regulates and integrates the operations of the computer. It selects and retrieves instructions from the main memory in proper sequence and interprets them
Answer:
public class Main
{
public static void main(String[] args) {
minMax(1, 2, 3);
minMax(100, 25, 33);
minMax(11, 222, 37);
}
public static void minMax(int n1, int n2, int n3){
int max, min;
if(n1 >= n2 && n1 >= n3){
max = n1;
}
else if(n2 >= n1 && n2 >= n3){
max = n2;
}
else{
max = n3;
}
if(n1 <= n2 && n1 <= n3){
min = n1;
}
else if(n2 <= n1 && n2 <= n3){
min = n2;
}
else{
min = n3;
}
System.out.println("The max is " + max + "\nThe min is " + min);
}
}
Explanation:
*The code is in Java.
Create a function named minMax() that takes three integers, n1, n2 and n3
Inside the function:
Declare the min and max
Check if n1 is greater than or equal to n2 and n3. If it is set it as max. If not, check if n2 is greater than or equal to n1 and n3. If it is set it as max. Otherwise, set n3 as max
Check if n1 is smaller than or equal to n2 and n3. If it is set it as min. If not, check if n2 is smaller than or equal to n1 and n3. If it is set it as min. Otherwise, set n3 as min
Print the max and min
Inside the main:
Call the minMax() with different combinations
Answer:
True
Explanation:
The arithmetic and logic unit (ALU) in a microprocessor is the digital electronic component which carries out arithmetic and logic operations on the provided operands. It is typically integrated as part of the microprocessor chip though standalone ICs are also available.
Some examples of the operations performed by ALU in common microprocessors include:
Answer:
Hi!
The answer coded in Javascript is:
function minimalNumbersOfBanknotes(input) {
var banknotes = [50, 20, 10, 5, 1];
var output = '';
//Each while writes on output variable the banknote and substract the same quantity on input variable.
//If the input is lesser than the value of while banknote, step into next while.
for (var i = 0; i < banknotes.length; i++) {
while(input >= banknotes[i]) {
output = output + ' ' + banknotes[i];
input = input - banknotes[i];
}
}
return output;
}
Answer: True
Explanation: File allocation table(FAT) is the part of the file system that helps the hard drives .It is used for the management of the files and data which gets stored in the hard drive by the operating system. It can also help in the extension or expansion of the hard drive storage.
It also keeps tracing the files and data accordingly. This table works for the portable devices ,cameras etc. Thus, the statement given is true.
Answer:
#include <iostream>
#include <string>
using namespace std;
int main() {
string inputMonth;
int inputDay;
cin >> inputMonth >> inputDay;
if (inputMonth == "January" && inputDay >= 1 && inputDay <= 31)
cout << "Winter" << endl;
else if (inputMonth == "February" && inputDay >= 1 && inputDay <= 29)
cout << "Winter" << endl;
else if (inputMonth == "April" && inputDay >= 1 && inputDay <= 30)
cout << "Spring" << endl;
else if (inputMonth == "May" && inputDay >= 1 && inputDay <= 30)
cout << "Spring" << endl;
else if (inputMonth == "July" && inputDay >= 1 && inputDay <= 31)
cout << "Summer" << endl;
else if (inputMonth == "August" && inputDay >= 1 && inputDay <= 31)
cout << "Summer" << endl;
else if (inputMonth == "October" && inputDay >= 1 && inputDay <= 31)
cout << "Autumn" << endl;
else if (inputMonth == "November" && inputDay >= 1 && inputDay <= 30)
cout << "Autumn" << endl;
else if (inputMonth == "March" && inputDay >= 20 && inputDay <= 31)
cout << "Spring" << endl;
else if (inputMonth == "June" && inputDay >= 1 && inputDay <= 20)
cout << "Spring" << endl;
else if (inputMonth == "June" && inputDay >= 21 && inputDay <= 30)
cout << "Summer" << endl;
else if (inputMonth == "September" && inputDay >= 1 && inputDay <= 21)
cout << "Summer" << endl;
else if (inputMonth == "September" && inputDay >= 22 && inputDay <= 30)
cout << "Autumn" << endl;
else if (inputMonth == "December" && inputDay >= 0 && inputDay <= 20)
cout << "Autumn" << endl;
else if (inputMonth == "December" && inputDay >= 21 && inputDay <= 30)
cout << "Winter" << endl;
else if (inputMonth == "March" && inputDay >= 1 && inputDay <= 19)
cout << "Winter" << endl;
else
cout << "Invalid" << endl;
return 0;
}
Answer:
FOR PYTHON!!
input_month = input()
input_day = int(input())
months= ('January', 'February','March', 'April' , 'May' , 'June' , 'July' , 'August' , 'September' , "October" , "November" , "December")
if not(input_month in months):
print("Invalid")
elif input_month == 'March':
if not(1<=input_day<=31):
print ("Invalid")
elif input_day<=19:
print("Winter")
else:
print ("Spring")
elif input_month == 'April' :
if not(1<=input_day<=30):
print("Invalid")
else:
print("Spring")
elif input_month == 'May':
if not(1<=input_day<=31):
print("Invalid")
else:
print("Spring")
elif input_month == 'June':
if not(1<=input_day<=30):
print("Invalid")
elif input_day<=20:
print ("Spring")
else:
print("Summer")
elif input_month == 'July':
if not(1<=input_day<=31):
print("Invalid")
else:
print("Summer")
elif input_month == 'August':
if not(1<=input_day<=31):
print("Invalid")
else:
print("Summer")
elif input_month == 'September':
if not(1<=input_day<31):
print("Invalid")
elif input_day<=21:
print ("Summer")
else:
print ("Autumn")
elif input_month == "October":
if not(1<=input_day<=31):
print("Invalid")
else:
print("Autumn")
elif input_month == "November":
if not(1<=input_day<=30):
print("Invalid")
else:
print ("Autumn")
elif input_month == "December":
if not(1<=input_day<=31):
print("Invalid")
elif input_day <=20:
print ("Autumn")
else:
print ("Winter")
elif input_month == 'January':
if not(1<=input_day<=31):
print("Invalid")
else:
print("Winter")
elif input_month == "February":
if not(1<=input_day<=29):
print("Invalid")
else:
print ("Winter")
Explanation:
Good luck in the rest of your class!
Answer:
When forced distribution is used to reduce leniency bias, this can cause (decreased trust between employees) if a pfp system is in place.
Explanation:
Please give me Brainlest!