You are measuring the volume of a chemical beaker how would u take the measurment? a.lift the beaker to eye level
b.you look down at the liquid above
c.use a ruler to measure
d.you squat to be eye level to the beaker

Answers

Answer 1
Answer:

I think its d  because lifting it would make the chemical swish around and that will make it so you cant get the right measurement. hope this helps :)


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John and Suzie are trying to improve the speed of their race car by adjusting the angle of the rear spoiler. Which choice is the controlled variable(s)?the maximum speed and the angle of the rear spoiler


the type of tire and the type of fuel


only the maximum speed


only the angle of the rear spoiler

Answers

Answer:

the type of tire and the type of fuel

Explanation:

The type of function that describes the amplitude of damped oscillatory motion is _______. The type of function that describes the amplitude of damped oscillatory motion is _______. quadratic sinusoidal inverse exponential linear

Answers

Answer:

exponential

Explanation:

type of function that describes the amplitude of damped oscillatory motion is exponential because as we know that here function is

y = A × e^{(-bt)/(2m)}  × cos(ωt + ∅ )    ..................................... ( 1 )          

here function A × e^{(-bt)/(2m)}   is amplitude

as per equation ( 1 )it is exponential

so that we can say that amplitude of damped oscillatory motion is exponential

Suppose that the speedometer of a truck is set to read the linear speed of the truck, but uses a device that actually measures the angular speed of the tires. If larger-diameter tires are mounted on the truck, will the reading on the speedometer be correct? If not, will the reading be greater than or less than the true linear speed of the truck? Why?

Answers

The measurement will be significantly affected.

Recall that the relationship between linear velocity and angular velocity is subject to the formula

v = \omega r,

Where r indicates the radius and \omega the angular velocity.

As the radius increases, it is possible that the calibration is delayed and a higher linear velocity is indicated, that to the extent that the velocity is directly proportional to the radius of the tires.

A proton is at the origin and an electron is at the point x = 0.36 nm , y = 0.39 nm . Find the electric force on the proton.Express your answer using two significant figures. Enter your answers numerically separated by a comma.

Answers

Answer:

The electric force on the proton is 8.2x10^-10 N

Explanation:

We use the formula to calculate the distance between two points, as follows:

r = ((x2-x1)^2 + (y2-y1)^2)^1/2, where x1 and x2 are the x coordinate, y2, y1 are the y coordinate. replacing values:

r = ((0.36-0)^2 + (0.39-0)^2)^1/2 = 0.53 nm = 5.3x10^-10 m

We will use the following expression to calculate the electrostatic force:

F = (q1*q2)/(4*pi*eo*r^2)

Here we have:

q1 = q2 = 1.6x10^-19 C, 1/4*pi*eo = 9x10^9 Nm^2C^-2

Replacing values:

F = (1.6x10^-19*1.6x10^-9*9x10^9)/((5.3x10^-10)^2) = 8.2x10^-10 N

What is the frequency of an xray with a wavelength of 2x10-10m?a) 1.5x1018hz
b) 6.67x10-19hz
c) 3x108hz
d) 1.5hz

Show calculation

Answers

Answer:

1.5 x 10¹⁸hz

Explanation:

Given parameters:

Wavelength  = 2 x 10⁻¹⁰m

Unknown:

Frequency   = ?

Solution:

To find the frequency, use the expression below;

  V  = f x wavelength

V is the speed of light = 3 x 10⁸m/s

f is the frequency

Now;

 Insert the parameters

     3 x 10⁸  = 2 x 10⁻¹⁰ x frequency

   Wavelength = (3 x 10^(8) )/(2 x 10^(-10) )    = 1.5 x 10¹⁸hz

A 1300-turn coil of wire that is 2.10 cm in diameter is in a magnetic field that drops from 0.130 T to 0 T in 12.0 ms. The axis of the coil is parallel to the field.Question: What is the emf of the coil? (in V)

Answers

Answer:

4.875 V

Explanation:

N = 1300

diameter = 2.10 cm

radius = half of diameter = 1.05 cm

B1 = 0.130 T

B2 = 0 T

t = 12 ms

According to the law of electromagnetic induction,

e = - N(d\phi )/(dt)

Where, Ф be the magnetic flux linked with the coil

e = - NA (dB )/(dt)

e = -1300*3.14*{1.05* 1.05* 10^(-4)*(0-0.130)/(12*10^(-3))=

e = 4.875 V