CHEMISTRY HIGH SCHOOL

What event marks the beginning of Earth's current era?O A. The emergence of human life
O B. A mass extinction
O C. The disappearance of land bridges
O D. The end of the last ice age

Answers

Answer 1
Answer: B. We are in the cenzoic era so what previously had happen to cause the life we live today was a huge mass extinction.... hope this helps!!
Answer 2
Answer:

Answer:

A mass extinction

Explanation:

Related Questions

In pole beans, green pods (G) are a dominate trait, while yellow pods(g) are a recessive trait. A bean plant with a GG genotype is crossed with a second plant that has a gg genotype. If the cross produces 500 spring, approximately how many of the offspring will have green pods?
the balanced chemical equation for one neutralization reaction. In your equation, which reactant contributed the salt's positive ion? Which one contributes the salt's negative ion?
Which is a base unit used in the metric system? quarts liters pints degrees Fahrenheit
A copper penny has a mass of 6.2 grams and a volume of 0.70ml. What is the density of the penny
In which compound does chlorine have the highest oxidation number?(1) NaClO (3) NaClO3(2) NaClO2 (4) NaClO4

Consider the following for the reaction at 300 K:3 ClO– (aq)  ClO3– (aq) + 2 Cl– (aq)ExperimentInitial [ClO–] (M)Initial Rate of Formation of ClO3– (aq)(M/min)10.4521.048 × 10–420.9034.183 × 10–4(7) (4 pts) What is the order of the reaction with respect to ClO– (aq)?A) 0B) 1C) 2(8) (4 pts) For experiment #2, what is the initial rate of consumption of ClO–

Answers

Answer:

Second order

Δ[ClO⁻]/Δt = -  4.183 x 10⁻⁴ M/min

Explanation:

Given the data:

Experiment #         [ClO–] (M)   Initial Rate of Formation of ClO3– (M/min)

         1                      10.452                     1.048 x 10⁻⁴

         2                     20.903                    4.183 x 10⁻⁴

we need to determine the order of the reaction with respect to ClO⁻.

We know the rate law for this reaction will have the form:

Rate = k [ClO⁻]^n

where n is the order of the reaction. Thus, what we need to do is to study the dependence of the initial rate on n for the experiment.

If the reaction were zeroth order the rate would not change, so we can eliminate n= 0

If the reaction were first order, doubling the concentration of   [ClO–] , as it was done exactly in experiment # 2, the initial rate should have doubled, which is not the case.

If the reaction were second order n: 2, doubling the concentration of  [ClO–] , should quadruple the initial rate of formation of ClO3–, which is what it is observed experimentally. Therefore the reaction is second order respect to ClO–.

The initial rate of consumption of ClO⁻ is the same as the rate of formation of ClO₃⁻ since:

Δ = - Δ[ClO⁻]/Δt =  + Δ[ClO₃⁻]/Δt = + 1/2 [Cl⁻] /Δt

where t is the time.

from the coefficients of the balanced chemical equation.

- Δ[ClO⁻]/Δt =  + Δ[ClO₃⁻]/Δt  = + 1/2 [Cl⁻ ] = rate

Δ[ClO⁻]/Δt = -  4.183 x 10⁻⁴ M/min

Which is the safest method for diluting concentrated sulfuric acid with water?

Answers

The safest method for diluting concentrated sulfuric acid with water is to add acid to water. This way, when spill occurs, the acid is already diluted and less harmful than adding water to acid.

If the strength of the magnetic field at A is 64 units, the strength of the magnetic field at B is _____.16 units
32 units
128 units
256 units

Answers

i would have to go with 128

Answer:

The answer is 128

Explanation:

Consider three gases: Ar, SF6, and Cl2. If 50.0 grams of these gases are placed in each of three identical containers, which container will have the highest pressure? The volume and temperature of all three containers are the same.

Answers

The ideal gas law:
pV=nRT \Rightarrow p=(nRT)/(V)
p - pressure, n - number of moles, R - the gas constant, T - temperature, V - volume

The volume and temperature of all three containers are the same, so the pressure depends on the number of moles. The greater the number of moles, the higher the pressure.
The mass of gases is 50 g.

Ar \nM \approx 39.948 \ (g)/(mol) \nn=(50 \ g)/(39.948 \ (g)/(mol)) \approx 1.25 \ mol \n \nSF_6 \nM \approx 146.06 \ (g)/(mol) \nn=(50 \ g)/(146.06 \ (g)/(mol)) \approx 0.34 \ mol \n \nCl_2 \nM=70.9 \ (g)/(mol) \nn=(50 \ g)/(70.9 \ (g)/(mol)) \approx 0.71 \ mol

The greatest number of moles is in the container with Ar, so there is the highest pressure.

When oxygen bonds to itself to form breathable oxygen gas what kind of bond is involved?a. ionic
b. covalent
c. oxygenated
d. non-metallic

Answers

The correcr anwer is B. The chemical bond between two oxygen atoms is a covalent bond, specifically double covalent bond. The two atoms share two pairs of electrons in order to achieve the most stable structure. Other examples are CO2 and C2H4.

What is the KE of a 4kg mass, moving at 3m/sec?

Answers

Answer:

The kinetic energy of a 4 kg mass moving at 3 m/s is 18 joules.

Explanation:

The kinetic energy (KE) of an object is calculated using the following formula: (image inserted)

Where:

KE: is the kinetic energy

m: is the mass of the object

v: is the velocity of the object

In your case, the mass (m) is 4 kg, and the velocity (v) is 3 m/s. Plugging these values into the formula.

The unit of kinetic energy is the joule (J), which is equivalent to a kg m^2/s^2. So:

KE = 18 J
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