CHEMISTRY HIGH SCHOOL

How many electrons does maganese 55 have?

Answers

Answer 1
Answer:

Answer:

Maganese 55 has 25 electrons.

Hope this helps you!

Explanation:

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Which is a unique feature of Jupiter? A.
the least dense planet in the solar system

B.
the largest, most massive planet

C.
rotates on an axis tilted entirely sideways

D.
the most distant planet from the sun

Answers

I would say the answer is A, because Jupiter is the least dense planet in the solar system. It is the largest planet in our solar system, but that is not what answer choice says. Jupiter does not rotate on an axis completely sideways, that is Uranus, and is not the most distant planet from the sun.

If 7.84 × 107 J of energy is released from a fusion reaction, what amount of mass in kilograms would be lost? Recall that c = 3 × 108 m/s.

Answers

the correct answer would be 8.71 × 10–10

What is the mass of 2.25 moles of manganese(lv) sulfide(MnS2)

Answers

Explanation:

Number of moles is defined as mass divided by molar mass of the substance or atom.

Mathematically,     No. of moles = (mass)/(molar mass)

It is known that molar mass of MnS_(2) is 119.058 g/mol and number of moles is given as 2.25 mol.

Therefore, calculate mass of MnS_(2) as follows.

                          No. of moles = (mass)/(molar mass)

                                   2.25 mol = (mass)/(119.058 g/mol)

                                 mass = 267.88 g

Thus, we can conclude that mass of 2.25 moles of manganese(lv) sulfide(MnS2) is 267.88 g.

                 

Final answer:

The mass of 2.25 moles of Manganese (V) Sulfide (MnS2) can be calculated by multiplying the molar mass of MnS2 (119.08 g/mol) by the number of moles (2.25). The result is approximately 267.93 grams.

Explanation:

The question asks about the mass of 2.25 moles of manganese (V) Sulfide (MnS2). We can calculate this using the molar mass of MnS2. The molar mass of manganese (Mn) is approximately 54.94 g/mol, and the molar mass of Sulfur (S) is approximately 32.07 g/mol. To find the molar mass of MnS2 we add up the molar mass of Mn and twice the molar mass of S (because we have 2 S atoms). Therefore the molar mass of MnS2 = 54.94 + 2*(32.07) = 119.08 g/mol. To find the mass in grams, we multiply this molar mass by the number of moles. Hence, the mass of 2.25 moles of MnS2 = 2.25 * 119.08 = 267.93 grams.

Learn more about Molar Mass here:

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A solute is a mixture in which particles can be seen and easily separated. Please select the best answer from the choices provided T F

Answers

F because solute is the one which is mixed to the other for a solution and after mixing I can never been seen neither separated !!

What is a spelling bee​

Answers

Answer: a contest in which you are eliminated if you fail to spell a word correctly.
a contest where you attempt to spell a series of words that you are given by the judges

Initially, a 55.0 liter compressible container, holding 2.4 moles of a gas, exerts a pressure of 760 millimeters of mercury at a temperature of 280 Kelvin. What is the pressure when the container is compressed to 43.0 liters, the moles of gas reduces to 1.8 moles, and the temperature changes to 36 degrees Celsius?93.7 mm Hg
492 mm Hg
740 mm Hg
805 mm Hg

Answers

Answer:

805 mmHg is the pressure when the container is compressed

Explanation:

Initial Volume of the gas, V = 55.0 L

Initial Moles of the gas, n = 2.4 mol

Initial Pressure of the gas ,P=760 mmHg

initial temperature of the gas, T = 280 K

Using an Ideal gas equation:

PV=nRT

R=(PV)/(nT)...(1)

Final Volume of the gas, V '= 43.0 L

Final Moles of the gas, n' = 1.8 mol

Final Pressure of the gas = p'

Final temperature of the gas, T' =36 °C = 309 K

Using an Ideal gas equation:

R=(P'V')/(n'T')..(2)

(1)=(2)

(PV)/(nT)=(P'V')/(n'T')

(760 mmHg* 55.0 L)/(2.4 mol* 280 K)=(P'* 43.0 L)/(1.8 mol* 309 K)

P' = 805 mmHg

805 mmHg is the pressure when the container is compressed.
You would have to use the ideal gas law for this:
PV=nRT
Pressure, Volume, n=moles, R gas constant, Temperature in Kelvin
P=nRT/V
(1.8mol)(62.36)(309K)/43.0L = 805mm Hg 
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