Which number completes the series: 1, 3, 6, 10, 15, ???

Answers

Answer 1
Answer:

Answer:

21

best of luck!

Answer 2
Answer:

Answer:

21

Step-by-step explanation:

1 + 2 = 3

3 + 3 = 6

6 + 4 = 10

10 + 5 = 15

15 + 6 = 21

Hope it helps

Mark it as Brainliest!


Related Questions

Kayla is having a neighbor watch her dog while she is gone for the week she decides to take 7/8 of a pound of dog food and put it in 7 containers equally. How much dog food will be in each container 
Perform the following calculation: (+10) + (–45). A. 55 B. –55 C. –35 D. 35
Can you help me please
There are 250 students in the senior class at Stats High School. Some are involved in clubs and some have part-time jobs. 130 students have a part-time job (some of these students may be in a club). 110 students are involved in a club (some of these students may have a job). 100 students are NOT involved in a club and do NOT have a part-time job1. Draw a Venn diagram to illustrate the data.
A certain city's population is 120,000 and decreases 1.4% per year for 15 years.Is this exponential growth or decay? GrowthWhat is the rate of growth or decay?What was the initial amount? 120000What is the function?What is the population after 10 years? Round to the nearest whole number.

What is the sum of 52.38 divided by 16

Answers

52.38 divided by 16 is 3.27

What is r in the problem d=2r

Answers

Answer:

radius

Step-by-step explanation:

Answer:

I'm not sure what you mean by "make the subject."

I can only guess that you'd like to solve this equation for r, which might be what you're looking for.

By "solve this equation for r," what I mean is to rewrite it in the form "r = [some expression]."

This is also known as "isolating."  By performing operations on both sides of the equation the task is achieved.

Step-by-step explanation:

In your example we could begin by dividing both sides by 2, as demonstrated below.

d = 2r

d / 2 = (2r) / 2

d / 2 = r or reversing the equality

r = d / 2.

That didn't require many operations, but the idea is the same for more complicated equations.

Hope this helps.

Hey I need help with my coordinates ​

Answers

Ok send the picture so I can help you.

Answer:

what is the question? I can help

Step-by-step explanation:

over 6 days, Dan jogged 7.5 miles, 6 miles, 3 miles, 3 miles, 5.5 miles and 5 miles what is the mean distance that Dan jogged each day

Answers

To start add together all of the miles over 6 days. Added together it equals 30 miles.

Then take 30 miles divided by how many days.
30 divided by 6.
30 divided by 6=5
5 miles is the mean distance.

Dan will be 8X years next year. how old was Dan five years ago. give your answer in terms of X

Answers

If Dan is 8x years old next year then he must be 8x-1 years old this year
With the same logic, five years ago from this year, he must be 8x-1-5=8x-6

The answer should be 8x-6

On each trial of an experiment, a subject is presented with a constant soft noise, which is interrupted at some unpredictable time by a noticeably louder sound. The time it takes for the subject to react to this louder sound is recorded. The following list contains the reaction times (in milliseconds) for the trials of this experiment: 296, 311, 202, 217, 231, 171, 241, 164, 257, 269, 175, 273, 285, 226, 261 Find 25th and 80th percentiles for these reaction times.

Answers

Answer:

25th percentile = 202

80th percentile = 285

Step-by-step explanation:

Rearranging the values in increasing order

164

171

175

202

217

226

231

241

257

261

269

273

285

296

311

N = total number of variables = 15.

25th percentile = [(N + 1)/4]th variable = (15 + 1)/4 = 4th variable.

So, the 25th percentile = 4th variable = 202.

80th percentile = 0.8(N + 1) th variable = 0.8 × (15 + 1) = 12.8th variable = 13th variable = 285

Final answer:

To find the 25th and 80th percentiles for the reaction times, sort the list and determine the corresponding values.

Explanation:

To find the 25th and 80th percentiles for the reaction times in this experiment, we need to first sort the list in ascending order:

  1. 164
  2. 171
  3. 175
  4. 202
  5. 217
  6. 226
  7. 231
  8. 241
  9. 257
  10. 261
  11. 269
  12. 273
  13. 285
  14. 296
  15. 311

The 25th percentile is the value that separates the lowest 25% of the data. In this case, it is the 4th value in the sorted list, which is 202 milliseconds. The 80th percentile is the value that separates the lowest 80% of the data. In this case, it is the 12th value in the sorted list, which is 273 milliseconds.

Learn more about percentiles here:

brainly.com/question/34021797

#SPJ3

Other Questions
Consider a random sample of ten children selected from a population of infants receiving antacids that contain aluminum, in order to treat peptic or digestive disorders. The distribution of plasma aluminum levels is known to be approximately normal; however its mean u and standard deviation o are not known. The mean aluminum level for the sample of n = 10 infants is found to be X = 37.20 ug/l and the sample standard deviation is s = 7.13 ug/1. Furthermore, the mean plasma aluminum level for the population of infants not receiving antacids is known to be only 4.13 ug/1.(a) Formulate the null hypothesis and complementary alternative hypothesis, for a two-sided test of whether the mean plasma aluminum level of the population of infants receiving antacids is equal to the mean plasma aluminum level of the population of infants not receiving antacids.(b) Construct a 95% confidence interval for the true mean plasma aluminum level of the population of infants receiving antacids.(c) Calculate the p-value of this sample (as best as possible), at the a=.05 significance level.(d) Based on your answers in parts (b) and (c), is the null hypothesis rejected in favor of the alternative hypothesis, at the a = .05 significance level? Interpret your conclusion: What exactly has been demonstrated, based on the empirical evidence?(e) With the knowledge that significantly elevated plasma aluminum levels are toxic to human beings, reformulate the null hypothesis and complementary alternative hypothesis, for the appropriate one-sided test of the mean plasma aluminum levels. With the same sample data as above, how does the new p-value compare with that found in part (c), and what is the resulting conclusion and interpretation?