PHYSICS COLLEGE

A local meteorologist reports the day’s weather. "Currently sunny outside, 34°F. Skies will become overcast later this afternoon, as temperatures drop to 25°F, with windy conditions out of the north at 10–15 miles per hour. Radar indicates 2–3 inches of snow expected to fall later tonight.” Which information is qualitative? These are non-numerical, descriptive data. These are numerical data that have been measured. “sunny” “25°F” “2–3 inches of snow” “10–15 miles per hour”

Answers

Answer 1

Answer:

Answer:

sunny

Explanation:

took the test

Answer 2

Answer:

Answer:

A.) Sunny

Explanation:

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A car (m = 2000 kg) is going around an unbanked curve at the recommended speed of 11m/s (24.6 MPH). (a) If the radius of the curvature of the path is 25m and the coefficient of static friction between the rubber tires and the road is µs = 0.70, does the car skid as it goes around the curve? (b) What will happen if the driver ignores the highway speed limit sign and travels at 18 m/s (40.3 MPH)? (c) What speed is safe for traveling around the curve if the road surface is wet from a recent rainstorm and the coefficient of static friction between the wet roud and the rubber tires is µs = 0.50?
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A typical sugar cube has an edge length of 1 cm. If you had a cubical box that contained a mole of sugar cubes, what would its edge length be? (One mole = 6.02 ✕ 1023 units.)

Answers

Since volume of each cube is 1 cm^3
Then we can get the volume of 1 mole of cubes, which is $1 * 6.02 * 10^23 cm^3$
The edge $edge = v^1/3$
And the new adge that we are looking for: $new edge = (6.02*10^23)^1/3$ = $= 1.8191 * 46415888.336 = 84435142.472$
So, the final soution for the edge length of cube is 844km.

Do hope it helps!
Regards.

When a 20.0-ohm resistor is connected across the terminals of a 12.0-V battery, the voltage across the terminals of the battery falls by 0.300 V. What is the internal resistance of this battery

Answers

The internal resistance of the battery is 0.5 ohms.

To calculate the internal resistance of the battery, we use the formula below

Formula:

(V/R)r = V'............. Equation 1

Where:

V = Voltage across the terminal of the battery
R = Resistance connected across the battery
r = internal resistance of the battery
V' = voltage drop of the battery.

Make r the subject of the equation

r = V'R/V............ Equation 2

From the question,

Given:

V = 12 V
R = 20 ohms
V' = 0.3 V

Substitute these values into equation 2

r = (0.3×20)/12
r = 6/12
r = 0.5 ohms.

Hence, The internal resistance of the battery is 0.5 ohms.

Learn more about internal resistance here: brainly.com/question/14883923

Answer:

The internal resistance is $r = 0.5 \ \Omega$

Explanation:

From the question we are told that the resistance of

The resistance of the resistor is $R = 20.0\ \Omega$

The voltage is $V = 12.0 \ V$

The magnitude of the voltage fall is $e = 0.300\ V$

Generally the current flowing through the terminal due to the voltage of the battery is mathematically represented as

$I = (V)/(R)$

substituting values

$I = (12.0 )/(20 )$

$I = 0.6 \ A$

The internal resistance of the battery is mathematically represented as

$r = (e)/(I)$

substituting values

$r = (0.300)/( 0.6 )$

$r = 0.5 \ \Omega$

Match each planet to an accurate characteristic

Answers

Answer:

venus - 2

earth - 3

mars - 4

mercury - 1

At an intersection of hospital hallways, a convex spherical mirror is mounted high on a wall to help people avoid collisions. The magnitude of the mirror's radius of curvature is 0.560 m.A) Locate the image of a patient10.6m from the mirror. B) Indicate whether the image is upright or inverted.C) Determine the magnification of the image.

Answers

Answer:

Explanation:

For a convex mirror, the value of its image distance and its focal length are negative.

using the mirror formula 1/f = 1/u+1/v

f is the focal length = Radius of curvature/2 = 0.560/2

f= 0.28m

u is the object distance = 10.6m

v is the position of the image = ?

On substitution;

1/0.28 = 1/10.6 + 1/-v

3.57 = 0.094 - 1/v

3.57 - 0.094 = -1/v

3.476 = -1/v

v = -1/3.476

v = -0.2877m

B) Since the image distance is negative, this means that the image is an upright and a virtual image. All Upright images has their image distance to be negative.

C) Magnification = Image distance/object distance

Magnification = 0.2877/10.6

Magnification = 0.0271

What is the speed of an electron with a de Broglie wavelength of 0.20 nm?

Answers

Answer:

$v = 3.65 * 10^6 m/s$

Explanation:

Given

de Broglie wavelength = 0.20nm

Required

Determine the speed (v)

The speed is calculated using the following formula;

$L = (h)/(mv)$

Where

$L = Wavelength = 0.2nm$

$h = Planck's\ constant = 6.63 * 10^(-34)Js$

$m = Mass\ of\ Electron = 9.11 * 10^(-31) kg$

Substitute these values in the above formula

$0.2nm = (6.63 * 10^(-34))/(9.11 * 10^(-31) * v)$

-----------------------------------------------------

Convert 0.2nm to metre (m)

$0.2nm = 0.2 * 10^(-9)m$

-----------------------------------------------------

$0.2 * 10^(-9) = (6.63 * 10^(-34))/(9.11 * 10^(-31) * v)$

Multiply both sides by v

$v * 0.2 * 10^(-9) = (6.63 * 10^(-34))/(9.11 * 10^(-31) * v) * v$

$v * 0.2 * 10^(-9) = (6.63 * 10^(-34))/(9.11 * 10^(-31) )$

$v * 0.2 * 10^(-9) = (0.73 * 10^(-34))/(10^(-31) )$

$v * 0.2 * 10^(-9) = 0.73 * 10^(-34) * 10^(31)$

Apply law of indices

$v * 0.2 * 10^(-9) = 0.73 * 10^(-34 + 31)$

$v * 0.2 * 10^(-9) = 0.73 * 10^(-3)$

Divide both sides by $0.2 * 10^(-9)m$

$v = (0.73 * 10^(-3) )/( 0.2 * 10^(-9) )$

$v = (3.65 * 10^(-3) )/(10^(-9) )$

Apply law of indices

$v = 3.65 * 10^(-3) * 10^9$

$v = 3.65 * 10^(-3+9)$

$v = 3.65 * 10^6$

Hence;

The velocity is

$v = 3.65 * 10^6 m/s$

Which of the following wouldhave low electromagnetic
energy?
A. X-rays
B. ultraviolet waves
C. radio waves

Answers

Final answer:

Radio waves have low electromagnetic energy compared to X-rays and ultraviolet waves.

Explanation:

Electromagnetic energy refers to the energy associated with electromagnetic waves, which are a form of energy that can travel through empty space. The energy of an electromagnetic wave is directly proportional to its frequency. Therefore, the frequency determines the energy level of the wave.

In the given options, radio waves would have the lowest electromagnetic energy. Radio waves have the longest wavelength and lowest frequency among the three options. X-rays, on the other hand, have a higher frequency and shorter wavelength, making them more energetic. Ultraviolet waves have an even higher frequency and shorter wavelength, making them the most energetic among the three options.

Learn more about Electromagnetic energy here:

brainly.com/question/22963020

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