How many significant digits are in 89015?

Answers

Answer 1

Answer:

Answer:5

Explanation:

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If atoms contain charged particles, why do they not have a charge?
The destruction of the ozone layer by chlorofluorocarbons (CFC’s) can be described by the following reactions:ClO(g) + O3(g) ? Cl(g) + 2 O2(g) ?H°rxn = –29.90 kJ2 O3(g) ? 3 O2(g) ?H°rxn = 24.18 kJDetermine the value of heat of reaction for the following:Cl(g) + O3(g) ? ClO(g) + O2(g) ?H°=_____________?
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Which of the following forces causes comets to regularly return to the inner solar system after being gone for many years?A. friction
B. magnetism
C. electromagnetic force
D. gravity

Answers

Answer is D. Gravity

Answer:

✨Gravity✨ hope this helps

Explanation:

Question 4What is the sum of these two reactions? Write your answer below, but don't worry about formatting with subscripts-Do write chemical formulas with
proper atomic symbols, though (e.g., write CuCl2, not CUCL2).
(1) Ca + 2HCl - CaCl2 + H2
(2) CaCl2+H2O = CaO + 2HCl

Answers

Answer:

$Ca +H_2O \rightarrow + H_2 + CaO$

Explanation:

Hello,

In this case, considering the given two reactions, when we add them, we obtain:

$Ca + 2HCl +CaCl_2 +H_2O \rightarrow CaCl_2 + H_2 + CaO+2HCl$

Thus, we can simplify both hydrochloric acid and calcium chloride as they are both sides to obtain:

$Ca +H_2O \rightarrow H_2 + CaO$

Best regards.

The value of delta for the [C_rF_6]^3- complex is 182 kJ/mol. Calculate the expected wavelength of the absorption corresponding to promotion of an electron from the lower-energy to the higher-energy of orbital set in this complex. (Remember to divide by Avogadro's number.) Should the complex absorb in the visible range?

Answers

Answer: Yes the absorb in the visible range.

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

$E=(Nhc)/(\lambda)$

where,

$E$ = energy of the wave = 182 kJ/mol = 182000 J/mol

N = avogadro's number = $6.023* 10^(23)$

h = plank constant = $6.6* 10^(-34)Js^(-1)$

c = speed of light = $3* 10^8m/s$

$\lambda$ = wavelength of the wave = ?

Putting all the values:

$182000=(6.023* 10^(23)* 6.6* 10^(-34)* 3* 10^8m/s)/(\lambda)$

$\lambda=0.65* 10^(-6)m=650nm$ $(1nm=10^(-9)m)$

The wavelength range for visible rays is 400 nm to 750 nm, thus the complex absorb in the visible range.

Final answer:

The expected wavelength of the absorption in the [CrF6]3- complex cannot be calculated without knowing the exact value of ΔE. Therefore, it is unclear if the complex will absorb in the visible range.

Explanation:

In this complex, the value of delta (Δ) is 182 kJ/mol. To calculate the expected wavelength of the absorption corresponding to the promotion of an electron from the lower-energy orbital to the higher-energy orbital, we can use the equation: Wavelength = (hc)/(ΔE), where h is Planck's constant and c is the speed of light. By substituting the given values and dividing by Avogadro's number, we can calculate the expected wavelength.

However, the information given in the question does not provide the exact value for ΔE. Without this information, it is not possible to calculate the expected wavelength accurately. Therefore, we cannot determine if the complex will absorb in the visible range.

Learn more about Calculating expected wavelength of absorption in a complex here:

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How many Cal2 formula units are present
in 5.164 g of Call2?

Answers

Answer:

1.06x10²² formula units

Explanation:

First we convert 5.164 g of CaI₂ into moles, using its molar mass:

5.164 g ÷ 293.887 g/mol = 0.0176 mol

Then we convert 0.0176 moles into formula units, using Avogadro's number, which relates the number of formula units present in 1 mol:

0.0176 mol * 6.023x10²³ FormulaUnits/mol = 1.06x10²² formula units

Consider the following reaction at 298K.I2 (s) + Pb (s) = 2 I- (aq) + Pb2+ (aq)
Which of the following statements are correct?
Choose all that apply.
ΔGo > 0
The reaction is product-favored.
K < 1
Eocell > 0
n = 2 mol electrons
B-