Answer:
The output is 20
Explanation:
This line divides the value of x by userVal
tmpVal = x / userVal;
i.e.
tmpVal = 100/5
tmpVal = 20
This line then prints the value of tmpVal
System.out.print(tmpVal);
i.e 20
Hence, The output is 20
The provided Java code checks if the variable userVal does not equal 0. As this is the case when userVal is 5, another variable tmpVal is assigned the value of another variable x (which is 100) divided by userVal. Hence, the output of the code would be 20.
In the given piece of code, the variable userVal is assigned a value of 5. The program also contains a variable x which is assigned a value of 100. An if statement checks whether userVal does not equal 0 - since 5 != 0, the condition is true. A new variable tmpVal is then declared and assigned the value of x divided by userVal, so tmpVal equals 100 / 5, which is 20. So, the output of this code when userVal is 5 would be 20.
#SPJ3
missing DLL files
installation issues
configuration issues
applications running slowly
kernel panic
power cords not being plugged in
The common problems experienced with software applications will be missing DLL files, installation issues, configuration issues, applications running slowly, and kernel panic. Then the correct options are B, C, D, E, and F.
Today's world depends heavily on technology. Technology now controls not just how businesses run but also how quickly many different sectors across the world are developing. The pace of technical development dictates the rate of development and company growth, leaving human progress and economic expansion at the whim of technology.
Some of the common problems are as follows:
The normal issues experienced with programming applications will be missing DLL documents, establishment issues, arrangement issues, applications running gradually, and part alarms. Then the right choices are B, C, D, E, and F.
More about the common problems with software applications link is given below.
#SPJ12
Answer:
All but the top and bottom on edge 2020
Explanation:
of the numbers 2 through 10.
Answer:
//Program in C++.
// header
#include <bits/stdc++.h>
using namespace std;
// function to multiply number with 2-10
void multiplicationTable(int num)
{
cout<<"Number when multiplied with 2-10:"<<endl;
for(int a=2;a<=10;a++)
{
// multiply number with 2-10
cout << num << " * " << a << " = " << num*a << endl;
}
}
// driver function
int main()
{
// variable
int num;
cout<<"Enter a number:";
// read number from user
cin>>num;
// call the function
multiplicationTable(num);
return 0;
}
Explanation:
Read a number from user and assign it to variable "num".Call the function multiplicationTable() with parameter "num".In this function, multiply number with each from 2 to 10 and print the value.
Output:
Enter a number:5
Number when multiplied with 2-10:
5 * 2 = 10
5 * 3 = 15
5 * 4 = 20
5 * 5 = 25
5 * 6 = 30
5 * 7 = 35
5 * 8 = 40
5 * 9 = 45
5 * 10 = 50
Answer:
True
Explanation:
SQL stands for structured query language , which is used to query Relational Database Management systems like SQLServer. This is not for writing applications like business layer where we use some programming languages.SQL is meant for data layer to perform CRUD operations against database.
CRUD operations :
Create
Read
Update
Delete
we can perform above operations on database by using SQL query language
Answer:
Remote Access Protocols
Explanation:
Considering the situation above, the most appropriate protocol to use is known as the Remote Access Protocol.
This is because Remote Access Protocol is a combination of techniques and sets of instructions that are used in managing the connection between a remote access server and a remote computer. For example, some of the Remote Access Protocols that can be used are Serial Line Internet Protocol, Point-to-Point Protocol, Point-to-Point Protocol over Ethernet, etc.
Hence, given that a trusted Remote Access Protocol allows people to access a steady, secure connection between desktop sharing and remote access for help desk activities.
Therefore, the Remote Access Protocol can be utilized in setting up a secure network connection at a remote site
• Enlist the odd numbers out of them
• Enlist the prime numbers out of odd number list and printtheir sum (add all the prime numbers)
Answer:Following is the c++ code for the problem:
#include <iostream>
using namespace std;
int main() {
int number;
cout<<"Enter the number"<<endl;
cin>>number;
int i=0,c=0,odd[500];
while(i<=number)//loop for printing the numbers form 0 to number.
{
cout<<i<<" ";
if(i%2!=0)// storing in the odd array if the number is odd.
{
odd[c++]=i;//storing odd numbers..
}
i++;
}
cout<<endl;
i=0;
cout<<"The odd numbers are "<<endl;
while(i<c)//loop to print the odd numbers.
{
cout<<odd[i]<<" ";
i++;
}
cout<<endl<<"The prime numbers are "<<endl;
i=0;
int sum=0;
while(i<c)//loop to print the prime numbers..
{
int div=2;
while(div<odd[i])
{
if(odd[i]%div==0)
break;
div++;
}
if(div==odd[i])
{
cout<<odd[i]<<" ";
sum+=odd[i];//updating the sum..
}
i++;
}
cout<<endl<<"The sum of odd prime numbers is "<<sum<<endl;//printing the sum..
return 0;
}
Output :
Enter the number
49
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49
The odd numbers are
1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49
The prime numbers are
3 5 7 11 13 17 19 23 29 31 37 41 43 47
The sum of odd prime numbers is 326.
Explanation:
First I have printed the values from 0 to n and i have taken an array to store odd numbers.After that i have printed the odd values.And after that i have printed prime numbers among the odd numbers and their sum.These all operations are done using while loop.