Which one A, B, C, D or the last one?

Answers

Answer 1

Answer:

Answer:

Explanation:

Answer is C.

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At a stop light, a truck traveling at 10.5 m/s passes a car as it starts from rest. The truck travels at constant velocity and the car accelerates at 3 m/s2. How much time does the car take to catch up to the truck?
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A poorly constructed room is suffering from a pipe leakage problem. The leaked pipes are continuously flooding the 90-m2 room such that the water level in the room increases at a steady rate of 1.2 cm/hr (a) How much water in L/min should be pumped out of the room to keep the water level cnstat (b) How much water in L/min should be pumped out of the room to reduce the water level by 4 cm/hr?

Answers

Answer:

(a): should be pumped out of the room 18 L/min to keep the water level constant.

(b): should be pumped out of the room 78 L/min to reduce the water level by 4 cm/hr.

Explanation:

S= 90 m²

rate= 1.2 cm/hr = 0.012 m/hr = 0.0002 m/min

Water leak= S*rate= 90 m² * 0.0002 m/min

Water leak= 0.018 m³/min * 1000 L/m³

Water leak= 18 L/min (a) Water should be pumped out to keep the level constant.

By the rule of 3:

1.2 cm/hr ------------- 18 L/min

(4+1.2) cm/hr -------- x= 78 L/min (b) Water should be pumped out to reduce the level by 4 cm/hr.

An aluminum rod 17.400 cm long at 20°C is heated to 100°C. What is its new length? Aluminum has a linear expansion coefficient of 25 × 10-6 C-1.

Answers

The new length of aluminum rod is 17.435 cm.

The linear expansion coefficient is given as,

$\alpha=(L_(1)-L_(0))/(L_(0)(T_(1)-T_(0)))$

Given that, An aluminum rod 17.400 cm long at 20°C is heated to 100°C.

and linear expansion coefficient is $25*10^(-6)C^(-1)$

Substitute, $L_(0)=17.400cm,T_(1)=100,T_(0)=20,\alpha=25*10^(-6)C^(-1)$

$25*10^(-6)C^(-1) =(L_(1)-17.400)/(17.400(100-20))\n\n25*10^(-6)C^(-1) = (L_(1)-17.400)/(1392) \n\nL_(1)=[25*10^(-6)C^(-1) *1392}]+17.400\n\nL_(1)=17.435cm$

Hence, The new length of aluminum rod is 17.435 cm.

Learn more:

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Answer:

the new length is 17.435cm

Explanation:

the new length is 17.435cm

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A sinusoidal wave is travelling on a string under tension T = 8.0(N), having a mass per unit length of 1 = 0.0128(kg/m). It’s displacement function is D(x,t) = Acos(kx - t). It’s amplitude is 0.001m and its wavelength is 0.8m. It reaches the end of this string, and continues on to a string with 2 = 0.0512(kg/m) and the same tension as the first string. Give the values of A, k, and , for the original wave, as well as k and  the reflected wave and the transmitted wave.

Answers

Answer:

Explanation:

A 2,000 kg car travels with a tangentialvelocity of 12 m/s around a circular
track with a radius of 30 meters. What
is the car's rate of centripetal
acceleration?

Answers

The car's rate of centripetal acceleration in the circular path is 4.8 m/s².

The given parameters;

mass of the car, m = 2,000 kg
velocity of the car, v = 12 m/s
radius of the circular path, r = 30 m

The centripetal acceleration of the car is calculated as follows;

$a_c = (v^2)/(r)$

where;

v is the tangential speed of the car
r is the radius of the circular path

Substitute the given parameters and solve for the centripetal acceleration;

$a_c = (12^2)/(30) \n\na_c = 4.8 \ m/s^2$

Thus, the car's rate of centripetal acceleration is 4.8 m/s².

Learn more here:brainly.com/question/11700262

a= v²/R
a = 12²/30 =4.8 m/s²

How to Measure the mass of a coin using a triple beam balance

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Answer:

https://youtu.be/stW-C7F7QOg

A standing wave of the third overtone is induced in a stopped pipe, 2.5 m long. The speed of sound is The frequency of the sound produced by the pipe, in SI units, is closest to: