when the distance between two charged objects increase, the force decreases by the Coulomb` s Law:
F= k * Q1*Q2 / r^2
where k is constant Q1, Q2-quantity of electricity and r- distance between two charged objects. So when you increase r, you divide with greater number and result decreases.
F=k(q1 * q2)/( r^(2) )