A student wants to make an electromagnet. Which items are needed?magnet copper wire
copper wire, metal nail, battery
magnet, copper wire, metal nail
battery, heat source, copper wire

Answers

Answer 1
Answer:

Answer:

copper wire, metal nail, battery

Explanation:

To create an electromagnet, the material to be magnetized (such as a metal nail) is placed inside a solenoid, the ends of the coils are connected to a circuit that includes a battery.

Current is allowed to flow for a few seconds and then cut off. The polarity of the magnet depends on the direction of flow of current in the solenoid.


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In ____________, electrons are gained by atoms and lost by others

Answers

the answer is ionic bonds

in ions atoms lose and gain electrons

Before arc welding was developed, a displacement reaction involving aluminum and iron(III) oxide was commonly used to produce molten iron (the thermite process). This reaction was used, for example, to connect sections of iron railroad track. Calculate the mass of molten iron produced when 2.28 kg of aluminum reacts with 17.2 mol of iron(III) oxide.

Answers

Answer: The mass of molten iron formed will be 1.92 kg

Explanation:

We are given:

Moles of iron (III) oxide = 17.2 moles

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     ......(1)

Given mass of aluminium = 2.28 kg = 2280 g     (Conversion factor:  1 kg = 1000 g)

Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium}=(2280g)/(27g/mol)=84.44mol

The chemical equation for the reaction of aluminium and iron (III) oxide follows:

2Al+Fe_2O_3\rightarrow Al_2O_3+2Fe

By Stoichiometry of the reaction:

1 mole of iron (III) oxide reacts with 2 moles of aluminium

So, 17.2 moles of iron (III) oxide will react with = (2)/(1)* 17.2=34.4mol of aluminium

As, given amount of aluminium is more than the required amount. So, it is considered as an excess reagent.

Thus, iron (III) oxide is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of iron (III) oxide produces 2 moles of iron

So, 17.2 moles of iron (III) oxide will produce =  (2)/(1)* 17.2=34.4mol of iron

Now, calculating the mass of iron by using equation 1, we get:

Molar mass of iron = 55.8 g/mol

Moles of iron = 34.4 moles

Putting values in equation 1, we get:

34.4mol=\frac{\text{Mass of iron}}{55.8g/mol}\n\n\text{Mass of iron}=(34.4mol* 55.8g/mol)=1919.5g=1.92kg

Hence, the mass of molten iron formed will be 1.92 kg

Nonmetals make up the largest grouping of elements on the periodic table. answer True or False

Answers

false, nonmetals do not make up the largest grouping of elements on the periodic table
The answer is false metals make up the largest group

A measurement of the amount of solute that is dissolved in a given quantity of solvent; usually expressed as mol/L.

Answers

Answer:Concentration is a measurement of the amount of solute that is dissolved in a given quantity of solvent; usually expressed as mol/L.

Explanation:

In 1909, Ernest Rutherford shot tiny particles at a sheet of gold foil. He expected all of the particles to move straight through the gold's atoms. Instead, some of the particles moved through, but other particles bounced back. What conclusion did Rutherford draw from these results?A. An atom is a soft blob of material composed of a mixture of protons and electrons.

B. An atom is entirely solid and has no empty spaces between its particles.

C. An atom has a dense nucleus surrounded by mostly empty space where electrons travel.

Answers

Option C: an atom has a dense nucleus sorrounded by mostly empty space where electrons travel.

Someone please help with these chemistry questions

Answers

Answer:

Option B. Add 1.46 g of NaCl to 250 mL of H₂O

Explanation:

Analyse the data given: 250 mL and 0.10 M

The molar concentration and the volume of solution can indicate the moles of solute that were used.

Let's convert the volume from mL to L → 250 mL . 1 L /1000mL =0.250L

M . volume = moles → 0.10 mol/L . 0.250L = 0.025 moles

If we convert the moles to mass, we'll know the mass of solute:

0.025 mol . 58.4 g/mol = 1.46 g

Answer:

We have to solve 1.46 grams of NaCl in 250 mL H2O (option B)

Explanation:

Step 1: Data given

Volume = 250 mL = 0.250 L

Molarity NaCl solution = 0.10 M

Molar mass of NaCl = 58.4 g/mol

Step 2: Calculate moles NaCl

Moles NaCl = molarity * volume

Moles NaCl = 0.10 M * 0.250 L

Moles NaCl = 0.025 moles

Step 3: Calculate mass NaCl

Mass NaCl = moles NaCl * molar mass NaCl

Mass NaCl = 0.025 moles * 58.4 g/mol

Mass NaCl = 1.46 grams

We have to solve 1.46 grams of NaCl in 250 mL H2O (option B)