Nicholas spends 20 minutes ironing shirts with his 1,800-watt iron. How many joules of energy were usedby the iron?
Answers
The amount of joules of energy used by the iron is 2.16 × J.
How to calculate energy?
Energy refers to the capacity to do work. The formula for electrical energy is as follows:
Energy = Power x Time
Where:
- Power is typically given in Watts (like a light bulb)
- Time is usually given in seconds
- Energy is usually measured in joules.
According to this question, Nicholas spends 20 minutes ironing shirts with his 1,800-watt iron. The energy used by the iron can be calculated as follows:
Energy = 1800watts × 1200s = 2.16 × J
Learn more about energy at: brainly.com/question/1932868
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A crate with a mass of 3.00 kg starts from rest at the top of a 27.0∘ incline and slides 2.00 m down the incline in 1.60 s. (a) What is the magnitude of the acceleration of the crate (in m/s² )? (b) What is the frictional force (in N) acting on the crate? (Enter the magnitude.) (c) What is the coefficient of kinetic friction between the crate and the incline? (d) What is the speed of the crate (in m/s ) after it has slid 2.00 m ?
Answers
Answer:
The distance travelled is 2.34*10^8 m.
Explanation:
The acceleration of the spacecraft is,
a=F/m
=391/7870 = 0.04968 m/s^2
The distance travelled,
d=v^2-v0^2/2a
=(4820)^2-(38)^2 / 2(0.04968)
=2.34*10^8 m.
b. twice the voltage and the same current will flow through each.
c. the same voltage and different current will flow through each.
d. twice the voltage and different currents will flwo through each.
Answers
Answer: option B
Explanation: each cell is suppose to have an emf and an internal resistance.
Let E1 be the emf of the first battery and E2 be the emf of the second battery.
Et is the total emf.
Going by the connection described above, it is a series arrangement.
Hence the total emf is calculated as sum of individual emf
Et = E1 + E2
But each cell are identical, hence E1 = E2 = E
Et = E + E = 2E.
Hence the total voltage is twice the voltage.
Since the connection is a series arrangement, the current passing through each cell is the same.
These points have made option B the correct answer.
Answer:
b) Twice the voltage and the same current
Explanation:
The two batteries are identical, and are connected in series. When elements in a circuit are connected in series, the same current flow through them but the voltage drops are additive.
Since the two batteries are identical, the possess the same voltage of magnitude V.
Therefore, the total voltage,
Answers
Answer:
Explanation:
Given
where h=Planck constant
c=speed of light
Answer:
1.82 × 10⁻¹⁹ J
Explanation:
The Bohr model of the atom states that the energy required to transition between two energy levels is equal to the difference between the inverse squares of the energy levels multiplied by the Rydberg constant:
Answers
Answer:
17.23L
Explanation:
The table lists pressure and volume values for a particular gas. Which is the best estimate for the value of V at P = 7.0 × 103 pascals?
P (pascals) V (liters) 1/v
1. 5.0 × 10^3 6.0 0.16
2. 1.5 × 10^4 3.0 0.33
3. 2.0 × 10^4 2.0 0.5
4. 2.5 × 10^4 1.5 0.66
if we are to plot the above data in a linear graph, the equation of a line graph below can be used
y-y1=m(x-x1)
y-y1=(x-x1)..............1
from the ideal gas law
pressure is inversely proportional to volume as nRT is the constant of proportionality
PV=nRT
P=nRT/V
from equation 1
let y1= 1.5 × 10^4
y2= 2.0 × 10^4
x1=0.33
x2= 0.5
y-1.5x10^4=2.0 × 10^4-1.5 × 10^4 /(0.5-.33)(x-0.33)
y-1.5x10^4=29411(x-0.33)
y=15000-9705.88+29411x
y=5294+29411x
at 7*10^3
7*10^3=5294+29411x
x=0.058
recall that x=1/V
inverse of both sides gives volume to be
V=17.23L
I think the question need to use extrapolation. FInd the linear function of the first and second data. And then, the anwser is 5.4 liters.
Answers
The one remained is C. fermi( femtometer) which is obviously correct answer.
Answers
2 (pi) (R²)
= (2 pi) (633 x 10⁻⁹ m)²
= (2 pi) (4.01 x 10⁻¹³) m²
= 2.52 x 10⁻¹² m²
Average power = (5 x 10⁻³ W) / (2.52 x 10⁻¹² m²)
= 1.984 GW / m² .
b).
c).
d). I don't remember how to do these parts of the question.
However, I do sincerely believe that the solution of part-'a' was
a fair return for the penurious and parsimonious award of 5-points.