Can two vectors of an unequal magnitude add up to give a vector with a magnitude of zero?

Answers

Answer 1

Answer: Two vectors of unequal magnitude can never sum to zero. If they point along the same line, since their magnitudes are different, the sum will not be zero.

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Q2. Zara travelled in a train moving at an average speed of 120km/h and covered a distance of 40km towards East. Calculate the time taken by the train to cover this distance.

Answers

Answer: 20 minutes

Explanation:

Given the following :

Average speed of train = 120km/hr

Distance = 40km.

The time take by the train moving at an average speed of 120km/hr to cover a distance of 40km due is ;

Recall:

Speed = distance / time

Therefore,

Time taken = distance covered / speed

Time taken = 40km / 120km/hr

Time taken = 1/ 3 hr

Therefore, 1/3 rd of an hour equals

1/3 × 60 = 20 minutes.

Time taken) 20 minutes

Time taken by tain to cover distance is 20 minutes as:

Distance= 40 km

Speed= 120 km/h

Time= distance/speed

= 40/120

= 1/3 hour

= 20 min

or =0.33 hrs

To know more about' Time and Speed 'visit:

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Which of these locations on earth experiences at least change in the number of daylight hours throughout the year?a) North pole
b) terrestrial equator
c) tropic of Capricorn
d) tropic of Cancer
e) South pole

Answers

The equator does. There, the noontime sun is never more than 23.5 degrees
from directly overhead, and the rising/setting sun is never more than 23.5 degrees
from due east/west.

So this is the place where the path of the sun across the sky changes the
least during the year, and therefore the place where the lengths of day and
night change the least during the year.

B the equator for it is the middle of the earth hope this helps

A 2,100 kg car is lifted by a pulley. If the cable breaks at 4.50 m, what is the velocity of the car when it hits the ground

Answers

The problem involves the conversion of potential energy to kinetic energy as the object falls from rest. Energy is conserved, so the equation used is:

PEi + KEi = PEf + KEf

Since the object is falling from rest, the initial kinetic energy is zero. Also, since the object hits the ground at its final position, the final potential energy is zero. This leaves:

PEi = KEf
mgh = 1/2 mv^2

*cancel out mass on both sides of the equation

gh = 0.5v^2
v = sqrt(2gh) = sqrt(2*9.81*4.5) = 9.40 m/s --> final ans.

A ski jumper competing for an Olympic gold medal wants to jump a horizontal distance of 135 meters. Thetakeoff point of the ski jump is at a height of 25 meters. With what horizontal speed must he leave the jump?
a. What do you know?
b. What do you need to solve for?
c. What equation(s) will you use?
d. What is the solution to this problem?

Answers

A. We know that the height (h) = 25 m, and the distance (x) = 135 m.

B. We need to find the time flight first (t), then we can find easily the horizontal velocity ( $v_(x)$ . )

C. Because this is a projectile motions, so horizontal velocity is constant, but the vertical velocity is change because of the gravitational acceleration.
So we can use : $h = (1)/(2) g t^(2)$ ,

Note : Time that will be exist is a time from a land to the takeoff point, that can be called as the time flight.
Then we use, $x = v_(x) t$ , to find the horizontal velocity.

D. We know that :
$h = (1)/(2) g t^(2)$ , so by insert the numbers, and assune that the (g = 10 m/ $s^(2)$ ), we get that ( t = $√(5)$ . )
After that by using $x = v_(x) t$ , we can get that $v_(x) = 27 √(5)$

A cube of side 3.56 cm has a charge of 9.11 μ C placed at its center. Calculate the electric flux through one side of the cube

Answers

Answer:

$\phi_(surface) = 1.72 * 10^5 N/Cm^2$

Explanation:

As we know by the theory of flux that if charge "q" is enclosed in a closed surface then total flux through the surface is given as

$\phi = (q)/(\epsilon_0)$

so here total flux passing through the cube is given as

$\phi_(total) = (9.11\muC)/(8.85 * 10^(-12))$

now we will have

$\phi_(total) = 1.03* 10^6$

now as we know that charge is placed at the center of the cube

so the total flux is uniformly passing through all faces of the cube

so flux passing one side of the cube is given as

$\phi_(surface) = (1.03* 10^6)/(6)$

$\phi_(surface) = 1.72 * 10^5 N/Cm^2$

Flux=q/e0
e0=8.85*10^-12
!!! Cube has 6 sides, so flux through one side is equal to total flux/6
Ans=9.11*10^(-6)/((8.85*10(-12))*6)=(approximately)1.72*10^5Nm^2/C

A person walks 25 m west and then 45 m at the angle of 60 degrees north of east what is the magnitude of the total displacement?

Answers

To solve this question, we need to use the component method and split our displacements into their x and y vectors. We will assign north and east as the positive directions.

The first movement of 25m west is already split. x = -25m, y = 0m.

The second movement of 45m [E60N] needs to be split using trig.
x = 45cos60 = 22.5m
y = 45sin60 = 39.0m

Then, we add the two x and two y displacements to get the total displacement in each direction.

x = -25m + 22.5m = -2.5m
y = 0m + 39.0m

We can use Pythagorean theorem to find the total displacement.
d² = x² + y²
d = √(-2.5² + 39²)
d = 39.08m

And then we can use tan to find the angle.
inversetan(y/x) = angle
inversetan(39/2.5) = 86.3

Therefore, the total displacement is 39.08m [W86.3N]

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